Explore topic-wise MCQs in Joint Entrance Exam - Main (JEE Main).

This section includes 8666 Mcqs, each offering curated multiple-choice questions to sharpen your Joint Entrance Exam - Main (JEE Main) knowledge and support exam preparation. Choose a topic below to get started.

5801.

The function defined by \[f(x)=\left\{ \begin{align}   & |x-3|\,;\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x\ge 1 \\  & \frac{1}{4}{{x}^{2}}-\frac{3}{2}x+\frac{13}{4};\,x

A.                    Continuous at \[x=1\]
B.            Continuous at \[x=3\]
C.            Differentiable at \[x=1\]
D.            All the above
Answer» E.
5802.

At the point \[x=1\], the given function \[f(x)=\left\{ \begin{align}   & {{x}^{3}}-1;\,\,1

A.            Continuous and differentiable
B.            Continuous and not differentiable
C.            Discontinuous and differentiable
D.            Discontinuous and not differentiable
Answer» C.            Discontinuous and differentiable
5803.

Let \[[x]\]denotes the greatest integer less than or equal to x. If \[f(x)=[x\sin \pi x]\], then \[f(x)\]is [IIT 1986]

A.            Continuous at \[x=0\]
B.            Continuous in \[(-1,0)\]
C.            Differentiable in (?1,1)
D.            All the above
Answer» E.
5804.

If \[y={{\sin }^{-1}}\left( \frac{19}{20}x \right)+{{\cos }^{-1}}\left( \frac{19}{20}x \right)\], then \[\frac{dy}{dx}=\]

A.            0
B.            1
C.            ? 1
D.            None of these
Answer» B.            1
5805.

If \[y=\log \log x\], then \[{{e}^{y}}\frac{dy}{dx}=\]                                    [MP PET 1994, 95]

A.            \[\frac{1}{x\log x}\]
B.            \[\frac{1}{x}\]
C.            \[\frac{1}{\log x}\]
D.            \[{{e}^{y}}\]
Answer» C.            \[\frac{1}{\log x}\]
5806.

\[\frac{d}{dx}[{{e}^{ax}}\cos (bx+c)]\]=                                                               [AISSE 1989]

A.            \[{{e}^{ax}}[a\cos (bx+c)-b\sin (bx+c)]\]
B.            \[{{e}^{ax}}[a\sin (bx+c)-b\cos (bx+c)]\]
C.            \[{{e}^{ax}}[\cos (bx+c)-\sin (bx+c)]\]
D.            None of these
Answer» B.            \[{{e}^{ax}}[a\sin (bx+c)-b\cos (bx+c)]\]
5807.

 \[\frac{d}{dx}[{{\tan }^{-1}}(\cot x)+{{\cot }^{-1}}(\tan x)]=\]

A.            0
B.            1
C.            ? 1
D.            ? 2
Answer» E.
5808.

At \[x=\sqrt{\frac{\pi }{2}},\frac{d}{dx}\cos (\sin {{x}^{2}})\]=

A.            ?1
B.            1
C.            0
D.            None of these
Answer» D.            None of these
5809.

If \[f(x)=\,|x|,\]then \[f'(0)=\]                                     [MNR 1982]

A.            0
B.            1
C.            x
D.            None of these
Answer» E.
5810.

\[\frac{d}{dx}\left[ \log \sqrt{\sin \sqrt{{{e}^{x}}}} \right]\]=       

A.            \[\frac{1}{4}{{e}^{x/2}}\cot ({{e}^{x/2}})\]
B.            \[{{e}^{x/2}}\cot ({{e}^{x/2}})\]
C.            \[\frac{1}{4}{{e}^{x}}\cot \,({{e}^{x}})\]
D.            \[\frac{1}{2}{{e}^{x/2}}\cot \,({{e}^{x/2}})\]
Answer» B.            \[{{e}^{x/2}}\cot ({{e}^{x/2}})\]
5811.

 \[\frac{d}{dx}\left[ \frac{2}{\pi }\sin {{x}^{0}} \right]=\]

A.            \[\frac{\pi }{180}\cos {{x}^{0}}\]
B.            \[\frac{1}{90}\cos {{x}^{0}}\]
C.            \[\frac{\pi }{90}\cos {{x}^{0}}\]
D.            \[\frac{2}{90}\cos {{x}^{0}}\]
Answer» C.            \[\frac{\pi }{90}\cos {{x}^{0}}\]
5812.

