Explore topic-wise MCQs in Genetic Engineering.

This section includes 129 Mcqs, each offering curated multiple-choice questions to sharpen your Genetic Engineering knowledge and support exam preparation. Choose a topic below to get started.

51.

The ends created by use of DNase have unique single stranded sequences.

A. True
B. False
C. May be True or False
D. Can't say
Answer» C. May be True or False
52.

Another method of DNA recovery is termed as freeze-squeeze. The correct statement for it is?

A. The slice containing DNA is cut and frozen into liquid oxygen
B. Freezing doesn’t have any effect on the DNA structure
C. After freezing centrifugation is carried out through glass wool plug
D. The substance used for centrifugation allows the gel to pass through but the liquid is retained
Answer» D. The substance used for centrifugation allows the gel to pass through but the liquid is retained
53.

Which of the following enzyme is said as reverse transcriptase?

A. DNA dependent DNA polymerase
B. RNA dependent RNA polymerase
C. RNA dependent DNA polymerase
D. DNA dependent RNA polymerase
Answer» D. DNA dependent RNA polymerase
54.

Ligation reaction can be both intramolecular and intermolecular in nature.

A. True
B. False
C. May be True or False
D. Can't say
Answer» B. False
55.

Bal31 is also an enzyme which is used. Which of the following statements hold true in its context?

A. It is having only 3’-5’ exonuclease activity and no endonuclease activity
B. It is having only an endonuclease activity
C. It is having 5’-3’ exonuclease activity
D. It leads to shortening from both the ends
Answer» E.
56.

Viral infection can also be used to take up the DNA by the cells.

A. True
B. False
C. May be True or False
D. Can't say
Answer» B. False
57.

Mechanism of ligation for both T4 DNA ligase and E. coli DNA ligase makes use of Adenosine Monophosphate (AMP). Which of the steps is involved in the ligation mechanism?

A. AMP is added to the 5’ phosphate of one of the DNA molecule
B. It leads to the liberation of pyrophosphate from NAD and nicotinamide mononucleotide from ATP
C. The AMP is further displaced by an electrophilic attack
D. The AMP is further displaced by nucleophilic attack by 3’ hydroxyl of the same DNA molecule
Answer» B. It leads to the liberation of pyrophosphate from NAD and nicotinamide mononucleotide from ATP
58.

What is the mode of action of exonuclease III?

A. Exonuclease III acts on single stranded DNA in 3’-5’ direction
B. Exonuclease III acts on double stranded DNA in 5’-3’ direction
C. Exonuclease III acts on single stranded DNA in 5’-3’ direction
D. Exonuclease III acts on double stranded DNA in 3’-5’ direction
Answer» E.
59.

Which of the following components settles at the bottom?

A. RNA
B. Proteins
C. Nicked DNA
D. Supercoiled DNA
Answer» B. Proteins
60.

Which of the following statements is correct with respect to a unit of an enzyme?

A. One unit of enzyme is defined as the amount of enzyme required to digest 1miligram of standard DNA in a specific time of 1hr and under given temperature conditions
B. The amount of enzyme required doesn’t vary with the number of sites present in the DNA
C. If more number of sites is there in the DNA more units of enzyme are required in comparison to same amount of DNA with fewer sites
D. The amount of enzyme required for digestion of DNA with less number of sites is more than that of more number of sites in the same amount of DNA
Answer» D. The amount of enzyme required for digestion of DNA with less number of sites is more than that of more number of sites in the same amount of DNA
61.

Phosphatases refer to __________

A. the enzymes which add phosphate group at the end of the DNA molecule in the place of hydroxyl group
B. the enzymes which hydrolytically remove phosphate group from the DNA molecules and replace them with hydroxyl group
C. the enzymes responsible for removal of phosphate group from the DNA molecules and replace them with hydrogen
D. the enzymes responsible for replacing hydrogen in the DNA molecules with the phosphate group
Answer» C. the enzymes responsible for removal of phosphate group from the DNA molecules and replace them with hydrogen
62.

