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This section includes 20 Mcqs, each offering curated multiple-choice questions to sharpen your Waste Water Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Lamella Clarifier works on which principle? |
| A. | Cocurrent settling |
| B. | Countercurrent settling |
| C. | Cross flow settling |
| D. | Hindered settling |
| Answer» C. Cross flow settling | |
| 2. |
When will the particles settle in a tank which is subjected to countercurrent settling? |
| A. | V<(VƟ – V sinƟ)/v cosƟ |
| B. | V>= VƟ/v cosƟ |
| C. | V>= (VƟ – V sinƟ)/v cosƟ |
| D. | V<VƟ/v cosƟ |
| Answer» D. V<VƟ/v cosƟ | |
| 3. |
How is the length of the surface calculated in case of countercurrent settling? |
| A. | Lp=wVƟ/ v cos Ɵ |
| B. | Lp=(VƟ – V sinƟ)/ v cos Ɵ |
| C. | Lp=w(VƟ – V sinƟ) |
| D. | Lp=w(VƟ – V sinƟ)/ v cos Ɵ |
| Answer» E. | |
| 4. |
HOW_IS_THE_LENGTH_OF_THE_SURFACE_CALCULATED_IN_CASE_OF_COUNTERCURRENT_SETTLING??$ |
| A. | L<sub>p</sub>=wV<sub>Ɵ</sub>/ v cos Ɵ |
| B. | L<sub>p</sub>=(V<sub>Ɵ</sub> – V sinƟ)/ v cos Ɵ |
| C. | L<sub>p</sub>=w(V<sub>Ɵ</sub> – V sinƟ) |
| D. | L<sub>p</sub>=w(V<sub>Ɵ</sub> – V sinƟ)/ v cos Ɵ |
| Answer» E. | |
| 5. |
Lamella Clarifier works on which principle?$ |
| A. | Cocurrent settling |
| B. | Countercurrent settling |
| C. | Cross flow settling |
| D. | Hindered settling |
| Answer» C. Cross flow settling | |
| 6. |
When will the particles settle in a tank which is subjected to countercurrent settling?$ |
| A. | V<(V<sub>Ɵ</sub> – V sinƟ)/v cosƟ |
| B. | V>= V<sub>Ɵ</sub>/v cosƟ |
| C. | V>= (V<sub>Ɵ</sub> – V sinƟ)/v cosƟ |
| D. | V<V<sub>Ɵ</sub>/v cosƟ |
| Answer» D. V<V<sub>‚Äö√†√ú‚àö¬∫</sub>/v cos‚Äö√†√ú‚àö¬∫ | |
| 7. |
How is the height of the sludge calculated in a sludge drying bed? |
| A. | H<sub>t</sub>-H<sub>x</sub>=(H<sub>2</sub>-H<sub>x</sub>)ei<sup>t2</sup> |
| B. | H<sub>t</sub>=(H<sub>2</sub>-H<sub>x</sub>)ei<sup>t2</sup> |
| C. | H<sub>t</sub>-H<sub>x</sub>=(H<sub>2</sub>)ei<sup>t2</sup> |
| D. | H<sub>t</sub>-H<sub>x</sub>=(H<sub>x</sub>)ei<sup>t2</sup> |
| Answer» B. H<sub>t</sub>=(H<sub>2</sub>-H<sub>x</sub>)ei<sup>t2</sup> | |
| 8. |
What is the major assumption made when solid flux method is used to find the area of the sedimentation basin? |
| A. | Settling basin is not operating at a steady state |
| B. | Settling basin is operating at an adiabatic state |
| C. | Settling basin is operating at a steady state |
| D. | Settling basin is operating at an isobaric state |
| Answer» D. Settling basin is operating at an isobaric state | |
| 9. |
How is the critical concentration of sludge thickener tank calculated? |
| A. | H<sub>u</sub>= C<sub>0</sub><sup>2</sup> H<sub>0</sub>/ Cu |
| B. | H<sub>u</sub>= C<sub>0</sub> H<sub>0</sub>/ Cu<sub>2</sub> |
| C. | H<sub>u</sub>= Cu H<sub>0</sub>/ C<sub>o</sub>S |
| D. | H<sub>u</sub>= C<sub>0</sub> H<sub>0</sub>/ Cu |
| Answer» E. | |
| 10. |
How is the area of a sludge thickening tank calculated? |
| A. | A=2QT<sub>a</sub>/H<sub>0</sub> |
| B. | A=QT<sub>a</sub>/H<sub>0</sub> |
| C. | A=QT<sub>a</sub>/2H<sub>0</sub> |
| D. | A=QT<sub>a</sub>/H<sub>0</sub><sup>2</sup> |
| Answer» C. A=QT<sub>a</sub>/2H<sub>0</sub> | |
| 11. |
How is the length of the surface of a settling tank determined in case of cross- flow settling? |
| A. | L<sub>p</sub>=wVƟ/ v cos Ɵ |
| B. | L<sub>p</sub><wVƟ/ v cos Ɵ |
| C. | L<sub>p</sub>= (VƟ – V sinƟ)/ v cos Ɵ |
| D. | L<sub>p</sub><(VƟ – V sinƟ)/ v cos Ɵ |
| Answer» B. L<sub>p</sub><wV‚Äö√†√ú‚àö¬∫/ v cos ‚Äö√†√ú‚àö¬∫ | |
| 12. |
In countercurrent settling how is the solid suspension fed? |
| A. | From the bottom |
| B. | From the sides |
| C. | From the top |
| D. | Flow is up the plates |
| Answer» D. Flow is up the plates | |
| 13. |
Which mode of settling are tube settlers based on? |
| A. | Counter current settling |
| B. | Cocurrent settling |
| C. | Cross flow settling |
| D. | Flocculant settling |
| Answer» B. Cocurrent settling | |
| 14. |
What is the product obtained when a coagulant is mixed with wastewater? |
| A. | Sediments |
| B. | Acid |
| C. | Floc |
| D. | Grit |
| Answer» B. Acid | |
| 15. |
What is type IV settling also called as? |
| A. | Zone settling |
| B. | Hindered settling |
| C. | Compression settling |
| D. | Expansion settling |
| Answer» D. Expansion settling | |
| 16. |
Type III settling is called as hindered settling. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 17. |
How many types of settling are present? |
| A. | 2 |
| B. | 3 |
| C. | 4 |
| D. | 6 |
| Answer» D. 6 | |
| 18. |
Which is the primary force acting on the Settleable particles? |
| A. | Gravitational force |
| B. | Centrifugal force |
| C. | Mechanical force |
| D. | Radial force |
| Answer» B. Centrifugal force | |
| 19. |
Settling tanks are also called as sedimentation tanks. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 20. |
_______ is a process by which particles settle to the bottom of the liquid. |
| A. | Settling |
| B. | Coagulation |
| C. | Sedimentation |
| D. | Filtration |
| Answer» B. Coagulation | |