If \[y={{\tan }^{-1}}\left( \frac{\sqrt{a}-\sqrt{x}}{1+\sqrt{ax}} \right)\], then \[\frac{dy}{dx}=\] [AI CBSE 1988]

If \[y={{\tan }^{-1}}\left( \frac{\sqrt{a}-\sqrt{x}}{1+\sqrt{ax}} \rig

1.	If \[y={{\tan }^{-1}}\left( \frac{\sqrt{a}-\sqrt{x}}{1+\sqrt{ax}} \right)\], then \[\frac{dy}{dx}=\] [AI CBSE 1988]
A.	\[\frac{1}{2(1+x)\sqrt{x}}\]
B.	\[\frac{1}{(1+x)\sqrt{x}}\]
C.	\[-\frac{1}{2(1+x)\sqrt{x}}\]
D.	None of these
Answer» D. None of these

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If \[y={{\tan }^{-1}}\left( \frac{\sqrt{a}-\sqrt{x}}{1+\sqrt{ax}} \right)\], then \[\frac{dy}{dx}=\] [AI CBSE 1988]

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