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MCQOPTIONS
This section includes 194 Mcqs, each offering curated multiple-choice questions to sharpen your Digital Electronics knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Perform subtraction on each of the following binary numbers by taking the two's-complement of the number being subtracted and then adding it to the first number.01001 0110000011 00111 |
| A. | 01100 10011 |
| B. | 00110 00101 |
| C. | 10110 10101 |
| D. | 00111 00100 |
| Answer» C. 10110 10101 | |
| 2. |
Multiply the following binary numbers. |
| A. | 0001 1110 0100 1101 0101 1011 |
| B. | 0001 1110 0100 1100 0101 1010 |
| C. | 0001 1110 0100 1101 0101 1010 |
| D. | 0001 1101 0100 1101 0101 1010 |
| Answer» D. 0001 1101 0100 1101 0101 1010 | |
| 3. |
The representation of –1 in eight-bit two's-complement notation is 11110111. |
| A. | True |
| B. | False |
| Answer» C. | |
| 4. |
The binary subtraction 0 – 1 = isdifference = 1borrow = 0 |
| A. | True |
| B. | False |
| Answer» C. | |
| 5. |
11101000 is the 2's-complement representation of –24. |
| A. | True |
| B. | False |
| Answer» C. | |
| 6. |
The solution to the BCD problem 0101 + 0100 is 00001001. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 7. |
The inputs of a full adder are labeled , , and . |
| A. | True |
| B. | False |
| Answer» B. False | |
| 8. |
If [A] = 10 and [B] = 01, then [A] [b] = ________. |
| A. | [00] |
| B. | 00 |
| C. | 11 |
| D. | [11] |
| Answer» D. [11] | |
| 9. |
–9 represented in eight-bit two's-complement notation is ________. |
| A. | 11110111 |
| B. | 11111001 |
| C. | 11110110 |
| D. | 01111101 |
| Answer» B. 11111001 | |
| 10. |
The contents of the A register after is ________. |
| A. | 0000 |
| B. | 0001 |
| C. | 1001 |
| D. | 1010 |
| Answer» E. | |
| 11. |
Convert each of the decimal numbers to two's-complement form and perform the addition in binary. |
| A. | 0001 0100 0000 0101 |
| B. | 0000 0110 0001 1001 |
| C. | 0000 0110 0000 0101 |
| D. | 1111 0110 1111 0101 |
| Answer» D. 1111 0110 1111 0101 | |
| 12. |
Add the following binary numbers. |
| A. | 0111 1011 0100 0001 0101 1011 |
| B. | 0111 1011 0101 1001 0101 1011 |
| C. | 0111 0111 0101 1001 0101 1011 |
| D. | 0111 0111 0100 0001 0101 1011 |
| Answer» C. 0111 0111 0101 1001 0101 1011 | |
| 13. |
The BCD addition of 9 and 7 will give initial code groups of 1001 + 0111. Addition of these groups generates a carry to the next higher position. The correct solution to this problem would be to: |
| A. | ignore the lowest order code group because 0000 is a valid code group and prefix the carry with three zeros |
| B. | add 0110 to both code groups to validate the carry from the lowest order code group |
| C. | disregard the carry and add 0110 to the lowest order code group |
| D. | add 0110 to the lowest order code group because a carry was generated and then prefix the carry with three zeros |
| Answer» E. | |
| 14. |
Subtract the following binary numbers. |
| A. | 0011 0100 0110 1010 1000 0110 |
| B. | 0011 0101 0110 1011 1000 0111 |
| C. | 0011 0101 0110 1010 1000 0111 |
| D. | 0011 0101 0110 1010 1000 0110 |
| Answer» C. 0011 0101 0110 1010 1000 0111 | |
| 15. |
Subtract the following hexadecimal numbers. |
| A. | 22 18 CB |
| B. | 22 17 CB |
| C. | 22 19 CB |
| D. | 22 18 CC |
| Answer» B. 22 17 CB | |
