If \[y={{\cot }^{-1}}\left( \frac{1+x}{1-x} \right)\], then \[\frac{dy}{dx}=\] [DSSE 1984]

If \[y={{\cot }^{-1}}\left( \frac{1+x}{1-x} \right)\], then \[\frac{dy

1.	If \[y={{\cot }^{-1}}\left( \frac{1+x}{1-x} \right)\], then \[\frac{dy}{dx}=\] [DSSE 1984]
A.	\[\frac{1}{1+{{x}^{2}}}\]
B.	\[-\frac{1}{1+{{x}^{2}}}\]
C.	\[\frac{2}{1+{{x}^{2}}}\]
D.	\[-\frac{2}{1+{{x}^{2}}}\]
Answer» C. \[\frac{2}{1+{{x}^{2}}}\]

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If \[y={{\cot }^{-1}}\left( \frac{1+x}{1-x} \right)\], then \[\frac{dy}{dx}=\] [DSSE 1984]

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