If \[y=x\sin x,\]then                      

A.            \[\frac{1}{y}\frac{dy}{dx}=\frac{1}{x}+\cot x\]
B.            \[\frac{dy}{dx}=\frac{1}{x}+\cot x\]
C.            \[\frac{1}{y}\frac{dy}{dx}=\frac{1}{x}-\cot x\]
D.            None of these
Answer» B.            \[\frac{dy}{dx}=\frac{1}{x}+\cot x\]
5813.

If \[y={{\sec }^{-1}}\left( \frac{x+1}{x-1} \right)+{{\sin }^{-1}}\left( \frac{x-1}{x+1} \right)\], then \[\frac{dy}{dx}=\]          [MNR 1984]

A.            0
B.            1
C.            2
D.            3
Answer» B.            1
5814.

If \[y={{\tan }^{-1}}\left( \frac{\sqrt{a}-\sqrt{x}}{1+\sqrt{ax}} \right)\], then \[\frac{dy}{dx}=\]          [AI CBSE 1988]

A.            \[\frac{1}{2(1+x)\sqrt{x}}\]
B.            \[\frac{1}{(1+x)\sqrt{x}}\]
C.            \[-\frac{1}{2(1+x)\sqrt{x}}\]
D.            None of these
Answer» D.            None of these
5815.

If \[y=\frac{2{{(x-\sin x)}^{3/2}}}{\sqrt{x}}\], then \[\frac{dy}{dx}=\]                 [Roorkee 1971]

A.            \[\frac{2{{(x-\sin x)}^{3/2}}}{\sqrt{x}}\left[ \frac{3}{2}.\frac{1-\cos x}{1-\sin x}-\frac{1}{2x} \right]\]
B.            \[\frac{2{{(x-\sin x)}^{3/2}}}{\sqrt{x}}\left[ \frac{3}{2}.\frac{1-\cos x}{x-\sin x}-\frac{1}{2x} \right]\]
C.            \[\frac{2{{(x-\sin x)}^{1/2}}}{\sqrt{x}}\left[ \frac{3}{2}.\frac{1-\cos x}{x-\sin x}-\frac{1}{2x} \right]\]
D.            None of these
Answer» C.            \[\frac{2{{(x-\sin x)}^{1/2}}}{\sqrt{x}}\left[ \frac{3}{2}.\frac{1-\cos x}{x-\sin x}-\frac{1}{2x} \right]\]
5816.

If \[y=\frac{{{e}^{2x}}+{{e}^{-2x}}}{{{e}^{2x}}-{{e}^{-2x}}}\], then \[\frac{dy}{dx}=\]                   [AI CBSE 1988]

A.            \[\frac{-8}{{{({{e}^{2x}}-{{e}^{-2x}})}^{2}}}\]
B.            \[\frac{8}{{{({{e}^{2x}}-{{e}^{-2x}})}^{2}}}\]
C.            \[\frac{-4}{{{({{e}^{2x}}-{{e}^{-2x}})}^{2}}}\]
D.            \[\frac{4}{{{({{e}^{2x}}-{{e}^{-2x}})}^{2}}}\]
Answer» B.            \[\frac{8}{{{({{e}^{2x}}-{{e}^{-2x}})}^{2}}}\]
5817.

\[\frac{d}{dx}\left\{ {{e}^{x}}\log (1+{{x}^{2}}) \right\}=\]                                [AI CBSE 1987]

A.            \[{{e}^{x}}\left[ \log (1+{{x}^{2}})+\frac{2x}{1+{{x}^{2}}} \right]\]
B.            \[{{e}^{x}}\left[ \log (1+{{x}^{2}})-\frac{2x}{1+{{x}^{2}}} \right]\]
C.            \[{{e}^{x}}\left[ \log (1+{{x}^{2}})+\frac{x}{1+{{x}^{2}}} \right]\]     
D.            \[{{e}^{x}}\left[ \log (1+{{x}^{2}})-\frac{x}{1+{{x}^{2}}} \right]\]
Answer» B.            \[{{e}^{x}}\left[ \log (1+{{x}^{2}})-\frac{2x}{1+{{x}^{2}}} \right]\]
5818.

