MCQOPTIONS
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MCQOPTIONS
This section includes 239 Mcqs, each offering curated multiple-choice questions to sharpen your Digital Electronics knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Convert the following octal number to decimal. 17 |
| A. | 51 |
| B. | 82 |
| C. | 57 |
| D. | 15 |
| Answer» E. | |
| 2. |
Convert the following binary number to octal. 010111100 |
| A. | 172 |
| B. | 272 |
| C. | 174 |
| D. | 274 |
| Answer» E. | |
| 3. |
How many binary digits are required to count to 100? |
| A. | 7 |
| B. | 2 |
| C. | 3 |
| D. | 100 |
| Answer» B. 2 | |
| 4. |
Convert 8B3F to binary. |
| A. | 35647 |
| B. | 011010 |
| C. | 1011001111100011 |
| D. | 1000101100111111 |
| Answer» E. | |
| 5. |
Convert the following decimal number to 8-bit binary.187 |
| A. | 10111011 |
| B. | 11011101 |
| C. | 10111101 |
| D. | 10111100 |
| Answer» B. 11011101 | |
| 6. |
Convert the following binary number to decimal. 01011 |
| A. | 11 |
| B. | 35 |
| C. | 15 |
| D. | 10 |
| Answer» B. 35 | |
| 7. |
Convert the binary number 1001.0010 to decimal. |
| A. | 90.125 |
| B. | 9.125 |
| C. | 125 |
| D. | 12.5 |
| Answer» C. 125 | |
| 8. |
Decode the following ASCII message. |
| A. | STUDYHARD |
| B. | STUDY HARD |
| C. | stydyhard |
| D. | study hard |
| Answer» C. stydyhard | |
| 9. |
Convert 59.72to BCD. |
| A. | 111011 |
| B. | 01011001.01110010 |
| C. | 1110.11 |
| D. | 0101100101110010 |
| Answer» C. 1110.11 | |
| 10. |
The binary number for octal 45 is ________. |
| A. | 100010 |
| B. | 100101 |
| C. | 110101 |
| D. | 100100 |
| Answer» C. 110101 | |
| 11. |
Convert the following binary number to decimal. 10011010 |
| A. | 154 |
| B. | 155 |
| C. | 153 |
| D. | 157 |
| Answer» B. 155 | |
| 12. |
Convert the following binary number to octal. 001101011 |
| A. | 153 |
| B. | 351 |
| C. | 253 |
| D. | 352 |
| Answer» B. 351 | |
| 13. |
The decimal number for octal 74 is ________. |
| A. | 74 |
| B. | 60 |
| C. | 22 |
| D. | 62 |
| Answer» C. 22 | |
| 14. |
12= 1101 = C = 00010010 BCD |
| A. | True |
| B. | False |
| Answer» C. | |
| 15. |
Convert the following octal number to binary.76 |
| A. | 110111 |
| B. | 111110 |
| C. | 111100 |
| D. | 100111 |
| Answer» C. 111100 | |
| 16. |
3C1D= 11110000011101 |
| A. | True |
| B. | False |
| Answer» B. False | |
| 17. |
Convert the following decimal number to octal.281 |
| A. | 134 |
| B. | 431 |
| C. | 331 |
| D. | 133 |
| Answer» C. 331 | |
| 18. |
Convert the following octal number to decimal. 35 |
| A. | 71 |
| B. | 17 |
| C. | 92 |
| D. | 29 |
| Answer» E. | |
| 19. |
Resistors—usually 300 apiece—inserted between a decoder and a 7-segment display are ________. |
| A. | pull-up resistors to keep logic HIGH when the input is open |
| B. | sense resistors to enable a test of logic levels |
| C. | current limiting resistors for the 7-segment display |
| D. | surge resistors to prevent damage from power-line variations |
| Answer» D. surge resistors to prevent damage from power-line variations | |
| 20. |
Odd-parity 9E is ________ decimal. |
| A. | 30 |
| B. | 158 |
| C. | 78 |
| D. | Nothing. Parity does not check. |
| Answer» B. 158 | |
| 21. |
Convert 1100101000110101 to hexadecimal. |
| A. | 121035 |
| B. | CA35 |
| C. | 53AC1 |
| D. | 530121 |
| Answer» C. 53AC1 | |
| 22. |
15 = 1111 = F = 00010101 BCD |
| A. | True |
| B. | False |
| Answer» B. False | |
| 23. |
Convert 1731 to decimal. |
| A. | 216.4 |
| B. | 985 |
| C. | 3D9 |
| D. | 1123 |
| Answer» C. 3D9 | |
| 24. |
Convert the following decimal number to 8-bit binary.35 |
| A. | 00010010 |
| B. | 00010011 |
| C. | 00100011 |
| D. | 00100010 |
| Answer» D. 00100010 | |
| 25. |
Convert the following hexadecimal number to binary.C9 |
| A. | 10111001 |
| B. | 10111011 |
| C. | 10011100 |
