\[\frac{d}{dx}\{\cos (\sin {{x}^{2}})\}=\] [DSSE 1979]

\[-\sin (\sin {{x}^{2}}).{{\cos }^{2}}x.2x\]

\[\sin (\sin {{x}^{2}}).\cos {{x}^{2}}.2x\]

\[-\sin (\sin {{x}^{2}}).\cos {{x}^{2}}.2x\]

\[\frac{d}{dx}\{\cos (\sin {{x}^{2}})\}=\]

1.	\[\frac{d}{dx}\{\cos (\sin {{x}^{2}})\}=\] [DSSE 1979]
A.	\[\sin (\sin {{x}^{2}}).\cos {{x}^{2}}.2x\]
B.	\[-\sin (\sin {{x}^{2}}).\cos {{x}^{2}}.2x\]
C.	\[-\sin (\sin {{x}^{2}}).{{\cos }^{2}}x.2x\]
D.	None of these
Answer» C. \[-\sin (\sin {{x}^{2}}).{{\cos }^{2}}x.2x\]

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\[\frac{d}{dx}\{\cos (\sin {{x}^{2}})\}=\] [DSSE 1979]

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