1274 + Mcqs in Analytical Geometry in SRMJEEE Page 26 McqOptions

1251.	Solve equation x2 - 3x
A.	x = -3
B.	x = 0, x = -3
C.	x = 3
D.	x = 0, x = 3
Answer» E.

Discussion

1252.	Solve equation x2 + 3x
A.	x = -3
B.	x = 0, x = -3
C.	x = 3
D.	x = 0, x = 3
Answer» C. x = 3

Discussion

1253.	Solve equation x2 + 6x - 7 = 0
A.	x = -6, x = -1
B.	x = -6, x = 1
C.	x = 6, x = -1
D.	x = 6, x = 1
Answer» E.

Discussion

1254.	Solve equation 4x2 + 36x + 81
A.	x = 9⁄2, x = 9⁄2
B.	x = -9⁄2, x = 9⁄2
C.	x = -9⁄2, x = -9⁄2
D.	None of the above
Answer» D. None of the above

Discussion

1255.	Logarithm of (a3)(b2)?c is:
A.	3(logarithm of a) - 2(logarithm of b) - (1⁄2)(logarithm of c)
B.	3(logarithm of a) + 2(logarithm of b) + (1⁄2)(logarithm of c)
C.	3(logarithm of a) + 2(logarithm of b) + (logarithm of c)
D.	3(logarithm of a) - 2(logarithm of b) - (logarithm of c)
Answer» C. 3(logarithm of a) + 2(logarithm of b) + (logarithm of c)

Discussion

1256.	Logarithm of 'x' to power 'y' is equal to:
A.	y × (logarithm of x)
B.	x × (logarithm of y)
C.	(logarithm of x) × (logarithm of y)
D.	None of the above
Answer» B. x × (logarithm of y)

Discussion

1257.	Logarithm to base 'x' of 'y&frasl;z' is equal to:
A.	(logarithm to the base x of y) × (logarithm to the base x of z)
B.	(logarithm to the base x of y) + (logarithm to the base x of z)
C.	(logarithm to the base x of y) - (logarithm to the base x of z)
D.	None of the above
Answer» D. None of the above

Discussion

1258.	Logarithm to base 'x' of 'yz' is equal to:
A.	(logarithm to the base x of y) × (logarithm to the base x of z)
B.	(logarithm to the base x of y) + (logarithm to the base x of z)
C.	(logarithm to the base x of y) - (logarithm to the base x of z)
D.	None of the above
Answer» C. (logarithm to the base x of y) - (logarithm to the base x of z)

Discussion

1259.	Logarithm to base 1&frasl;2 of 16 is:
A.	4
B.	5
C.	-5
D.	-4
Answer» E.

Discussion

1260.	In logarithmic form of '2&sup6; = 64':
A.	base = 6, log = 2, number = 64
B.	base = 2, log = 6, number = 64
C.	base = 2, log = 64, number = 6
D.	base = 64, log = 2, number = 6
Answer» C. base = 2, log = 64, number = 6

Discussion

1261.	Index form of 'logarithm to base x of y is z' is:
A.	x^z = y
B.	x^y = z
C.	y^z = x
D.	z^y = x
Answer» B. x^y = z

Discussion

1262.	Logarithm to base 10 of 1000 is:
A.	1
B.	2
C.	3
D.	4
Answer» D. 4

Discussion

1263.	Evaluate (1 &frasl; 64)^(-1&frasl;3)
A.	4^-1
B.	4
C.	2^-1
D.	2
Answer» C. 2^-1

Discussion

1264.	Simplify (a^(-1 &frasl; 3) × a^(1 &frasl; 3)) &frasl; a^(-1 &frasl; 2)
A.	a^(-7 ⁄ 18)
B.	a^(-1 ⁄ 2)
C.	a^(1 ⁄ 2)
D.	None of the above
Answer» D. None of the above

Discussion

1265.	Rationalise denominator of 1 &frasl; (3?5 - 3?2), simplify where possible
A.	(3?5 - 3?2) ⁄ (63 - 18?10)
B.	(3?5 + 3?2) ⁄ 27
C.	(3?5 + 3?2) ⁄ (63 - 18?10)
D.	(3?5 - 3?2) ⁄ 27
Answer» C. (3?5 + 3?2) ⁄ (63 - 18?10)

