MCQOPTIONS
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| 1. |
Design a circuit using a 74121 to convert a 33-kHz, 30% duty cycle waveform to a 33-kHz, 60% duty cycle waveform. |
| A. | Rint = 2 k, Cext = 0.012 nF |
| B. | Rint = 2 k, Cext = 0.012 F |
| C. | Rint = 4 k, Cext = 0.012 nF |
| D. | Rint = 4 k, Cext = 0.012 F |
| Answer» C. Rint¬†=¬†4 k, Cext¬†=¬†0.012 nF | |