| 16. |
Find the 2's complement of –110110. |
| A. | 110100 |
| B. | 101010 |
| C. | 001001 |
| D. | 001010 |
| Answer» E. | |
| 17. |
Add the following BCD numbers. |
| A. | 0000 1011 0000 1111 0001 0001 |
| B. | 0001 0001 0001 0101 0001 0001 |
| C. | 0000 1011 0000 1111 0001 0111 |
| D. | 0001 0001 0001 0101 0001 0111 |
| Answer» E. | |
| 18. |
Add the following hexadecimal numbers. |
| A. | 60 3C 116 |
| B. | 62 3C 118 |
| C. | 61 3C 117 |
| D. | 61 3D 117 |
| Answer» D. 61 3D 117 | |
| 19. |
How many BCD adders would be required to add the numbers 973 + 39? |
| A. | 3 |
| B. | 4 |
| C. | 5 |
| D. | 6 |
| Answer» B. 4 | |
| 20. |
Convert each of the signed decimal numbers to an 8-bit signed binary number (two's-complement).+7 –3 –12 |
| A. | 0000 0111 1111 1101 1111 0100 |
| B. | 1000 0111 0111 1101 0111 0100 |
| C. | 0000 0111 0000 0011 0000 1100 |
| D. | 0000 0111 1000 0011 1000 1100 |
| Answer» B. 1000 0111 0111 1101 0111 0100 | |
| 21. |
Perform the following hex subtraction: ACE – 999 = |
| A. | 235 |
| B. | 135 |
| C. | 035 |
| D. | 335 |
| Answer» C. 035 | |
| 22. |
Determine the two's-complement of each binary number.00110 00011 11101 |
| A. | 11001 11100 00010 |
| B. | 00111 00010 00010 |
| C. | 00110 00011 11101 |
| D. | 11010 11101 00011 |
| Answer» E. | |
| 23. |
The decimal value for E is: |
| A. | 12 |
| B. | 13 |
| C. | 14 |
| D. | 15 |
| Answer» D. 15 | |
| 24. |
Add the following hex numbers: 0110 + 10010 |
| A. | 10120 |
| B. | 10020 |
| C. | 11120 |
| D. | 00120 |
| Answer» B. 10020 | |
| 25. |
Convert each of the following signed binary numbers (two's-complement) to a signed decimal number.00000101 11111100 11111000 |
| A. | –5 +4 +8 |
| B. | +5 –4 –8 |
| C. | –5 +252 +248 |
| D. | +5 –252 –248 |
| Answer» C. –5 +252 +248 | |
| 26. |
Add the following BCD numbers. 0110 0111 1001 0101 1000 1000 |
| A. | 0000 1011 0000 1111 0001 0001 |
| B. | 0001 0001 0001 0101 0001 0001 |
| C. | 0000 1011 0000 1111 0001 0111 |
| D. | 0001 0001 0001 0101 0001 0111 |
| Answer» E. | |
| 27. |
Subtract the following hexadecimal numbers. 47 34 FA –25 –1C –2F |
| A. | 22 18 CB |
| B. | 22 17 CB |
| C. | 22 19 CB |
| D. | 22 18 CC |
| Answer» B. 22 17 CB | |
| 28. |
Add the following hexadecimal numbers. 3C 14 3B +25 +28 +DC |
| A. | 60 3C 116 |
| B. | 62 3C 118 |
| C. | 61 3C 117 |
| D. | 61 3D 117 |
| Answer» D. 61 3D 117 | |
| 29. |
Perform the following hex subtraction: ACE16 – 99916 = |
| A. | 23516 |
| B. | 13516 |
| C. | 03516 |
| D. | 33516 |
| Answer» C. 03516 | |
| 30. |
Perform subtraction on each of the following binary numbers by taking the two's-complement of the number being subtracted and then adding it to the first number.01001 0110000011 00111 |
| A. | 01100 10011 |
| B. | 00110 00101 |
| C. | 10110 10101 |
| D. | 00111 00100 |
| Answer» C. 10110 10101 | |
| 31. |
Convert each of the following signed binary numbers (two's-complement) to a signed decimal number.00000101 11111100 11111000 |
| A. | –5 +4 +8 |
| B. | +5 –4 –8 |
| C. | –5 +252 +248 |
| D. | +5 –252 –248 |
| Answer» C. –5 +252 +248 | |
| 32. |
Convert each of the decimal numbers to two's-complement form and perform the addition in binary. +13 –10 add –7 add +15 |
| A. | 0001 0100 0000 0101 |
| B. | 0000 0110 0001 1001 |
| C. | 0000 0110 0000 0101 |
| D. | 1111 0110 1111 0101 |
| Answer» D. 1111 0110 1111 0101 | |
| 33. |
Convert each of the signed decimal numbers to an 8-bit signed binary number (two's-complement).+7 –3 –12 |
| A. | 0000 0111 1111 1101 1111 0100 |
| B. | 1000 0111 0111 1101 0111 0100 |
| C. | 0000 0111 0000 0011 0000 1100 |
| D. | 0000 0111 1000 0011 1000 1100 |
| Answer» B. 1000 0111 0111 1101 0111 0100 | |
| 34. |
Determine the two's-complement of each binary number.00110 00011 11101 |
| A. | 11001 11100 00010 |
| B. | 00111 00010 00010 |
| C. | 00110 00011 11101 |
| D. | 11010 11101 00011 |
| Answer» E. | |
| 35. |
Solving –11 + (–2) will yield which two's-complement answer? |
| A. | 1110 1101 |
| B. | 1111 1001 |
| C. | 1111 0011 |
| D. | 1110 1001 |
| Answer» D. 1110 1001 | |
| 36. |
Subtract the following binary numbers. 0101 1000 1010 0011 1101 1110 –0010 0011 –0011 1000 –0101 0111 |
| A. | 0011 0100 0110 1010 1000 0110 |
| B. | 0011 0101 0110 1011 1000 0111 |
| C. | 0011 0101 0110 1010 1000 0111 |
| D. | 0011 0101 0110 1010 1000 0110 |
| Answer» C. 0011 0101 0110 1010 1000 0111 | |
| 37. |
Multiply the following binary numbers. 1010 1011 1001 ×0011 ×0111 ×1010 |
| A. | 0001 1110 0100 1101 0101 1011 |
| B. | 0001 1110 0100 1100 0101 1010 |
| C. | 0001 1110 0100 1101 0101 1010 |
| D. | 0001 1101 0100 1101 0101 1010 |
| Answer» D. 0001 1101 0100 1101 0101 1010 | |
| 38. |
Add the following binary numbers. 0010 0110 0011 1011 0011 1100 +0101 0101 +0001 1110 +0001 1111 |
| A. | 0111 1011 0100 0001 0101 1011 |
| B. | 0111 1011 0101 1001 0101 1011 |
| C. | 0111 0111 0101 1001 0101 1011 |
| D. | 0111 0111 0100 0001 0101 1011 |
| Answer» C. 0111 0111 0101 1001 0101 1011 | |
| 39. |
The carry-out of a full adder is ________. |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» E. | |
| 40. |
FC48 – AB91 = ________. |
| A. | 5B77 |
| B. | 5267 |
| C. | 50B7 |
| D. | 5077 |
| Answer» D. 5077 | |
| 41. |
–910 represented in eight-bit two's-complement notation is ________. |
| A. | 11110111 |
| B. | 11111001 |
| C. | 11110110 |
| D. | 01111101 |
| Answer» B. 11111001 | |
| 42. |
Solve this binary problem: 01011000 ÷ 00001011 = ________. |
| A. | 1010 |
| B. | 0110 |
| C. | 1000 |
| D. | 1110 |
| Answer» D. 1110 | |
| 43. |
Solve this binary problem: 1001 × 1100 = ________. |
| A. | 01110001 |
| B. | 01111000 |
| C. | 01101100 |
| D. | 01101110 |
| Answer» D. 01101110 | |
| 44. |
The binary subtraction 1 – 1 = ________. |
| A. | difference = 0borrow = 0 |
| B. | difference = 1borrow = 0 |
| C. | difference = 1borrow = 1 |
| D. | difference = 0borrow = 1 |
| Answer» B. difference = 1borrow = 0 | |
| 45. |
10011100 in two's-complement notation has a decimal value of –100. |
| A. | True |
| B. | False |
| Answer» C. | |
| 46. |
The representation of –110 in eight-bit two's-complement notation is 11110111. |
| A. | True |
| B. | False |
| Answer» C. | |
| 47. |
The range of negative numbers when using an eight-bit two's-complement system is –1 to –128. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 48. |
The solution to the binary problem 00110110 – 00011111 is 00011000. |
| A. | True |
| B. | False |
| Answer» C. | |
| 49. |
The solution to the binary problem 1011 – 0111 is 1000. |
| A. | True |
| B. | False |
| Answer» C. | |
| 50. |
The solution to the binary problem 1011 × 0110 is 01100110. |
| A. | True |
| B. | False |
| Answer» C. | |