

MCQOPTIONS
This section includes 2291 Mcqs, each offering curated multiple-choice questions to sharpen your Engineering knowledge and support exam preparation. Choose a topic below to get started.
1. |
How many gates would be required to implement the following Boolean expression after simplification? XY + X(X + Z) + Y(X + Z) |
A. | 1 |
B. | 2 |
C. | 4 |
D. | 5 |
Answer» C. 4 | |
2. |
What is the primary motivation for using Boolean algebra to simplify logic expressions? |
A. | It may make it easier to understand the overall function of the circuit. |
B. | It may reduce the number of gates. |
C. | It may reduce the number of inputs required. |
D. | all of the above |
Answer» E. | |
3. |
An AND gate with schematic "bubbles" on its inputs performs the same function as a(n)________ gate. |
A. | NOT |
B. | OR |
C. | NOR |
D. | NAND |
Answer» D. NAND | |
4. |
Applying DeMorgan's theorem to the expression |
A. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0060a.gif"> |
B. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0060b.gif"> |
C. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0060c.gif"> |
D. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0060d.gif"> |
Answer» E. | |
5. |
Applying DeMorgan's theorem to the expression |
A. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0050a.gif"> |
B. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0050b.gif"> |
C. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0050c.gif"> |
D. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0050d.gif"> |
Answer» B. <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0050b.gif"> | |
6. |
Which of the following is an important feature of the sum-of-products (SOP) form of expression? |
A. | All logic circuits are reduced to nothing more than simple AND and OR gates. |
B. | The delay times are greatly reduced over other forms. |
C. | No signal must pass through more than two gates, not including inverters. |
D. | The maximum number of gates that any signal must pass through is reduced by a factor of two. |
Answer» D. The maximum number of gates that any signal must pass through is reduced by a factor of two. | |
7. |
Mapping the SOP expression |
A. | (A) |
B. | (B) |
C. | (C) |
D. | (D) |
Answer» C. (C) | |
8. |
Derive the Boolean expression for the logic circuit shown below: |
A. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0080a.gif"> |
B. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0080b.gif"> |
C. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0080c.gif"> |
D. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0080d.gif"> |
Answer» D. <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0080d.gif"> | |
9. |
Which is the correct logic function for this PAL diagram? |
A. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_00250a.gif"> |
B. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_00250b.gif"> |
C. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_00250c.gif"> |
D. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_00250d.gif"> |
Answer» D. <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_00250d.gif"> | |
10. |
For the SOP expression |
A. | zero |
B. | 1 |
C. | 4 |
D. | 5 |
Answer» D. 5 | |
11. |
Mapping the standard SOP expression |
A. | (A) |
B. | (B) |
C. | (C) |
D. | (D) |
Answer» C. (C) | |
12. |
The Boolean expression |
A. | NAND |
B. | NOR |
C. | AND |
D. | OR |
Answer» B. NOR | |
13. |
Applying the distributive law to the expression |
A. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0030a.gif"> |
B. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0030b.gif"> |
C. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0030c.gif"> |
D. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0030d.gif"> |
Answer» E. | |
14. |
AC + ABC = AC |
A. | True |
B. | False |
Answer» B. False | |
15. |
A Karnaugh map is a systematic way of reducing which type of expression? |
A. | product-of-sums |
B. | exclusive NOR |
C. | sum-of-products |
D. | those with overbars |
Answer» D. those with overbars | |
16. |
How many gates would be required to implement the following Boolean expression before simplification? XY + X(X + Z) + Y(X + Z) |
A. | 1 |
B. | 2 |
C. | 4 |
D. | 5 |
Answer» E. | |
17. |
Which Boolean algebra property allows us to group operands in an expression in any order without affecting the results of the operation [for example, A + B = B + A]? |
A. | associative |
B. | commutative |
C. | Boolean |
D. | distributive |
Answer» C. Boolean | |
18. |
For the SOP expression |
A. | 1 |
B. | 2 |
C. | 3 |
D. | 5 |
Answer» D. 5 | |
19. |
Applying DeMorgan's theorem to the expression |
A. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0040a.gif"> |
B. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0040b.gif"> |
C. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0040c.gif"> |
D. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0040d.gif"> |
Answer» B. <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0040b.gif"> | |
20. |
A truth table for the SOP expression |
A. | 1 |
B. | 2 |
C. | 4 |
D. | 8 |
Answer» E. | |
21. |
Determine the values of A, B, C, and D that make the product term |
A. | A = 0, B = 1, C = 0, D = 1 |
B. | A = 0, B = 0, C = 0, D = 1 |
C. | A = 1, B = 1, C = 1, D = 1 |
D. | A = 0, B = 0, C = 1, D = 0 |
Answer» B. A = 0, B = 0, C = 0, D = 1 | |
22. |
The systematic reduction of logic circuits is accomplished by: |
A. | using Boolean algebra |
B. | symbolic reduction |
C. | TTL logic |
D. | using a truth table |
Answer» B. symbolic reduction | |
23. |
Which output expression might indicate a product-of-sums circuit construction? |
A. | <img src="/_files/images/digital-electronics/basic-digital-electronics/mca5_1023a1.gif"> |
B. | <img src="/_files/images/digital-electronics/basic-digital-electronics/mca5_1023b1.gif"> |
C. | <img src="/_files/images/digital-electronics/basic-digital-electronics/mca5_1023c1.gif"> |
D. | <img src="/_files/images/digital-electronics/basic-digital-electronics/mca5_1023d1.gif"> |
Answer» E. | |
24. |
Occasionally, a particular logic expression will be of no consequence in the operation of a circuit, such as a BCD-to-decimal converter. These result in ________terms in the K-map and can be treated as either ________ or ________, in order to ________ the resulting term. |
A. | don't care, 1s, 0s, simplify |
B. | spurious, ANDs, ORs, eliminate |
C. | duplicate, 1s, 0s, verify |
D. | spurious, 1s, 0s, simplify |
Answer» B. spurious, ANDs, ORs, eliminate | |
25. |
The NAND or NOR gates are referred to as "universal" gates because either: |
A. | can be found in almost all digital circuits |
B. | can be used to build all the other types of gates |
C. | are used in all countries of the world |
D. | were the first gates to be integrated |
Answer» C. are used in all countries of the world | |
26. |
Converting the Boolean expression LM + M(NO + PQ) to SOP form, we get ________. |
A. | LM + MNOPQ |
B. | L + MNO + MPQ |
C. | LM + M + NO + MPQ |
D. | LM + MNO + MPQ |
Answer» E. | |
27. |
One of De Morgan's theorems states that |
A. | a NOR and an AND gate with inverted inputs |
B. | a NAND and an OR gate with inverted inputs |
C. | an AND and a NOR gate with inverted inputs |
D. | a NOR and a NAND gate with inverted inputs |
Answer» B. a NAND and an OR gate with inverted inputs | |
28. |
Applying DeMorgan's theorem to the expression |
A. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0070a.gif"> |
B. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0070b.gif"> |
C. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0070c.gif"> |
D. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0070d.gif"> |
Answer» B. <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0070b.gif"> | |
29. |
The output of an AND gate with three inputs, A, B, and C, is HIGH when ________. |
A. | A = 1, B = 1, C = 0 |
B. | A = 0, B = 0, C = 0 |
C. | A = 1, B = 1, C = 1 |
D. | A = 1, B = 0, C = 1 |
Answer» D. A = 1, B = 0, C = 1 | |
30. |
Convert the following SOP expression to an equivalent POS expression. |
A. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0160a.gif"> |
B. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0160b.gif"> |
C. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0160c.gif"> |
D. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0160d.gif"> |
Answer» C. <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0160c.gif"> | |
31. |
Determine the values of A, B, C, and D that make the sum term |
A. | A = 1, B = 0, C = 0, D = 0 |
B. | A = 1, B = 0, C = 1, D = 0 |
C. | A = 0, B = 1, C = 0, D = 0 |
D. | A = 1, B = 0, C = 1, D = 1 |
Answer» C. A = 0, B = 1, C = 0, D = 0 | |
32. |
Derive the Boolean expression for the logic circuit shown below: |
A. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0090a.gif"> |
B. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0090b.gif"> |
C. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0090c.gif"> |
D. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0090d.gif"> |
Answer» B. <img src="/_files/images/digital-electronics/digital-fundamentals/mca4_0090b.gif"> | |
33. |
What is the difference between a 7400 and a 7411 IC? |
A. | 7400 has two four-input NAND gates; 7411 has three three-input AND gates |
