1.

 If \[y=\frac{{{e}^{x}}\log x}{{{x}^{2}}}\], then \[\frac{dy}{dx}=\]                                       [AI CBSE 1982]

A.            \[\frac{{{e}^{x}}[1+(x+2)\log x]}{{{x}^{3}}}\]
B.            \[\frac{{{e}^{x}}[1-(x-2)\log x]}{{{x}^{4}}}\]
C.            \[\frac{{{e}^{x}}[1-(x-2)\log x]}{{{x}^{3}}}\]
D.            \[\frac{{{e}^{x}}[1+(x-2)\log x]}{{{x}^{3}}}\]
Answer» E.


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