Many bacterial species are having a natural ability to take up the exogenous DNA material. Which of the statement is not correct in regard to it?

A. This ability is termed as competence
B. It is not limited to particular growth phases
C. The bacteria may develop new biochemical abilities under special conditions such as nutrient deprivation
D. Induction of specific set of bacterial proteins may take place
Answer» C. The bacteria may develop new biochemical abilities under special conditions such as nutrient deprivation
63.

Why reverse transcriptase enzymes are having comparatively high error rates than other polymerases?

A. Because they are not having 3’-5’ proofreading exonucleolytic activity
B. Because they are not having 5’-3’ proofreading exonucleolytic activity
C. Because they are having slow rates of exonucleolytic activity
D. It is difficult to synthesize DNA from RNA
Answer» B. Because they are not having 5’-3’ proofreading exonucleolytic activity
64.

The disadvantage in the approach based on using PCR is that there is no permanent record until some of the bacterial cells are preserved.

A. True
B. False
C. May be True or False
D. Can't say
Answer» B. False
65.

Enzyme commonly used for carrying out ligation reaction is ____________

A. Transferase
B. Reverse transciptase
C. Ligase
D. DNase
Answer» D. DNase
66.

If blunt ended ligations are to be carried out. Which of the following enzymes can be used?

A. E. coli DNA ligase
B. T4 DNA ligase
C. Both of these enzymes act equally in carrying out blunt ended ligations
D. None of them is able to carry out blunt ended ligations
Answer» C. Both of these enzymes act equally in carrying out blunt ended ligations
67.

At times, a specific fragment of the molecules of DNA which are analyzed needs to be separated. One of the methods is digesting the gels simply. Which of the following statement is not correct in with respect to it?

A. The gelling temperature has an important role to play
B. For higher gelling temperatures, digestion of DNA is done via the addition of agarase or some chaotropic agents
C. For lower gelling temperatures, simply slicing out of target DNA is done which is followed by melting
D. The DNA can be extracted via the addition of sodium or any positively charged group
Answer» E.
68.

After cleaving the sequence, the nature of the ends created by the type II endonuclease is __________

A. The ends created are always single stranded
B. The ends created are always double stranded
C. Either the ends are single stranded or they are double stranded
D. One end is single stranded and one end is double stranded
Answer» D. One end is single stranded and one end is double stranded
69.

Introduction of DNA molecules into the recipient organism is termed as ____________

A. transformation
B. translation
C. transduction
D. transcription
Answer» B. translation
70.

Type II cuts the sequence in the following way __________

A. Within the recognition sequence
B. At 100-1000 nucleotides away from the recognition sequence
C. At 27-30 nucleotides away from the recognition sequence
D. It cuts randomly
Answer» B. At 100-1000 nucleotides away from the recognition sequence
71.

Methylase is useful in cloning experiments.

A. True
B. False
C. May be True or False
D. Can't say
Answer» B. False
72.

The extent of deletions can be manipulated by controlling which of them?

A. Time of incubation only
B. Amount of nuclease added
C. They both have a role to play in the extent of the deletion
D. The amount of deletion which can be carried out for a particular amount of DNA is fixed regardless of the amount of nuclease and incubation time
Answer» D. The amount of deletion which can be carried out for a particular amount of DNA is fixed regardless of the amount of nuclease and incubation time
73.

Ligation enzymes are used for ligating newly synthesized okazaki fragments. What holds true for okazaki fragments?

A. Okazaki fragments are short fragments of DNA formed on the leading strand
B. Okazaki fragments are large fragments of DNA formed on the lagging strand
C. Okazaki fragments are short fragments of DNA formed on the lagging strand
D. Okazaki fragments are large fragments of DNA formed on the leading strand
Answer» D. Okazaki fragments are large fragments of DNA formed on the leading strand
74.

