MCQOPTIONS
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MCQOPTIONS
This section includes 166 Mcqs, each offering curated multiple-choice questions to sharpen your Electrical Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 101. |
The constant M-circle represented by the equation x^2+2.25x+y^2=-1.25 has the value of M equal to: |
| A. | 1 |
| B. | 2 |
| C. | 3 |
| D. | 4 |
| Answer» D. 4 | |
| 102. |
A system has poles at 0.01 Hz, 1 Hz and 80Hz, zeroes at 5Hz, 100Hz and 200Hz. The approximate phase of the system response at 20 Hz is : |
| A. | -90° |
| B. | 0° c) 90° |
| C. | d) -180° |
| Answer» B. 0° c) 90° | |
| 103. |
In polar plots, what does each and every point represent w.r.t magnitude and angle? |
| A. | scalar |
| B. | vector |
| C. | phasor |
| D. | differentiator |
| Answer» D. differentiator | |
| 104. |
If the system is represented by G(s) H(s) = k (s+7) / s (s +3) (s + 2), what would be its magnitude at ω = ∞? |
| A. | 0 |
| B. | ∞ c) 7/10 |
| C. | d) 21 |
| Answer» B. ∞ c) 7/10 | |
| 105. |
In polar plots, if a pole is added at the origin, what would be the value of the magnitude at Ω = 0? |
| A. | zero |
| B. | infinity |
| C. | unity |
| D. | unpredictable |
| Answer» C. unity | |
| 106. |
Consider the system represented by the equation given below. What would be the total phase value at ω = 0? |
| A. | -90° |
| B. | -180° |
| C. | -270° |
| D. | -360° |
| Answer» D. -360° | |
| 107. |
According to Nyquist stability criterion, where should be the position of all zeros of q(s) corresponding to s-plane? |
| A. | on left half |
| B. | at the center |
| C. | on right half |
| D. | random |
| Answer» B. at the center | |
| 108. |
If a Nyquist plot of G (jω) H (jω) for a closed loop system passes through (-2, j0) point in GH plane, what would be the value of gain margin of the system in dB? |
| A. | 0 db |
| B. | 2.0201 db |
| C. | 4 db |
| D. | 6.0205 db |
| Answer» E. | |
| 109. |
Which principle specifies the relationship between enclosure of poles & zeros by s- plane contour and the encirclement of origin by q(s) plane contour? |
| A. | argument |
| B. | agreement |
| C. | assessment |
| D. | assortment |
| Answer» B. agreement | |
| 110. |
For Nyquist contour, the size of radius is |
| A. | 25 |
| B. | 0 |
| C. | 1 |
| D. | ∞ |
| Answer» E. | |
| 111. |
For a stable closed loop system, the gain at phase crossover frequency should always be: |
| A. | < 20 db |
| B. | < 6 db |
| C. | > 6 db |
| D. | > 0 db |
| Answer» E. | |
| 112. |
Nichol’s chart: |
| A. | constant gain and constant phase shift loci of the closed-loop system. |
| B. | plot of loop gain with the variation in frequency |
| C. | circles of constant gain for the closed loop transfer function |
| D. | circles of constant phase shift for the closed loop transfer function |
| Answer» C. circles of constant gain for the closed loop transfer function | |
| 113. |
Constant N-loci: |
| A. | constant gain and constant phase shift loci of the closed-loop system. |
| B. | plot of loop gain with the variation in frequency |
| C. | circles of constant gain for the closed loop transfer function |
| D. | circles of constant phase shift for the closed loop transfer function |
| Answer» D. circles of constant phase shift for the closed loop transfer function | |
| 114. |
Constant M- loci: |
| A. | constant gain and constant phase shift loci of the closed-loop system. |
| B. | plot of loop gain with the variation in frequency |
| C. | circles of constant gain for the closed loop transfer function |
| D. | circles of constant phase shift for the closed loop transfer function |
| Answer» E. | |
| 115. |
Which one of the following methods can determine the closed loop system resonance frequency operation? |
| A. | root locus method |
| B. | nyquist method |
| C. | bode plot |
