\[\frac{d}{dx}{{({{x}^{2}}+\cos x)}^{4}}=\] [DSSE 1979]

\[4{{({{x}^{2}}+\cos x)}^{3}}(2x+\sin x)\]

\[4({{x}^{2}}+\cos x)(2x-\sin x)\]

\[4{{({{x}^{2}}-\cos x)}^{3}}(2x-\sin x)\]

\[4{{({{x}^{2}}+\cos x)}^{3}}(2x-\sin x)\]

\[\frac{d}{dx}{{({{x}^{2}}+\cos x)}^{4}}=\] �

1.	\[\frac{d}{dx}{{({{x}^{2}}+\cos x)}^{4}}=\] [DSSE 1979]
A.	\[4({{x}^{2}}+\cos x)(2x-\sin x)\]
B.	\[4{{({{x}^{2}}-\cos x)}^{3}}(2x-\sin x)\]
C.	\[4{{({{x}^{2}}+\cos x)}^{3}}(2x-\sin x)\]
D.	\[4{{({{x}^{2}}+\cos x)}^{3}}(2x+\sin x)\]
Answer» D. \[4{{({{x}^{2}}+\cos x)}^{3}}(2x+\sin x)\]

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\[\frac{d}{dx}{{({{x}^{2}}+\cos x)}^{4}}=\] [DSSE 1979]

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