If \[y=\sqrt{\frac{1+{{e}^{x}}}{1-{{e}^{x}}}}\], then \[\frac{dy}{dx}=\]                                         [AI CBSE 1986]

A.            \[\frac{{{e}^{x}}}{(1-{{e}^{x}})\sqrt{1-{{e}^{2x}}}}\]
B.            \[\frac{{{e}^{x}}}{(1-{{e}^{x}})\sqrt{1-{{e}^{x}}}}\]
C.            \[\frac{{{e}^{x}}}{(1-{{e}^{x}})\sqrt{1+{{e}^{2x}}}}\]
D.            \[\frac{{{e}^{x}}}{(1-{{e}^{x}})\sqrt{1-{{e}^{2x}}}}\]
Answer» B.            \[\frac{{{e}^{x}}}{(1-{{e}^{x}})\sqrt{1-{{e}^{x}}}}\]
5819.

\[\frac{d}{dx}\{{{e}^{-a{{x}^{2}}}}\log (\sin x)\}=\]                                            [AI CBSE 1984]

A.            \[{{e}^{-a{{x}^{2}}}}(\cot x+2ax\log \sin x)\]
B.            \[{{e}^{-a{{x}^{2}}}}(\cot x+ax\log \sin x)\]
C.            \[{{e}^{-a{{x}^{2}}}}(\cot x-2ax\log \sin x)\]
D.            None of these
Answer» D.            None of these
5820.

If \[y=\frac{{{e}^{2x}}\cos x}{x\sin x},\]then \[\frac{dy}{dx}=\]                                [AI CBSE 1982]

A.            \[\frac{{{e}^{2x}}[(2x-1)\cot x-x\,\text{cose}{{\text{c}}^{2}}x]}{{{x}^{2}}}\]
B.            \[\frac{{{e}^{2x}}[(2x+1)\cot x-x\,\text{cose}{{\text{c}}^{2}}x]}{{{x}^{2}}}\]
C.            \[\frac{{{e}^{2x}}[(2x-1)\cot x+x\,\text{cose}{{\text{c}}^{2}}x]}{{{x}^{2}}}\]
D.            None of these
Answer» B.            \[\frac{{{e}^{2x}}[(2x+1)\cot x-x\,\text{cose}{{\text{c}}^{2}}x]}{{{x}^{2}}}\]
5821.

 If \[y=\frac{{{e}^{x}}\log x}{{{x}^{2}}}\], then \[\frac{dy}{dx}=\]                                       [AI CBSE 1982]

A.            \[\frac{{{e}^{x}}[1+(x+2)\log x]}{{{x}^{3}}}\]
B.            \[\frac{{{e}^{x}}[1-(x-2)\log x]}{{{x}^{4}}}\]
C.            \[\frac{{{e}^{x}}[1-(x-2)\log x]}{{{x}^{3}}}\]
D.            \[\frac{{{e}^{x}}[1+(x-2)\log x]}{{{x}^{3}}}\]
Answer» E.
5822.

\[\frac{d}{dx}\left[ \frac{{{e}^{ax}}}{\sin (bx+c)} \right]=\]                                   [AI CBSE 1983]

A.            \[\frac{{{e}^{ax}}[a\sin (bx+c)+b\cos (bx+c)]}{{{\sin }^{2}}(bx+c)}\]
B.            \[\frac{{{e}^{ax}}[a\sin (bx+c)-b\cos (bx+c)]}{\sin (bx+c)}\]
C.            \[\frac{{{e}^{ax}}[a\sin (bx+c)-b\cos (bx+c)]}{{{\sin }^{2}}(bx+c)}\]
D.            None of these
Answer» D.            None of these
5823.

\[\frac{d}{dx}(x{{e}^{{{x}^{2}}}})=\]                                                                   [DSSE 1981]

A.            \[2{{x}^{2}}{{e}^{x}}^{2}+{{e}^{x}}^{2}\]
B.            \[{{x}^{2}}{{e}^{x}}^{2}+{{e}^{x}}^{2}\]
C.            \[{{e}^{x}}.2{{x}^{2}}+{{e}^{x}}^{2}\]
D.            None of these
Answer» B.            \[{{x}^{2}}{{e}^{x}}^{2}+{{e}^{x}}^{2}\]
5824.