| D. | m and n circle |
| Answer» E. | |
| 116. |
Scientist Nyquist have contribution in: |
| A. | asymptotic plots |
| B. | polar plots |
| C. | root locus technique |
| D. | constant m and n circle |
| Answer» C. root locus technique | |
| 117. |
Scientist Evans have contribution in : |
| A. | asymptotic plots |
| B. | polar plots |
| C. | root locus technique |
| D. | constant m and n circle |
| Answer» D. constant m and n circle | |
| 118. |
Scientist Bode have contribution in : |
| A. | asymptotic plots |
| B. | polar plots |
| C. | root locus technique |
| D. | constant m and n circle |
| Answer» B. polar plots | |
| 119. |
If the gain of the open loop system is doubled, the gain of the system is : |
| A. | not affected |
| B. | doubled |
| C. | halved |
| D. | one fourth of the original value |
| Answer» B. doubled | |
| 120. |
Negative exponential term in the equation of the transfer function causes the transportation lag. |
| A. | true |
| B. | false |
| Answer» B. false | |
| 121. |
Rate compensation : |
| A. | increases bandwidth |
| B. | attenuation |
| C. | increases damping factor |
| D. | second order |
| Answer» D. second order | |
| 122. |
Lag-lead compensation is a: |
| A. | increases bandwidth |
| B. | attenuation |
| C. | increases damping factor |
| D. | second order |
| Answer» E. | |
| 123. |
Lead compensation leads to: |
| A. | increases bandwidth |
| B. | attenuation |
| C. | increases damping factor |
| D. | second order |
| Answer» B. attenuation | |
| 124. |
Derivative error compensation: |
| A. | improvement in transient response |
| B. | reduction in steady state error |
| C. | reduction is settling time |
| D. | increase in damping constant |
| Answer» E. | |
| 125. |
Derivative output compensation: |
| A. | improvement in transient response |
| B. | reduction in steady state error |
| C. | reduction is settling time |
| D. | increase in damping constant |
| Answer» D. increase in damping constant | |
| 126. |
Addition of zero at origin: |
| A. | improvement in transient response |
| B. | reduction in steady state error |
| C. | reduction is settling time |
| D. | increase in damping constant |
| Answer» B. reduction in steady state error | |
| 127. |
Lag compensation leads to: |
| A. | increases bandwidth |
| B. | attenuation |
| C. | increases damping factor |
| D. | second order |
| Answer» C. increases damping factor | |
| 128. |
Systems of type higher than 2 are not employed in practice. |
| A. | true |
| B. | false |
| Answer» B. false | |
| 129. |
A particular control system yielded a steady state error of 0.20 for unit step input. A unit integrator is cascaded to this system and unit ramp input is applied to this modified system. What is the value of steady- state error for this modified system? |
| A. | 0.10 |
| B. | 0.15 |
| C. | 0.20 |
| D. | 0.25 |
| Answer» E. | |
| 130. |
A ramp input applied to a unity feedback system results in 5% steady state error. The type number and zero frequency gain of the system are respectively |
| A. | 1 and 20 |
| B. | 0 and 20 |
| C. | 0 and 1/20 |
| D. | 1 and 1/20 |
| Answer» B. 0 and 20 | |
| 131. |
Consider the unity feedback system with open loop transfer function the minimum value of the steady state error to a ramp input r(t) = 6tu(t) is OLTF = K/s(s+1)(s+2) |
| A. | 1 |
| B. | 2 |
| C. | 3 |
| D. | 4 |
| Answer» C. 3 | |
| 132. |
The system in originally critically damped if the gain is doubled the system will be : |
| A. | remains same |
| B. | overdamped |
| C. | under damped |
| D. | undamped |
| Answer» D. undamped | |
| 133. |
The steady state error for a unity feedback system for the input r(t) = Rt^2/2 to the system G(s) = K(s+2)/s(s3+7s2+12s) is |
| A. | 0 |
| B. | 6r/k |
| C. | ∞ |
| D. | 3r/k |
| Answer» C. ∞ | |
| 134. |