The recognition sequence for BamHI is 5’ G|GATCC 3’. The ‘|’ represents the cutting site. What can be inferred about the ends from it?

A. The ends created are double stranded
B. The single stranded end is 5’ in nature
C. The single stranded end is 3’ in nature
D. To decide about the nature of the ends more information is needed
Answer» C. The single stranded end is 3’ in nature
75.

If the molecules to be separated are larger than the size for conventional electrophoresis, which type of gels can be used?

A. Wedge gels
B. Buffer-gradient gels
C. Pulse field gels
D. Varying the amount of agarose will carry out the separation
Answer» D. Varying the amount of agarose will carry out the separation
76.

Which of the following is the correct nomenclature of a restriction enzyme obtained from the first activity of strain R of Escherichia coli?

A. EcoR1
B. EscRI
C. EcorI
D. EcoRI
Answer» E.
77.

How can gradient in the field strength be obtained?

A. It can be obtained via varying the amount of current, keeping the resistance constant
B. It can be obtained via varying the amount of resistance, keeping the current constant
C. Both can be varied, but resistance is having more effect
D. Buffer-gradient gels can be used with decreasing concentration of buffer at the bottom
Answer» C. Both can be varied, but resistance is having more effect
78.

Which of the statements is correct for non uniform separation obtained other than the conventional one?

A. It can be obtained via applying strong field towards the cathode
B. It can be obtained via applying the same field on both the sides
C. The separation is greater on the side of stronger field
D. Its is greater towards the weaker field
Answer» D. Its is greater towards the weaker field
79.

Chemical transformation refers to the methods which use chemicals in order to carry out transformation. Which of the following statements is true with respect to it?

A. Chemical transformation decreases the efficiency of transformation as compared to natural transformation
B. Ice cold calcium solution followed by heat shock is responsible for affecting the efficiency of DNA uptake
C. The mechanism responsible for it named as ‘the heat shock model’
D. Other complex mixtures such as those containing Manganese and hexamine cobalt can’t be used to affect the efficiency
Answer» C. The mechanism responsible for it named as ‘the heat shock model’
80.

Which of the following statement is correct for the method of separation of large molecules?

A. The large DNA molecules can pass through the matrix in any direction, not necessarily in the direction parallel to the movement
B. The separation can be carried out if the fields are at right angles to each other
C. The time of pulse should be less than that of the reorientation time
D. Separation is not of the megabase level
Answer» C. The time of pulse should be less than that of the reorientation time
81.

The particle gun method consists of which of the following steps?

A. The DNA of interest is absorbed onto microprojectile beads
B. These beads are often made of aluminium
C. The explosion in a gun propels a macroprojectile forward which in turn propels microprojectile beads
D. The macroprojectiles and microprojectiles both cross the perforated plate and hit the target tissue behind it
Answer» D. The macroprojectiles and microprojectiles both cross the perforated plate and hit the target tissue behind it
82.

Gel electrophoresis separates nucleic acid molecules based on ____________

A. charge on molecules
B. size of the molecules
C. nature of the molecules i.e. whether DNA or RNA
D. chemical properties of the nucleic acids
Answer» C. nature of the molecules i.e. whether DNA or RNA
83.

The ligation reaction is more efficient in which case?

A. Blunt end ligation
B. Sticky end ligation
C. Both have the same efficiency
D. Depends on the reaction conditions
Answer» C. Both have the same efficiency
84.

How many approaches are there which can be used for exonucleolytic activity in double stranded DNA molecules?

A. 1
B. 2
C. 3
D. 4
Answer» C. 3
85.

Basic classification of polymerases includes how many types?

A. 2
B. 3
C. 4
D. 5
Answer» E.
86.

The greatest separation is obtained in which portion of the gel?