\[\frac{d}{dx}\{\log (\sec x+\tan x)\}=\]                                                         [AISSE 1982]

A.            \[\cos x\]
B.            \[\sec x\]
C.            \[\tan x\]
D.            \[\cot x\]
Answer» C.            \[\tan x\]
5825.

\[\frac{d}{dx}{{e}^{x\sin x}}=\]                          [DSSE 1979]

A.            \[{{e}^{x\sin x}}(x\cos x+\sin x)\]
B.            \[{{e}^{x\sin x}}(\cos x+x\sin x)\]
C.            \[{{e}^{x\sin x}}(\cos x+\sin x)\]
D.            None of these
Answer» B.            \[{{e}^{x\sin x}}(\cos x+x\sin x)\]
5826.

\[\frac{d}{dx}\left[ {{\tan }^{-1}}\sqrt{\frac{1-\cos x}{1+\cos x}} \right]=\] [BIT Ranchi 1989; Roorkee 1989; RPET 1996]

A.            \[-\frac{1}{2}\]
B.            0
C.            \[\frac{1}{2}\]
D.            1
Answer» D.            1
5827.

\[\frac{d}{dx}\left[ \log \sqrt{\frac{1-\cos x}{1+\cos x}} \right]=\]                             [BIT Ranchi 1990]

A.            \[\sec x\]
B.            \[\cos \text{ec}\,x\]
C.            \[\cos \text{ec}\frac{x}{2}\]
D.            \[\sec \frac{x}{2}\]
Answer» C.            \[\cos \text{ec}\frac{x}{2}\]
5828.

The differential coefficient of the given function \[{{\log }_{e}}\left( \sqrt{\frac{1+\sin x}{1-\sin x}} \right)\] with respect to x is          [MP PET 1993]

A.            \[\cos \text{ec}\,x\]
B.            \[\tan x\]
C.            \[\cos x\]
D.            \[\sec x\]
Answer» E.
5829.

If \[y={{\cot }^{-1}}\left( \frac{1+x}{1-x} \right)\], then \[\frac{dy}{dx}=\]                       [DSSE 1984]

A.            \[\frac{1}{1+{{x}^{2}}}\]
B.          \[-\frac{1}{1+{{x}^{2}}}\]
C.            \[\frac{2}{1+{{x}^{2}}}\]
D.            \[-\frac{2}{1+{{x}^{2}}}\]
Answer» C.            \[\frac{2}{1+{{x}^{2}}}\]
5830.

If \[y=1+x+\frac{{{x}^{2}}}{2!}+\frac{{{x}^{3}}}{3!}+.....\infty ,\]then \[\frac{dy}{dx}=\] [Karnataka CET 1999]

A.            y
B.            \[y-1\]
C.            \[y+1\]
D.            None of these
Answer» B.            \[y-1\]
5831.

If \[y={{\tan }^{-1}}\left( \frac{{{x}^{1/3}}+{{a}^{1/3}}}{1-{{x}^{1/3}}{{a}^{1/3}}} \right)\], then \[\frac{dy}{dx}=\]      [DSSE 1986]

A.          \[\frac{1}{3{{x}^{2/3}}(1+{{x}^{2/3}})}\]
B.            \[\frac{1}{3{{x}^{2/3}}(1+{{x}^{2/3}})}\]
C.            \[-\frac{1}{3{{x}^{2/3}}(1+{{x}^{2/3}})}\]
D.            \[-\frac{a}{3{{x}^{2/3}}(1+{{x}^{2/3}})}\]
Answer» B.            \[\frac{1}{3{{x}^{2/3}}(1+{{x}^{2/3}})}\]
5832.

\[\frac{d}{dx}\left( {{x}^{3}}{{\tan }^{2}}\frac{x}{2} \right)\]=                                          [AISSE 1979]