For non-unity feedback system, the error is calculated with respect to the reference signal. |
| A. | true |
| B. | false |
| Answer» C. | |
| 135. |
On which of the following factors does the sensitivity of a closed loop system to gain changes and load disturbances depend? |
| A. | frequency |
| B. | loop gain |
| C. | forward gain |
| D. | all of the mentioned |
| Answer» E. | |
| 136. |
A control system with excessive noise, is likely to suffer from |
| A. | saturation in amplifying stages |
| B. | loss of gain |
| C. | vibrations |
| D. | oscillations |
| Answer» B. loss of gain | |
| 137. |
The output of a feedback control system must be a function of |
| A. | reference and output |
| B. | reference and input |
| C. | input and feedback signal |
| D. | output and feedback signal |
| Answer» E. | |
| 138. |
Regenerative feedback implies feedback with |
| A. | oscillations |
| B. | step input |
| C. | negative sign |
| D. | positive sign |
| Answer» E. | |
| 139. |
The relationship between an input and output variable of a signal flow graph is given by the net gain between the input and output node is known as the overall |
| A. | overall gain of the system |
| B. | stability |
| C. | bandwidth |
| D. | speed |
| Answer» B. stability | |
| 140. |
Loop which do not possess any common node are said to be                        loops. |
| A. | forward gain |
| B. | touching loops |
| C. | non touching loops |
| D. | feedback gain |
| Answer» D. feedback gain | |
| 141. |
A signal flow graph is the graphical representation of the relationships between the variables of set linear algebraic equations. |
| A. | true |
| B. | false |
| Answer» B. false | |
| 142. |
Which of the following is not the feature of modern control system? |
| A. | quick response |
| B. | accuracy |
| C. | correct power level |
| D. | no oscillation |
| Answer» E. | |
| 143. |
Primary purpose of using Feedback is : |
| A. | to reduce the sensitivity of the system to parameter variations. |
| B. | to increase the bandwidth of the system |
| C. | to reduce the noise and distortion of the system |
| D. | to increase stability of the system |
| Answer» B. to increase the bandwidth of the system | |
| 144. |
The output of the feedback control system must be a function of: |
| A. | reference input |
| B. | reference output |
| C. | output and feedback signal |
| D. | input and feedback signal |
| Answer» E. | |
| 145. |
Determine the sensitivity of the overall transfer function for the system shown in the figure below, at w=1 rad/sec with respect to the feedback path transfer function. |
| A. | 1.11 |
| B. | -1.11 |
| C. | 2.22 |
| D. | -2.22 |
| Answer» C. 2.22 | |
| 146. |
For the gain feedback system, does not affect the system output if KG is : |
| A. | small |
| B. | negative |
| C. | one |
| D. | very large |
| Answer» E. | |
| 147. |
Open loop system is                        stable than closed loop system |
| A. | more |
| B. | less |
| C. | inclined |
| D. | exponential |
| Answer» B. less | |
| 148. |
Insertion of negative feedback in control system affects: |
| A. | the transient response to vanish uniformly |
| B. | the transient response to decay very fast |
| C. | no change in transient response |
| D. | the transient response decays at slow rate |
| Answer» C. no change in transient response | |
| 149. |
As compared to the closed loop system, an open loop system is |
| A. | more stable but less accurate |
| B. | less stable as well as less accurate |
| C. | more stable as well as more accurate |
| D. | less stable but more accurate |
| Answer» B. less stable as well as less accurate | |
| 150. |
Which of the following will not decrease as a result of introduction of negative feedback? |
| A. | instability |
| B. | bandwidth |
| C. | overall gain |
| D. | distortion |
| Answer» C. overall gain | |