| D. | 11001001 |
| Answer» E. | |
| 26. |
Convert 527 to binary. |
| A. | 011100111 |
| B. | 101010111 |
| C. | 343 |
| D. | 111010101 |
| Answer» C. 343 | |
| 27. |
Convert the following BCD number to decimal.010101101001 |
| A. | 539 |
| B. | 2551 |
| C. | 569 |
| D. | 1552 |
| Answer» D. 1552 | |
| 28. |
The binary number for F3A is ________. |
| A. | 111100111010 |
| B. | 111100111110 |
| C. | 000000111010 |
| D. | 000011000100 |
| Answer» B. 111100111110 | |
| 29. |
Convert the following decimal number to hexadecimal.125 |
| A. | 7D |
| B. | D7 |
| C. | 7C |
| D. | C7 |
| Answer» B. D7 | |
| 30. |
Convert the following decimal number to octal.39 |
| A. | 63 |
| B. | 36 |
| C. | 47 |
| D. | 74 |
| Answer» D. 74 | |
| 31. |
Convert the following hexadecimal number to decimal.B5 |
| A. | 212 |
| B. | 197 |
| C. | 165 |
| D. | 181 |
| Answer» E. | |
| 32. |
Convert 11001001 (binary) to decimal. |
| A. | 201 |
| B. | 2001 |
| C. | 20 |
| D. | 210 |
| Answer» B. 2001 | |
| 33. |
Convert the following decimal number to BCD.127 |
| A. | 011100100001 |
| B. | 111010001 |
| C. | 001010111 |
| D. | 000100100111 |
| Answer» E. | |
| 34. |
Convert 731 to decimal. |
| A. | 216.4 |
| B. | 985 |
| C. | 3D9 |
| D. | 1841 |
| Answer» E. | |
| 35. |
What decimal number does 2 represent? |
| A. | 10 |
| B. | 31 |
| C. | 25 |
| D. | 32 |
| Answer» E. | |
| 36. |
Convert the following decimal number to hexadecimal.74 |
| A. | A4 |
| B. | B4 |
| C. | 4A |
| D. | 4B |
| Answer» D. 4B | |
| 37. |
Convert the following hexadecimal number to decimal.1CF |
| A. | 463 |
| B. | 4033 |
| C. | 479 |
| D. | 4049 |
| Answer» B. 4033 | |
| 38. |
Convert the following hexadecimal number to binary. 14B |
| A. | 101101000001 |
| B. | 000101001011 |
| C. | 000101001101 |
| D. | 110101000001 |
| Answer» C. 000101001101 | |
| 39. |
Convert the following BCD number to decimal.100000000011 |
| A. | 8003 |
| B. | 803 |
| C. | 1003 |
| D. | 103 |
| Answer» C. 1003 | |
| 40. |
Convert 457 to hexadecimal. |
| A. | 711 |
| B. | 2C7 |
| C. | 811 |
| D. | 1C9 |
| Answer» E. | |
| 41. |
Convert the following octal number to binary.104 |
| A. | 001000100 |
| B. | 100000001 |
| C. | 0010100 |
| D. | 1000001 |
| Answer» B. 100000001 | |
| 42. |
3 × 10 + 7 × 10 is equal to ________. |
| A. | 3.7 |
| B. | 37 |
| C. | 10 |
| D. | 370 |
| Answer» C. 10 | |
| 43. |
Convert the following decimal number to BCD.469 |
| A. | 100101101000 |
| B. | 010001101001 |
| C. | 100001101001 |
| D. | 100101100100 |
| Answer» C. 100001101001 | |
| 44. |
Resistors—usually 300 apiece—inserted between a decoder and a 7-segment display are ________. |
| A. | pull-up resistors to keep logic HIGH when the input is open |
| B. | sense resistors to enable a test of logic levels |
| C. | current limiting resistors for the 7-segment display |
| D. | surge resistors to prevent damage from power-line variations |
| Answer» D. surge resistors to prevent damage from power-line variations | |
| 45. |
The decimal number –128 is represented in the signed 2's complement system as ________. |
| A. | 1111 1110 |
| B. | 0111 1111 |
| C. | 1000 0000 |
| D. | 1111 1111 |
| Answer» D. 1111 1111 | |
| 46. |
The hexadecimal number system consists of 16 digits, 0–15. |
| A. | True |
| B. | False |
| Answer» C. | |
| 47. |
The decimal number system consists of the digits 0–10. |
| A. | True |
| B. | False |
| Answer» C. | |
| 48. |
Express the decimal number –37 as an 8-bit number in sign-magnitude. |
| A. | 10100101 |
| B. | 00100101 |
| C. | 11011000 |
| D. | 11010001 |
| Answer» B. 00100101 | |
| 49. |
The difference of 111 – 001 equals ________. |
| A. | 100 |
| B. | 111 |
| C. | 001 |
| D. | 110 |
| Answer» E. | |
| 50. |
3 × 101 + 7 × 100 is equal to ________. |
| A. | 3.7 |
| B. | 37 |
| C. | 10 |
| D. | 370 |
| Answer» C. 10 | |