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This section includes 239 Mcqs, each offering curated multiple-choice questions to sharpen your Digital Electronics knowledge and support exam preparation. Choose a topic below to get started.
| 201. |
The base of the hexadecimal system is: |
| A. | eight. |
| B. | sixteen. |
| C. | ten. |
| D. | two. |
| Answer» C. ten. | |
| 202. |
Convert the decimal number 151.75 to binary. |
| A. | 10000111.11 |
| B. | 11010011.01 |
| C. | 111100 |
| D. | 10010111.11 |
| Answer» E. | |
| 203. |
Convert 59.7210 to BCD. |
| A. | 111011 |
| B. | 1011001.011 |
| C. | 1110.11 |
| D. | 101100000000000 |
| Answer» C. 1110.11 | |
| 204. |
The binary number system is fundamental to all digital computers. |
| A. | 1 |
| B. | |
| C. | 1 |
| D. | |
| Answer» B. | |
| 205. |
Convert 5278 to binary. |
| A. | 11100111 |
| B. | 101010111 |
| C. | 343 |
| D. | 111010101 |
| Answer» C. 343 | |
| 206. |
Assign the proper odd parity bit to the code 111001. |
| A. | 1111011 |
| B. | 1111001 |
| C. | 111111 |
| D. | 11111 |
| Answer» C. 111111 | |
| 207. |
Convert 8B3F16 to binary. |
| A. | 35647 |
| B. | 11010 |
| C. | 1011000000000000 |
| D. | 1000100000000000 |
| Answer» E. | |
| 208. |
An analog signal has a range from 0 V to 5 V. What is the total number of analog possibilities within this range? |
| A. | 5 |
| B. | 50 |
| C. | 250 |
| D. | infinite |
| Answer» E. | |
| 209. |
In odd parity, 100011010 would pass the parity check. |
| A. | 1 |
| B. | |
| C. | 1 |
| D. | |
| Answer» C. 1 | |
| 210. |
Which is typically the longest: bit, byte, nibble, word? |
| A. | Bit |
| B. | Byte |
| C. | Nibble |
| D. | Word |
| Answer» E. | |
| 211. |
What decimal number does 25 represent? |
| A. | 10 |
| B. | 31 |
| C. | 25 |
| D. | 32 |
| Answer» E. | |
| 212. |
The binary number for octal 458 is ________. |
| A. | 100010 |
| B. | 100101 |
| C. | 110101 |
| D. | 100100 |
| Answer» C. 110101 | |
| 213. |
Select one of the following statements that best describes the parity method of error detection. |
| A. | Parity checking is best suited for detecting single-bit errors in transmitted codes. |
| B. | Parity checking is not suitable for detecting single-bit errors in transmitted codes. |
| C. | Parity checking is capable of detecting and correcting errors in transmitted codes. |
| D. | Parity checking is best suited for detecting double-bit errors that occur during the transmission of codes from one location to another. |
| Answer» B. Parity checking is not suitable for detecting single-bit errors in transmitted codes. | |
| 214. |
The difference of 111 – 001 equals ________. |
| A. | 100 |
| B. | 111 |
| C. | 1 |
| D. | 110 |
| Answer» E. | |
| 215. |
Binary 10111111 is ________ in hexadecimal. |
| A. | BF16 |
| B. | FB16 |
| C. | 27716 |
| D. | 10111111 |
| Answer» B. FB16 | |
| 216. |
What is the result when a decimal 5238 is converted to base 16? |
| A. | 327.375 |
| B. | 12.166 |
| C. | 1388 |
| D. | 1476 |
| Answer» E. | |
| 217. |
Convert the following octal number to binary.1048 |
| A. | 10001002 |
| B. | 1000000012 |
| C. | 101002 |
| D. | 10000012 |
| Answer» B. 1000000012 | |
| 218. |
Convert the binary number 1001.00102 to decimal. |
| A. | 90.125 |
| B. | 9.125 |
| C. | 125 |
| D. | 12.5 |
| Answer» C. 125 | |
| 219. |
Convert 52716 to binary. |
| A. | 343 |
| B. | 1101000111 |
| C. | 10100100111 |
| D. | 11100100101 |
| Answer» D. 11100100101 | |
| 220. |
Convert decimal 64 to binary. |
| A. | 1010010 |