A.            \[{{x}^{3}}\tan \frac{x}{2}.{{\sec }^{2}}\frac{x}{2}+3x{{\tan }^{2}}\frac{x}{2}\]             
B.          \[{{x}^{3}}\tan \frac{x}{2}.{{\sec }^{2}}\frac{x}{2}+3{{x}^{2}}{{\tan }^{2}}\frac{x}{2}\]
C.            \[{{x}^{3}}{{\tan }^{2}}\frac{x}{2}.{{\sec }^{2}}\frac{x}{2}+3{{x}^{2}}{{\tan }^{2}}\frac{x}{2}\]
D.            None of these
Answer» C.            \[{{x}^{3}}{{\tan }^{2}}\frac{x}{2}.{{\sec }^{2}}\frac{x}{2}+3{{x}^{2}}{{\tan }^{2}}\frac{x}{2}\]
5833.

\[\frac{d}{dx}\left( \frac{\sec x+\tan x}{\sec x-\tan x} \right)=\]             [DSSE 1979, 81; CBSE 1981]

A.            \[\frac{2\cos x}{{{(1-\sin x)}^{2}}}\]
B.            \[\frac{\cos x}{{{(1-\sin x)}^{2}}}\]
C.            \[\frac{2\cos x}{1-\sin x}\]
D.            None of these
Answer» B.            \[\frac{\cos x}{{{(1-\sin x)}^{2}}}\]
5834.

\[\frac{d}{dx}\sqrt{{{\sec }^{2}}x+\text{cose}{{\text{c}}^{2}}x}=\]                                [DSSE 1981]

A.            \[4\cos \text{ec 2}x.\cot 2x\]
B.            \[-4\cos \text{ec 2}x.\cot 2x\]
C.            \[-4\cos \text{ec }x.\cot 2x\]
D.            None of these
Answer» C.            \[-4\cos \text{ec }x.\cot 2x\]
5835.

\[\frac{d}{dx}\sqrt{x\sin x}=\]                              [AISSE 1985]

A.            \[\frac{\sin x+x\cos x}{2\sqrt{x\sin x}}\]
B.            \[\frac{\sin x+x\cos x}{\sqrt{x\sin x}}\]
C.            \[\frac{x\sin x+\cos x}{\sqrt{2\sin x}}\]
D.            \[\frac{\sin x+x\cos x}{2\sqrt{x\sin x}}\]
Answer» B.            \[\frac{\sin x+x\cos x}{\sqrt{x\sin x}}\]
5836.

\[\frac{d}{dx}{{({{x}^{2}}+\cos x)}^{4}}=\]                                                        [DSSE 1979]

A.            \[4({{x}^{2}}+\cos x)(2x-\sin x)\]                                         
B.  \[4{{({{x}^{2}}-\cos x)}^{3}}(2x-\sin x)\]                                   
C.            \[4{{({{x}^{2}}+\cos x)}^{3}}(2x-\sin x)\]
D.            \[4{{({{x}^{2}}+\cos x)}^{3}}(2x+\sin x)\]
Answer» D.            \[4{{({{x}^{2}}+\cos x)}^{3}}(2x+\sin x)\]
5837.

 If \[y=\sqrt{\frac{1+\tan x}{1-\tan x}}\], then \[\frac{dy}{dx}=\] [AISSE 1981, 83, 84, 85; DSSE 1985; AI CBSE 1981, 83]

A.          \[\frac{1}{2}\sqrt{\frac{1-\tan x}{1+\tan x}}.{{\sec }^{2}}\left( \frac{\pi }{4}+x \right)\]
B.            \[\sqrt{\frac{1-\tan x}{1+\tan x}}.{{\sec }^{2}}\left( \frac{\pi }{4}+x \right)\]
C.            \[\frac{1}{2}\sqrt{\frac{1-\tan x}{1+\tan x}}.\sec \left( \frac{\pi }{4}+x \right)\]
D.            None of these
Answer» B.            \[\sqrt{\frac{1-\tan x}{1+\tan x}}.{{\sec }^{2}}\left( \frac{\pi }{4}+x \right)\]
5838.