A. Lower portion where the anode is
B. Lower portion where the cathode is
C. The separation is uniform all over
D. It varies according to the quantity of the size of the molecules to be separated
Answer» B. Lower portion where the cathode is
87.

The restriction endonuclease is having a defence mechanism in the bacterial system against foreign DNA such as viruses. But how it is able to protect its own DNA?

A. By methylation of bacterial DNA by restriction enzyme
B. By methylation of foreign DNA by restriction enzyme
C. By phosphorylation of bacterial DNA by restriction enzyme
D. By phosphorylation of foreign DNA by restriction enzyme
Answer» B. By methylation of foreign DNA by restriction enzyme
88.

Amplification of specific region can be done by using primers for specific regions. If the PCR product is ______ and is in sufficient quantity, then sequence can be determined ________

A. non-specific, directly
B. non-specific, indirectly or directly
C. specific, directly
D. specific, indirectly
Answer» D. specific, indirectly
89.

If the known DNA sequences are immobilized onto a solid support, it is called ____________

A. Blot
B. Microarray
C. DNA plate
D. Column
Answer» C. DNA plate
90.

Isoschizomers are defined as ___________

A. enzymes having same recognition sequence and always cutting at the same site
B. enzymes having same recognition sequence and always cutting at different site
C. enzymes having different recognition site and cutting at the same site
D. enzymes having same recognition site and they may or may not cut at the same site
Answer» E.
91.

How can phosphatase activity terminated prior to a ligation reaction?

A. By heating
B. By cooling
C. By creating vibrations
D. By alternatively cooling and heating
Answer» B. By cooling
92.

If the amount of agarose added is more, the molecular under analysis should have the following characteristic:

A. small size
B. large size
C. size has no relation with the amount of agarose
D. the amount of molecules under analysis matters
Answer» B. large size
93.

Force is defined as mass per unit acceleration. As the number of phosphate molecules increases, the charge also increases which increases the force required. The acceleration is dependent on the size of the molecules.

A. True
B. False
C. May be True or False
D. Can't say
Answer» C. May be True or False
94.

If a ligation reaction is being carried out and recircularization is observed, which type of reaction is being carried out?

A. Intramolecular
B. Intermolecular
C. Both observe recircularization equally
D. Recirculation is not possible in any of the cases
Answer» B. Intermolecular
95.

Oligonucleotides are synthesized chemically. Which of the following step is involved in oligonucleotide synthesis?

A. Nucleotide addition is done by adding many nucleotides at a time
B. The coupling reaction should involve water
C. Only one type of nucleotides can be added at a time
D. Unblocking of the reactive groups leads to addition of nucleotides
Answer» E.
96.

How is the size of molecules under analysis measured?

A. By measuring the distance moved through a ruler
B. By measuring the amount of visualising dye used
C. By running a standard molecule, whose size is known in parallel
D. There is no exact criterion for doing so
Answer» D. There is no exact criterion for doing so
97.

Chromosomal or genomic DNA is separated by ____________

A. Sedimentation
B. Dissolution in water
C. Centrifugation
D. Distillation
Answer» D. Distillation
98.

Which of the following statement is correct regarding partial digestion?

A. It is defined as the conditions where all the sites in the DNA sequence are not recognized
B. The number of fragments created by partial digestion are same as that of complete digestion
C. It is not useful in representation of genomic library
D. Exactly half of the sites in the DNA are recognized
Answer» B. The number of fragments created by partial digestion are same as that of complete digestion
99.

How many approaches are there in order to clone the complete genome?

A. 1
B. 2
C. 3
D. 4
Answer» C. 3
100.

Which of the following is correct with respect to caesium chloride centrifugation?

A. Caesium is light in weight
B. The dissolution of caesium and nucleic acids leads to the formation of gradients
C. According to the amount of supercoiling and A+T content, the DNA settles
D. Nicked DNA settles below than supercoiled DNA
Answer» C. According to the amount of supercoiling and A+T content, the DNA settles