| B. | 1000000 |
| C. | 110110 |
| D. | 1001000 |
| Answer» C. 110110 | |
| 221. |
In ASCII code, the hexadecimal sequence 53 54 55 44 45 4E 54 decodes to STUDENT. |
| A. | 1 |
| B. | |
| C. | 1 |
| D. | |
| Answer» B. | |
| 222. |
Hexadecimal letters A through F are used for decimal equivalent values from: |
| A. | 1 through 6 |
| B. | 9 through 14 |
| C. | 10 through 15 |
| D. | 11 through 17 |
| Answer» D. 11 through 17 | |
| 223. |
The voltages in digital electronics are continuously variable. |
| A. | 1 |
| B. | |
| Answer» C. | |
| 224. |
What is the decimal value of the hexadecimal number 777? |
| A. | 191 |
| B. | 1911 |
| C. | 19 |
| D. | 19111 |
| Answer» C. 19 | |
| 225. |
One hex digit is sometimes referred to as a(n): |
| A. | byte |
| B. | nibble |
| C. | grouping |
| D. | instruction |
| Answer» C. grouping | |
| 226. |
Convert 11001010001101012 to hexadecimal. |
| A. | 121035 |
| B. | CA35 |
| C. | 53AC1 |
| D. | 530121 |
| Answer» C. 53AC1 | |
| 227. |
Convert binary 111111110010 to hexadecimal. |
| A. | EE216 |
| B. | FF216 |
| C. | 2FE16 |
| D. | FD216 |
| Answer» C. 2FE16 | |
| 228. |
The octal number for binary 1101110101110110 is ________. |
| A. | 6545218 |
| B. | 5565618 |
| C. | 1566568 |
| D. | 1565668 |
| Answer» E. | |
| 229. |
Convert the following binary number to decimal. 010112 |
| A. | 11 |
| B. | 35 |
| C. | 15 |
| D. | 10 |
| Answer» B. 35 | |
| 230. |
Decode the following ASCII message. 1010011101010010101011000100101100101000001001000100000110100101000100 |
| A. | STUDYHARD |
| B. | STUDY HARD |
| C. | stydyhard |
| D. | study hard |
| Answer» C. stydyhard | |
| 231. |
The decimal number for octal 748 is ________. |
| A. | 74 |
| B. | 60 |
| C. | 22 |
| D. | 62 |
| Answer» C. 22 | |
| 232. |
Convert the following decimal number to BCD.127 |
| A. | 11100100001 |
| B. | 111010001 |
| C. | 1010111 |
| D. | 100100111 |
| Answer» E. | |
| 233. |
A complete alphanumeric code would include 26 lowercase letters, 26 uppercase letters, 10 numeric digits, 7 punctuation marks, and anywhere from ________ to ________ other characters. |
| A. | 5, 10 |
| B. | 10, 15 |
| C. | 10, 20 |
| D. | 20, 40 |
| Answer» E. | |
| 234. |
Express the decimal number –37 as an 8-bit number in sign-magnitude. |
| A. | 10100101 |
| B. | 100101 |
| C. | 11011000 |
| D. | 11010001 |
| Answer» B. 100101 | |
| 235. |
When using the repeated division by 2 method of converting from decimal to binary, one must write the first remainder as the: |
| A. | MSB |
| B. | MSB, provided the following sequence of remainders are written in descending order until the final remainder is achieved. |
| C. | LSB |
| D. | LSB, provided the final remainder is used to replace the original LSB, which is then moved to the MSB position. |
| Answer» B. MSB, provided the following sequence of remainders are written in descending order until the final remainder is achieved. | |
| 236. |
The sum of 11101 + 10111 equals ________. |
| A. | 110011 |
| B. | 100001 |
| C. | 110100 |
| D. | 100100 |
| Answer» D. 100100 | |
| 237. |
Convert the binary number 1100 to Gray code. |
| A. | 11 |
| B. | 1010 |
| C. | 1100 |
| D. | 1001 |
| Answer» C. 1100 | |
| 238. |
Convert the following decimal number to 8-bit binary.187 |
| A. | 101110112 |
| B. | 110111012 |
| C. | 101111012 |
| D. | 101111002 |
| Answer» B. 110111012 | |
| 239. |
Convert hexadecimal value 16 to decimal. |
| A. | 2210 |
| B. | 1610 |
| C. | 1010 |
| D. | 2010 |
| Answer» B. 1610 | |