If \[y=\sin \left( \frac{1+{{x}^{2}}}{1-{{x}^{2}}} \right)\], then \[\frac{dy}{dx}=\]                      [AISSE 1987]

A.            \[\frac{4x}{1-{{x}^{2}}}.\cos \left( \frac{1+{{x}^{2}}}{1-{{x}^{2}}} \right)\]
B.            \[\frac{x}{{{(1-{{x}^{2}})}^{2}}}.\cos \left( \frac{1+{{x}^{2}}}{1-{{x}^{2}}} \right)\]
C.            \[\frac{x}{(1-{{x}^{2}})}.\cos \left( \frac{1+{{x}^{2}}}{1-{{x}^{2}}} \right)\]
D.            \[\frac{4x}{{{(1-{{x}^{2}})}^{2}}}.\cos \left( \frac{1+{{x}^{2}}}{1-{{x}^{2}}} \right)\]
Answer» E.
5839.

\[\frac{d}{dx}\{\cos (\sin {{x}^{2}})\}=\]                                                                   [DSSE 1979]

A.            \[\sin (\sin {{x}^{2}}).\cos {{x}^{2}}.2x\]
B.            \[-\sin (\sin {{x}^{2}}).\cos {{x}^{2}}.2x\]
C.            \[-\sin (\sin {{x}^{2}}).{{\cos }^{2}}x.2x\]
D.            None of these
Answer» C.            \[-\sin (\sin {{x}^{2}}).{{\cos }^{2}}x.2x\]
5840.

If \[y=1+x+\frac{{{x}^{2}}}{2\,!}+\frac{{{x}^{3}}}{3\,!}+.....+\frac{{{x}^{n}}}{n\,!}\], then \[\frac{dy}{dx}=\]

A.            y
B.            \[y+\frac{{{x}^{n}}}{n!}\]
C.            \[y-\frac{{{x}^{n}}}{n!}\]
D.            \[y-1-\frac{{{x}^{n}}}{n!}\]
Answer» D.            \[y-1-\frac{{{x}^{n}}}{n!}\]
5841.

 If \[y={{(x{{\cot }^{3}}x)}^{3/2}},\]then \[dy/dx=\]

A.            \[\frac{3}{2}{{(x{{\cot }^{3}}x)}^{1/2}}[{{\cot }^{3}}x-3x{{\cot }^{2}}x\cos \text{e}{{\text{c}}^{2}}x]\]
B.            \[\frac{3}{2}{{(x{{\cot }^{3}}x)}^{1/2}}[{{\cot }^{2}}x-3x{{\cot }^{2}}x\,\text{cose}{{\text{c}}^{2}}x]\]
C.            \[\frac{3}{2}{{(x{{\cot }^{3}}x)}^{1/3}}[{{\cot }^{3}}x-3x\,\text{cos}\text{e}{{\text{c}}^{2}}x]\]
D.            \[\frac{3}{2}{{(x{{\cot }^{3}}x)}^{3/2}}[{{\cot }^{3}}x-3x\,\text{cos}\text{e}{{\text{c}}^{2}}x]\]
Answer» B.            \[\frac{3}{2}{{(x{{\cot }^{3}}x)}^{1/2}}[{{\cot }^{2}}x-3x{{\cot }^{2}}x\,\text{cose}{{\text{c}}^{2}}x]\]
5842.

If \[y=\frac{\sqrt{a+x}-\sqrt{a-x}}{\sqrt{a+x}+\sqrt{a-x}}\], then  \[\frac{dy}{dx}=\]             [AISSE 1986]

A.          \[\frac{ay}{x\sqrt{{{a}^{2}}-{{x}^{2}}}}\]
B.            \[\frac{ay}{\sqrt{{{a}^{2}}-{{x}^{2}}}}\]
C.            \[\frac{ay}{x\sqrt{{{x}^{2}}-{{a}^{2}}}}\]
D.            None of these
Answer» B.            \[\frac{ay}{\sqrt{{{a}^{2}}-{{x}^{2}}}}\]
5843.

If \[y=\frac{\sqrt{{{x}^{2}}+1}+\sqrt{{{x}^{2}}-1}}{\sqrt{{{x}^{2}}+1}-\sqrt{{{x}^{2}}-1}}\], then \[\frac{dy}{dx}=\]

A.            \[2x+\frac{2{{x}^{3}}}{\sqrt{{{x}^{4}}-1}}\]
B.            \[2x+\frac{{{x}^{3}}}{\sqrt{{{x}^{4}}-1}}\]
C.            \[x+\frac{2{{x}^{3}}}{\sqrt{{{x}^{4}}-1}}\]
D.            None of these
Answer» B.            \[2x+\frac{{{x}^{3}}}{\sqrt{{{x}^{4}}-1}}\]
5844.

If \[A=\frac{{{2}^{x}}\cot x}{\sqrt{x}},\]then \[\frac{dA}{dx}=\]

A.          \[\frac{{{2}^{x-1}}\left\{ -2x\,\text{cos}\text{e}{{\text{c}}^{2}}x+\cot x.\log \left( \frac{{{4}^{x}}}{e} \right) \right\}}{{{x}^{3/2}}}\]
B.            \[\frac{{{2}^{x-1}}\left\{ -2x\cos \text{e}{{\text{c}}^{2}}x+\cot x.\log \left( \frac{{{4}^{x}}}{e} \right) \right\}}{x}\]
C.            \[\frac{2x\left\{ -2x\text{cose}{{\text{c}}^{2}}x+\cot x.\log \left( \frac{{{4}^{x}}}{e} \right) \right\}}{{{x}^{\text{3/2}}}}\]
D.            None of these
Answer» B.            \[\frac{{{2}^{x-1}}\left\{ -2x\cos \text{e}{{\text{c}}^{2}}x+\cot x.\log \left( \frac{{{4}^{x}}}{e} \right) \right\}}{x}\]
5845.

\[\frac{d}{dx}\left( \frac{\log x}{\sin x} \right)=\]                               

A.            \[\frac{\frac{\sin x}{x}-\log x.\cos x}{\sin x}\]
B.            \[\frac{\frac{\sin x}{x}-\log x.\cos x}{{{\sin }^{2}}x}\]
C.            \[\frac{\sin x-\log x.\cos x}{{{\sin }^{2}}x}\]
D.            \[\frac{\frac{\sin x}{x}-\log x}{{{\sin }^{2}}x}\]
Answer» C.            \[\frac{\sin x-\log x.\cos x}{{{\sin }^{2}}x}\]
5846.

If \[y=\frac{\tan x+\cot x}{\tan x-\cot x},\]then \[\frac{dy}{dx}=\]

A.            \[2\tan 2x\sec 2x\]
B.            \[\tan 2x\sec 2x\]
C.            \[-\tan 2x\sec 2x\]
D.          \[-2\tan 2x\sec 2x\]
Answer» E.
5847.

If \[y={{x}^{2}}\log x+\frac{2}{\sqrt{x}},\] then \[\frac{dy}{dx}=\]

A.            \[x+2x\log x-\frac{1}{\sqrt{x}}\]
B.            \[x+2x\log x-\frac{1}{{{x}^{3/2}}}\]
C.            \[x+2x\log x-\frac{2}{{{x}^{3/2}}}\]
D.            None of these
Answer» C.            \[x+2x\log x-\frac{2}{{{x}^{3/2}}}\]
5848.

If \[y={{t}^{4/3}}-3{{t}^{-2/3}}\], then \[dy/dt\]=

A.            \[\frac{2{{t}^{2}}+3}{3{{t}^{5/3}}}\]
B.            \[\frac{2{{t}^{2}}+3}{{{t}^{5/3}}}\]
C.            \[\frac{2(2{{t}^{2}}+3)}{{{t}^{5/3}}}\]
D.          \[\frac{2(2{{t}^{2}}+3)}{3{{t}^{5/3}}}\]
Answer» E.
5849.

\[\frac{d}{dx}{{\sin }^{-1}}(3x-4{{x}^{3}})=\]                                                     [RPET 2003]

A.            \[\frac{3}{\sqrt{1-{{x}^{2}}}}\]
B.            \[\frac{-3}{\sqrt{1-{{x}^{2}}}}\]
C.            \[\frac{1}{\sqrt{1-{{x}^{2}}}}\]
D.            \[\frac{-1}{\sqrt{1-{{x}^{2}}}}\]
Answer» B.            \[\frac{-3}{\sqrt{1-{{x}^{2}}}}\]
5850.

\[\frac{d}{dx}\left( \frac{1}{{{x}^{4}}\sec x} \right)=\]     

A.            \[\frac{x\sin x+4\cos x}{{{x}^{5}}}\]
B.            \[\frac{-(x\sin x+4\cos x)}{{{x}^{5}}}\]
C.                    \[\frac{4\cos x-x\sin x}{{{x}^{5}}}\]
D.            None of these
Answer» C.                    \[\frac{4\cos x-x\sin x}{{{x}^{5}}}\]