MCQOPTIONS
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| 1. |
If \[y=1+x+\frac{{{x}^{2}}}{2!}+\frac{{{x}^{3}}}{3!}+.....\infty ,\]then \[\frac{dy}{dx}=\] [Karnataka CET 1999] |
| A. | y |
| B. | \[y-1\] |
| C. | \[y+1\] |
| D. | None of these |
| Answer» B. \[y-1\] | |