MCQOPTIONS
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| 1. |
Let ϕ be the phase angle between the line current and line voltage, and α be the load angle. The per phase mechanical power developed by a synchronous motor is: |
| A. | \(\frac{{{E_b}V}}{{{X_S}}}\sin \phi \) |
| B. | \(\frac{{{E_b}V}}{{{X_S}}}\cos \alpha \) |
| C. | \(\frac{{{E_b}V}}{{{X_s}}}\cos \phi \) |
| D. | \(\frac{{{E_b}V}}{{{X_S}}}\sin \alpha \) |
| Answer» E. | |