Discussion

1266.	Expand and simplify (3 + 2?5)(6 + 4?5)
A.	58 + 24?5
B.	58 + 12?5
C.	58 + 24?10
D.	18 + 32?5
Answer» B. 58 + 12?5

Discussion

1267.	Express ?500 in terms of simplest possible surd.
A.	10?50
B.	50?10
C.	10?5
D.	5?10
Answer» D. 5?10

Discussion

1268.	Express ?20 in terms of simplest possible surd.
A.	10
B.	5?2
C.	4?5
D.	2?5
Answer» E.

Discussion

1269.	Simplify (2 &frasl; tanA) + (4 &frasl; tanB)
A.	(2tanB + 4tanA) ⁄ tanAtanB
B.	(2tanA + 4tanB) ⁄ tanAtanB
C.	6 ⁄ (tanA + tanB)
D.	None of the above
Answer» B. (2tanA + 4tanB) ⁄ tanAtanB

Discussion

1270.	Consider a line passing through (16, 4) and (36, 6), gradient of this line is equal to:
A.	-0.1
B.	0.1
C.	-10
D.	10
Answer» C. -10

Discussion

1271.	Consider a line passing through (1, 2) and (4, 8), gradient of this line is equal to:
A.	1 ⁄ 2
B.	-1 ⁄ 2
C.	2
D.	-2
Answer» D. -2

Discussion

1272.	Length of line joining two points (16, 4) and (36, 6) is:
A.	22
B.	?22
C.	404
D.	?404
Answer» E.

Discussion

1273.	Coordinates of midpoint of line joining two points (16, 4) and (36, 6) are:
A.	(26, 5)
B.	(5, 26)
C.	(10, 1)
D.	(1, 10)
Answer» B. (5, 26)

Discussion

1274.	Length of line joining two points (1, 2) and (4, 8) is:
A.	3
B.	9
C.	?45
D.	45
Answer» D. 45

Discussion

Explore topic-wise MCQs in SRMJEEE .

Solve&nbsp;equation&nbsp;x2&nbsp;-&nbsp;3x

Solve&nbsp;equation&nbsp;x2&nbsp;+&nbsp;3x

Solve&nbsp;equation&nbsp;x2&nbsp;+&nbsp;6x&nbsp;-&nbsp;7&nbsp;=&nbsp;0

Solve&nbsp;equation&nbsp;4x2&nbsp;+&nbsp;36x&nbsp;+&nbsp;81

Logarithm&nbsp;of&nbsp;(a3)(b2)?c&nbsp;is:

Logarithm&nbsp;of&nbsp;&#39;x&#39;&nbsp;to&nbsp;power&nbsp;&#39;y&#39;&nbsp;is&nbsp;equal&nbsp;to:

&nbsp;Logarithm&nbsp;to&nbsp;base&nbsp;&#39;x&#39;&nbsp;of&nbsp;&#39;y&frasl;z&#39;&nbsp;is&nbsp;equal&nbsp;to:

Logarithm&nbsp;to&nbsp;base&nbsp;&#39;x&#39;&nbsp;of&nbsp;&#39;yz&#39;&nbsp;is&nbsp;equal&nbsp;to:

&nbsp;Logarithm&nbsp;to&nbsp;base&nbsp;1&frasl;2&nbsp;of&nbsp;16&nbsp;is:

&nbsp;In&nbsp;logarithmic&nbsp;form&nbsp;of&nbsp;&#39;2&amp;sup6;&nbsp;=&nbsp;64&#39;:

Index&nbsp;form&nbsp;of&nbsp;&#39;logarithm&nbsp;to&nbsp;base&nbsp;x&nbsp;of&nbsp;y&nbsp;is&nbsp;z&#39;&nbsp;is:

Logarithm&nbsp;to&nbsp;base&nbsp;10&nbsp;of&nbsp;1000&nbsp;is:

Evaluate&nbsp;(1&nbsp;&frasl;&nbsp;64)^(-1&frasl;3)

