\[\frac{d}{dx}\left( \frac{\sec x+\tan x}{\sec x-\tan x} \right)=\] [DSSE 1979, 81; CBSE 1981]

\[\frac{\cos x}{{{(1-\sin x)}^{2}}}\]

\[\frac{2\cos x}{{{(1-\sin x)}^{2}}}\]

\[\frac{d}{dx}\left( \frac{\sec x+\tan x}{\sec x-\tan x} \right)=\] �

1.	\[\frac{d}{dx}\left( \frac{\sec x+\tan x}{\sec x-\tan x} \right)=\] [DSSE 1979, 81; CBSE 1981]
A.	\[\frac{2\cos x}{{{(1-\sin x)}^{2}}}\]
B.	\[\frac{\cos x}{{{(1-\sin x)}^{2}}}\]
C.	\[\frac{2\cos x}{1-\sin x}\]
D.	None of these
Answer» B. \[\frac{\cos x}{{{(1-\sin x)}^{2}}}\]

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\[\frac{d}{dx}\left( \frac{\sec x+\tan x}{\sec x-\tan x} \right)=\] [DSSE 1979, 81; CBSE 1981]

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