1.

If \[y={{\tan }^{-1}}\left( \frac{{{x}^{1/3}}+{{a}^{1/3}}}{1-{{x}^{1/3}}{{a}^{1/3}}} \right)\], then \[\frac{dy}{dx}=\]      [DSSE 1986]

A.          \[\frac{1}{3{{x}^{2/3}}(1+{{x}^{2/3}})}\]
B.            \[\frac{1}{3{{x}^{2/3}}(1+{{x}^{2/3}})}\]
C.            \[-\frac{1}{3{{x}^{2/3}}(1+{{x}^{2/3}})}\]
D.            \[-\frac{a}{3{{x}^{2/3}}(1+{{x}^{2/3}})}\]
Answer» B.            \[\frac{1}{3{{x}^{2/3}}(1+{{x}^{2/3}})}\]


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