Simplify&nbsp;(a^(-1&nbsp;&frasl;&nbsp;3)&nbsp;&times;&nbsp;a^(1&nbsp;&frasl;&nbsp;3))&nbsp;&frasl;&nbsp;a^(-1&nbsp;&frasl;&nbsp;2)

Rationalise&nbsp;denominator&nbsp;of&nbsp;1&nbsp;&frasl;&nbsp;(3?5&nbsp;-&nbsp;3?2),&nbsp;simplify&nbsp;where&nbsp;possible

&nbsp;Expand&nbsp;and&nbsp;simplify&nbsp;(3&nbsp;+&nbsp;2?5)(6&nbsp;+&nbsp;4?5)

Express&nbsp;?500&nbsp;in&nbsp;terms&nbsp;of&nbsp;simplest&nbsp;possible&nbsp;surd.

&nbsp;Express&nbsp;?20&nbsp;in&nbsp;terms&nbsp;of&nbsp;simplest&nbsp;possible&nbsp;surd.

Simplify&nbsp;(2&nbsp;&frasl;&nbsp;tanA)&nbsp;+&nbsp;(4&nbsp;&frasl;&nbsp;tanB)

&nbsp;Consider&nbsp;a&nbsp;line&nbsp;passing&nbsp;through&nbsp;(16,&nbsp;4)&nbsp;and&nbsp;(36,&nbsp;6),&nbsp;gradient&nbsp;of&nbsp;this&nbsp;line&nbsp;is&nbsp;equal&nbsp;to:

&nbsp;Consider&nbsp;a&nbsp;line&nbsp;passing&nbsp;through&nbsp;(1,&nbsp;2)&nbsp;and&nbsp;(4,&nbsp;8),&nbsp;gradient&nbsp;of&nbsp;this&nbsp;line&nbsp;is&nbsp;equal&nbsp;to:

&nbsp;Length&nbsp;of&nbsp;line&nbsp;joining&nbsp;two&nbsp;points&nbsp;(16,&nbsp;4)&nbsp;and&nbsp;(36,&nbsp;6)&nbsp;is:

Coordinates&nbsp;of&nbsp;midpoint&nbsp;of&nbsp;line&nbsp;joining&nbsp;two&nbsp;points&nbsp;(16,&nbsp;4)&nbsp;and&nbsp;(36,&nbsp;6)&nbsp;are:

Length&nbsp;of&nbsp;line&nbsp;joining&nbsp;two&nbsp;points&nbsp;(1,&nbsp;2)&nbsp;and&nbsp;(4,&nbsp;8)&nbsp;is:

Solve equation x2 - 3x

Solve equation x2 + 3x

Solve equation x2 + 6x - 7 = 0

Solve equation 4x2 + 36x + 81

Logarithm of (a3)(b2)?c is:

Logarithm of 'x' to power 'y' is equal to:

Logarithm to base 'x' of 'y&frasl;z' is equal to:

Logarithm to base 'x' of 'yz' is equal to:

Logarithm to base 1&frasl;2 of 16 is:

In logarithmic form of '2&sup6; = 64':

Index form of 'logarithm to base x of y is z' is:

Logarithm to base 10 of 1000 is:

Evaluate (1 &frasl; 64)^(-1&frasl;3)

Simplify (a^(-1 &frasl; 3) × a^(1 &frasl; 3)) &frasl; a^(-1 &frasl; 2)

Rationalise denominator of 1 &frasl; (3?5 - 3?2), simplify where possible

Expand and simplify (3 + 2?5)(6 + 4?5)

Express ?500 in terms of simplest possible surd.

Express ?20 in terms of simplest possible surd.

Simplify (2 &frasl; tanA) + (4 &frasl; tanB)

Consider a line passing through (16, 4) and (36, 6), gradient of this line is equal to:

Consider a line passing through (1, 2) and (4, 8), gradient of this line is equal to:

Length of line joining two points (16, 4) and (36, 6) is:

Coordinates of midpoint of line joining two points (16, 4) and (36, 6) are:

Length of line joining two points (1, 2) and (4, 8) is: