1.

\[\frac{d}{dx}\left( \frac{\log x}{\sin x} \right)=\]                               

A.            \[\frac{\frac{\sin x}{x}-\log x.\cos x}{\sin x}\]
B.            \[\frac{\frac{\sin x}{x}-\log x.\cos x}{{{\sin }^{2}}x}\]
C.            \[\frac{\sin x-\log x.\cos x}{{{\sin }^{2}}x}\]
D.            \[\frac{\frac{\sin x}{x}-\log x}{{{\sin }^{2}}x}\]
Answer» C.            \[\frac{\sin x-\log x.\cos x}{{{\sin }^{2}}x}\]


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