\[\frac{d}{dx}{{\sin }^{-1}}(3x-4{{x}^{3}})=\] [RPET 2003]

\[\frac{-3}{\sqrt{1-{{x}^{2}}}}\]

\[\frac{3}{\sqrt{1-{{x}^{2}}}}\]

\[\frac{1}{\sqrt{1-{{x}^{2}}}}\]

\[\frac{-1}{\sqrt{1-{{x}^{2}}}}\]

\[\frac{d}{dx}{{\sin }^{-1}}(3x-4{{x}^{3}})=\]

1.	\[\frac{d}{dx}{{\sin }^{-1}}(3x-4{{x}^{3}})=\] [RPET 2003]
A.	\[\frac{3}{\sqrt{1-{{x}^{2}}}}\]
B.	\[\frac{-3}{\sqrt{1-{{x}^{2}}}}\]
C.	\[\frac{1}{\sqrt{1-{{x}^{2}}}}\]
D.	\[\frac{-1}{\sqrt{1-{{x}^{2}}}}\]
Answer» B. \[\frac{-3}{\sqrt{1-{{x}^{2}}}}\]

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\[\frac{d}{dx}{{\sin }^{-1}}(3x-4{{x}^{3}})=\] [RPET 2003]

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