Logarithm to base 'x' of 'y&frasl;z' is equal to:

(logarithm to the base x of y) × (logarithm to the base x of z)

(logarithm to the base x of y) + (logarithm to the base x of z)

(logarithm to the base x of y) - (logarithm to the base x of z)

Logarithm to base 'x' of 'y⁄z' is equal to:

1.	Logarithm to base 'x' of 'y&frasl;z' is equal to:
A.	(logarithm to the base x of y) × (logarithm to the base x of z)
B.	(logarithm to the base x of y) + (logarithm to the base x of z)
C.	(logarithm to the base x of y) - (logarithm to the base x of z)
D.	None of the above
Answer» D. None of the above

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Logarithm to base 'x' of 'y&frasl;z' is equal to: