

MCQOPTIONS
This section includes 2291 Mcqs, each offering curated multiple-choice questions to sharpen your Engineering knowledge and support exam preparation. Choose a topic below to get started.
351. |
Which of the following is an example of a counter with a truncated modulus? |
A. | 8 |
B. | 13 |
C. | 16 |
D. | 32 |
Answer» C. 16 | |
352. |
Why can a synchronous counter operate at a higher frequency than a ripple counter? |
A. | The flip-flops change one after the other. |
B. | The flip-flops change at the same time. |
C. | A synchronous counter cannot operate at higher frequencies. |
D. | A ripple counter is faster. |
Answer» C. A synchronous counter cannot operate at higher frequencies. | |
353. |
Which of the following is a type of shift register counter? |
A. | Decade |
B. | Binary |
C. | Ring |
D. | BCD |
Answer» D. BCD | |
354. |
Which of the following groups of logic devices would be the minimum required for a MOD-64 synchronous counter? |
A. | Five flip-flops, three AND gates |
B. | Seven flip-flops, five AND gates |
C. | Four flip-flops, ten AND gates |
D. | Six flip-flops, four AND gates |
Answer» E. | |
355. |
How many data bits can be stored in the register shown below? |
A. | 5 |
B. | 32 |
C. | 31 |
D. | 4 |
Answer» B. 32 | |
356. |
The designation |
A. | up count is active-HIGH, the down count is active-LOW |
B. | up count is active-LOW, the down count is active-HIGH |
C. | up and down counts are both active-LOW |
D. | up and down counts are both active-HIGH |
Answer» B. up count is active-LOW, the down count is active-HIGH | |
357. |
For a one-shot application, how can HDL code be used to make a circuit respond once to each positive transition on its trigger input? |
A. | By using a counter |
B. | By using an active clock |
C. | By using an immediate reload |
D. | By using edge trapping |
Answer» E. | |
358. |
A counter with a modulus of 16 acts as a ________. |
A. | divide-by-8 counter |
B. | divide-by-16 counter |
C. | divide-by-32 counter |
D. | divide-by-64 counter |
Answer» C. divide-by-32 counter | |
359. |
What is the difference between a 7490 and a 7493? |
A. | 7490 is a MOD-10, 7493 is a MOD-16 |
B. | 7490 is a MOD-16, 7493 is a MOD-10 |
C. | 7490 is a MOD-12, 7493 is a MOD-16 |
D. | 7490 is a MOD-10, 7493 is a MOD-12 |
Answer» B. 7490 is a MOD-16, 7493 is a MOD-10 | |
360. |
What function does the CTR DIV 8 circuit given below perform? |
A. | It divides the clock frequency down to match the frequency of the serial data in. |
B. | The divide-by-8 counter is triggered by the control flip-flop and clock, which then allows the data output register to begin storing the input data. Once all eight data bits are stored in the data output register, the data output register and the divide-by-8 counter trigger the one-shot. The one-shot then begins the process all over again. |
C. | The divide-by-8 counter is used to verify that the parity bit is attached to the input data string. |
D. | It keeps track of the eight data bits, triggering the transfer of the data through the output register and the one-shot, which then resets the control flip-flop and divide-by-8 counter. |
Answer» E. | |
361. |
Synchronous (parallel) counters eliminate the delay problems encountered with asynchronous (ripple) counters because the: |
A. | input clock pulses are applied only to the first and last stages. |
B. | input clock pulses are applied only to the last stage. |
C. | input clock pulses are applied simultaneously to each stage. |
D. | input clock pulses are not used to activate any of the counter stages. |
Answer» D. input clock pulses are not used to activate any of the counter stages. | |
362. |
A 4-bit up/down binary counter is in the DOWN mode and in the 1100 state. To what state does the counter go on the next clock pulse? |
A. | 1101 |
B. | 1011 |
C. | 1111 |
D. | 0000 |
Answer» C. 1111 | |
363. |
A 4-bit ripple counter consists of flip-flops, which each have a propagation delay from clock to Q output of 15 ns. For the counter to recycle from 1111 to 0000, it takes a total of ________. |
A. | 15 ns |
B. | 30 ns |
C. | 45 ns |
D. | 60 ns |
Answer» E. | |
364. |
The terminal count of a 3-bit binary counter in the DOWN mode is ________. |
A. | 000 |
B. | 111 |
C. | 101 |
D. | 010 |
Answer» B. 111 | |
365. |
The hexadecimal equivalent of 15,536 is ________. |
A. | 3CB0 |
B. | 3C66 |
C. | 63C0 |
D. | 6300 |
Answer» B. 3C66 | |
366. |
In a VHDL retriggerable edge-triggered one-shot, which condition will not exist when a clock edge occurs? |
A. | A trigger edge has occurred and we must load the counter. |
B. | The counter is zero and we need to keep it at zero. |
C. | The shift register is reset. |
D. | The counter is not zero and we need to count down by one. |
Answer» D. The counter is not zero and we need to count down by one. | |
367. |
Which of the following is an invalid output state for an 8421 BCD counter? |
A. | 1110 |
B. | 0000 |
C. | 0010 |
D. | 0001 |
Answer» B. 0000 | |
368. |
How many different states does a 3-bit asynchronous counter have? |
A. | 2 |
B. | 4 |
C. | 8 |
D. | 16 |
Answer» D. 16 | |
369. |
How many flip-flops are required to construct a decade counter? |
A. | 10 |
B. | 8 |
C. | 5 |
D. | 4 |
Answer» E. | |
370. |
The terminal count of a typical modulus-10 binary counter is ________. |
A. | 0000 |
B. | 1010 |
C. | 1001 |
D. | 1111 |
Answer» D. 1111 | |
371. |
A seven-segment, common-anode LED display is designed for: |
A. | all cathodes to be wired together |
B. | one common LED |
C. | a HIGH to turn off each segment |
D. | disorientation of segment modules |
Answer» D. disorientation of segment modules | |
372. |
To operate correctly, starting a ring counter requires: |
A. | clearing one flip-flop and presetting all the others. |
B. | clearing all the flip-flops. |
C. | presetting one flip-flop and clearing all the others. |
D. | presetting all the flip-flops. |
Answer» D. presetting all the flip-flops. | |
373. |
When two counters are cascaded, the overall MOD number is equal to the ________ of their individual MOD numbers. |
A. | product |
B. | sum |
C. | log |
D. | reciprocal |
Answer» B. sum | |
374. |
A MOD-12 and a MOD-10 counter are cascaded. Determine the output frequency if the input clock frequency is 60 MHz. |
A. | 500 kHz |
B. | 1,500 kHz |
C. | 6 MHz |
D. | 5 MHz |
Answer» B. 1,500 kHz | |
375. |
How many natural states will there be in a 4-bit ripple counter? |
A. | 4 |
B. | 8 |
C. | 16 |
D. | 32 |
Answer» D. 32 | |
376. |
A ripple counter's speed is limited by the propagation delay of: |
A. | each flip-flop |
B. | all flip-flops and gates |
C. | the flip-flops only with gates |
D. | only circuit gates |
Answer» B. all flip-flops and gates | |
377. |
Referring to the given figure, at which point is the serial data transferred to the parallel output? |
A. | W |
B. | X |
C. | Y |
D. | Z |
Answer» E. | |
378. |
How many AND gates would be required to completely decode ALL the states of a MOD-64 counter, and how many inputs must each AND gate have? |
A. | 128 gates, 6 inputs to each gate |
B. | 64 gates, 5 inputs to each gate |
C. | 64 gates, 6 inputs to each gate |
D. | 128 gates, 5 inputs to each gate |
Answer» D. 128 gates, 5 inputs to each gate | |
379. |
A 4-bit counter has a maximum modulus of ________. |
A. | 3 |
B. | 6 |
C. | 8 |
D. | 16 |
Answer» E. | |
380. |
What function will the counter shown below be performing during period "B" on the timing diagram? |
A. | Counting up |
B. | Counting down |
C. | Inhibited |
D. | Loading |
Answer» B. Counting down | |
381. |
Three cascaded decade counters will divide the input frequency by ________. |
A. | 10 |
B. | 20 |
C. | 100 |
D. | 1,000 |
Answer» E. | |
382. |
One of the major drawbacks to the use of asynchronous counters is: |
A. | low-frequency applications are limited because of internal propagation delays |
B. | high-frequency applications are limited because of internal propagation delays |
C. | asynchronous counters do not have major drawbacks and are suitable for use in high- and low-frequency counting applications |
D. | asynchronous counters do not have propagation delays and this limits their use in high-frequency applications |
Answer» C. asynchronous counters do not have major drawbacks and are suitable for use in high- and low-frequency counting applications | |
383. |
The final output of a modulus-8 counter occurs one time for every ________. |
A. | 8 clock pulses |
B. | 16 clock pulses |
C. | 24 clock pulses |
D. | 32 clock pulses |
Answer» B. 16 clock pulses | |
384. |
Once an up-/down-counter begins its count sequence, it cannot be reversed. |
A. | True |
B. | False |
Answer» C. | |
385. |
Three cascaded modulus-5 counters have an overall modulus of ________. |
A. | 5 |
B. | 25 |
C. | 125 |
D. | 500 |
Answer» D. 500 | |
386. |
An asynchronous 4-bit binary down counter changes from count 2 to count 3. How many transitional states are required? |
A. | None |
B. | One |
C. | Two |
D. | Fifteen |
Answer» E. | |
387. |
A 5-bit asynchronous binary counter is made up of five flip-flops, each with a 12 ns propagation delay. The total propagation delay (tp(tot)) is ________. |
A. | 12 ms |
B. | 24 ns |
C. | 48 ns |
D. | 60 ns |
Answer» E. | |
388. |
A four-channel scope is used to check the counter in the figure given below. Are the displayed waveforms correct? |
A. | Yes |
B. | No |
Answer» C. | |
389. |
One application of a digital multiplexer is to facilitate: |
A. | data generation |
B. | serial-to-parallel conversion |
C. | parity checking |
D. | data selector |
Answer» E. | |
390. |
How can the active condition (HIGH or LOW) or the decoder output be determined from the logic symbol? |
A. | A bubble indicates active-HIGH. |
B. | A bubble indicates active-LOW. |
C. | A square indicates active-HIGH. |
D. | A square indicates active-LOW. |
Answer» C. A square indicates active-HIGH. | |
391. |
If two inputs are active on a priority encoder, which will be coded on the output? |
A. | the higher value |
B. | the lower value |
C. | neither of the inputs |
D. | both of the inputs |
Answer» B. the lower value | |
392. |
A circuit that responds to a specific set of signals to produce a related digital signal output is called a(n): |
A. | BCD matrix |
B. | display driver |
C. | encoder |
D. | decoder |
Answer» D. decoder | |
393. |
How many 74184 BCD-to-binary converters would be required to convert two complete BCD digits to a binary number? |
A. | 8 |
B. | 4 |
C. | 2 |
D. | 1 |
Answer» D. 1 | |
394. |
How many select lines would be required for an 8-line-to-1-line multiplexer? |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 8 |
Answer» C. 4 | |
395. |
A binary code that progresses such that only one bit changes between two successive codes is: |
A. | nine's-complement code |
B. | 8421 code |
C. | excess-3 code |
D. | Gray code |
Answer» E. | |
396. |
Which of the following is not a weighted value positional numbering system: |
A. | hexadecimal |
B. | binary-coded decimal |
C. | binary |
D. | octal |
Answer» C. binary | |
397. |
In a BCD-to-seven-segment converter, why must a code converter be utilized? |
A. | to convert the 4-bit BCD into 7-bit code |
B. | to convert the 4-bit BCD into 10-bit code |
C. | to convert the 4-bit BCD into Gray code |
D. | No conversion is necessary. |
Answer» B. to convert the 4-bit BCD into 10-bit code | |
398. |
A microcontroller differs from a microprocessor in that it has several ________ ports and ________ built into its architecture, making it better suited for ________ applications. |
A. | communication, PROMs, control |
B. | parallel, logic gates, processing |
C. | input/output, memory, control |
D. | data, memory, decoding |
Answer» D. data, memory, decoding | |
399. |
A truth table with output columns numbered 0 15 may be for which type of decoder IC? |
A. | hexadecimal 1-of-16 |
B. | dual octal outputs |
C. | binary-to-hexadecimal |
D. | hexadecimal-to-binary |
Answer» B. dual octal outputs | |
400. |
Why is the Gray code more practical to use when coding the position of a rotating shaft? |
A. | All digits change between counts. |
B. | Two digits change between counts. |
C. | Only one digit changes between counts. |
Answer» D. | |