B. | 7400 has four two-input NAND gates; 7411 has three three-input AND gates |
C. | 7400 has two four-input AND gates; 7411 has three three-input NAND gates |
D. | 7400 has four two-input AND gates; 7411 has three three-input NAND gates |
Answer» C. 7400 has two four-input AND gates; 7411 has three three-input NAND gates | |
34. |
If the output of a three-input AND gate must be a logic LOW, what must the condition of the inputs be? |
A. | All inputs must be LOW. |
B. | All inputs must be HIGH. |
C. | At least one input must be LOW. |
D. | At least one input must be HIGH. |
Answer» D. At least one input must be HIGH. | |
35. |
What are the pin numbers of the outputs of the gates in a 7432 IC? |
A. | 3, 6, 10, and 13 |
B. | 1, 4, 10, and 13 |
C. | 3, 6, 8, and 11 |
D. | 1, 4, 8, and 11 |
Answer» D. 1, 4, 8, and 11 | |
36. |
If the input to a NOT gate is A and the output is X, then ________. |
A. | X = A |
B. | <img src="/_files/images/digital-electronics/digital-fundamentals/mca3_0040b.gif"> |
C. | X = 0 |
D. | none of the above |
Answer» C. X = 0 | |
37. |
If a 3-input AND gate has eight input possibilities, how many of those possibilities will result in a HIGH output? |
A. | 1 |
B. | 2 |
C. | 7 |
D. | 8 |
Answer» B. 2 | |
38. |
The Boolean expression for a 3-input AND gate is ________. |
A. | X = AB |
B. | X = ABC |
C. | X = A + B + C |
D. | X = AB + C |
Answer» C. X = A + B + C | |
39. |
What does the small bubble on the output of the NAND gate logic symbol mean? |
A. | open collector output |
B. | tristate |
C. | The output is inverted. |
D. | none of the above |
Answer» D. none of the above | |
40. |
The output of an exclusive-OR gate is HIGH if ________. |
A. | all inputs are LOW |
B. | all inputs are HIGH |
C. | the inputs are unequal |
D. | none of the above |
Answer» D. none of the above | |
41. |
A CMOS IC operating from a 3-volt supply will consume ________. |
A. | less power than a TTL IC |
B. | more power than a TTL IC |
C. | the same power as a TTL IC |
D. | no power at all |
Answer» B. more power than a TTL IC | |
42. |
TTL operates from a ________. |
A. | 9-volt supply |
B. | 3-volt supply |
C. | 12-volt supply |
D. | 5-volt supply |
Answer» E. | |
43. |
The power dissipation, PD, of a logic gate is the product of the ________. |
A. | dc supply voltage and the peak current |
B. | dc supply voltage and the average supply current |
C. | ac supply voltage and the peak current |
D. | ac supply voltage and the average supply current |
Answer» C. ac supply voltage and the peak current | |
44. |
Which of the following choices meets the minimum requirement needed to create specialized waveforms that are used in digital control and sequencing circuits? |
A. | basic gates, a clock oscillator, and a repetitive waveform generator |
B. | basic gates, a clock oscillator, and a Johnson shift counter |
C. | basic gates, a clock oscillator, and a DeMorgan pulse generator |
D. | basic gates, a clock oscillator, a repetitive waveform generator, and a Johnson shift counter |
Answer» B. basic gates, a clock oscillator, and a Johnson shift counter | |
45. |
The expression W(X + YZ) can be converted to SOP form by applying which law? |
A. | associative law |
B. | commutative law |
C. | distributive law |
D. | none of the above |
Answer» D. none of the above | |
46. |
The output of a NOR gate is HIGH if ________. |
A. | all inputs are HIGH |
B. | any input is HIGH |
C. | any input is LOW |
D. | all inputs are LOW |
Answer» E. | |
47. |
The switching speed of CMOS is now ________. |
A. | competitive with TTL |
B. | three times that of TTL |
C. | slower than TTL |
D. | twice that of TTL |
Answer» B. three times that of TTL | |
48. |
How many pins does the 4049 IC have? |
A. | 14 |
B. | 16 |
C. | 18 |
D. | 20 |
Answer» C. 18 | |
49. |
The commutative law of addition and multiplication indicates that: |
A. | we can group variables in an AND or in an OR any way we want |
B. | an expression can be expanded by multiplying term by term just the same as in ordinary algebra |
C. | the way we OR or AND two variables is unimportant because the result is the same |
D. | the factoring of Boolean expressions requires the multiplication of product terms that contain like variables |
Answer» D. the factoring of Boolean expressions requires the multiplication of product terms that contain like variables | |
50. |
The output of an OR gate with three inputs, A, B, and C, is LOW when ________. |
A. | A = 0, B = 0, C = 0 |
B. | A = 0, B = 0, C = 1 |
C. | A = 0, B = 1, C = 1 |
D. | all of the above |
Answer» B. A = 0, B = 0, C = 1 | |