\[\frac{d}{dx}[{{e}^{ax}}\cos (bx+c)]\]= [AISSE 1989]

\[{{e}^{ax}}[a\sin (bx+c)-b\cos (bx+c)]\]

\[{{e}^{ax}}[a\cos (bx+c)-b\sin (bx+c)]\]

\[{{e}^{ax}}[\cos (bx+c)-\sin (bx+c)]\]

\[\frac{d}{dx}[{{e}^{ax}}\cos (bx+c)]\]=

1.	\[\frac{d}{dx}[{{e}^{ax}}\cos (bx+c)]\]= [AISSE 1989]
A.	\[{{e}^{ax}}[a\cos (bx+c)-b\sin (bx+c)]\]
B.	\[{{e}^{ax}}[a\sin (bx+c)-b\cos (bx+c)]\]
C.	\[{{e}^{ax}}[\cos (bx+c)-\sin (bx+c)]\]
D.	None of these
Answer» B. \[{{e}^{ax}}[a\sin (bx+c)-b\cos (bx+c)]\]

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\[\frac{d}{dx}[{{e}^{ax}}\cos (bx+c)]\]= [AISSE 1989]

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