1.

If \[y=x\sin x,\]then                      

A.            \[\frac{1}{y}\frac{dy}{dx}=\frac{1}{x}+\cot x\]
B.            \[\frac{dy}{dx}=\frac{1}{x}+\cot x\]
C.            \[\frac{1}{y}\frac{dy}{dx}=\frac{1}{x}-\cot x\]
D.            None of these
Answer» B.            \[\frac{dy}{dx}=\frac{1}{x}+\cot x\]


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