MCQOPTIONS
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MCQOPTIONS
This section includes 2171 Mcqs, each offering curated multiple-choice questions to sharpen your ENGINEERING SERVICES EXAMINATION (ESE) knowledge and support exam preparation. Choose a topic below to get started.
| 1551. |
In a transistor βdc is likely to vary between 100 and 400. The proper value of βdc to be used to located Q point is |
| A. | 100 |
| B. | 400 |
| C. | 250 |
| D. | 200 |
| Answer» E. | |
| 1552. |
As compared to full wave rectifier, a half wave rectifier |
| A. | has higher ripple factor |
| B. | has lower ripple factor |
| C. | may have higher or lower ripple factor |
| D. | has same ripple factor |
| Answer» B. has lower ripple factor | |
| 1553. |
In a common emitter circuit all voltages are measured with respect to |
| A. | base |
| B. | emitter |
| C. | collector |
| D. | base or collector |
| Answer» C. collector | |
| 1554. |
A delay equalizer is a |
| A. | low pass filter |
| B. | band pass filter |
| C. | all pass filter |
| D. | high pass filter |
| Answer» C. all pass filter | |
| 1555. |
Linear transistor circuits always operate in |
| A. | saturation region |
| B. | cut off region |
| C. | active region |
| D. | passive region |
| Answer» D. passive region | |
| 1556. |
An op-amp has |
| A. | low input and output impedance |
| B. | low input impedance and high output impedance |
| C. | low output impedance and high input impedance |
| D. | high output impedance and high input impedance |
| Answer» D. high output impedance and high input impedance | |
| 1557. |
The circuit shown in the figure is that of |
| A. | non-inverting amplifier |
| B. | Inverting amplifier |
| C. | an oscillator |
| D. | Schmitt trigger |
| Answer» E. | |
| 1558. |
In figure the diode is ideal (zero cut in voltage zero forward resistance). Then the current through diode is |
| A. | 0 |
| B. | 4 A |
| C. | 1 A |
| D. | none of the above |
| Answer» D. none of the above | |
| 1559. |
A capacitor input filter relies on |
| A. | average detection |
| B. | peak detection |
| C. | both (a) and (b) |
| D. | neither (a) nor (b) |
| Answer» C. both (a) and (b) | |
| 1560. |
A CB amplifier has IE = 3.5 mA, a = 0.98 and RL = 600 Ω. The input impedance |
| A. | 0.98 Ω |
| B. | 0.025 Ω |
| C. | 0.025/3.5 x 10¯³ Ω |
| D. | 600 Ω |
| Answer» D. 600 Ω | |
| 1561. |
Occasionally a discrete amplifier user RF chokes instead of collector resistors. Such amplifiers are inherently |
| A. | low pass amplifiers |
| B. | high pass amplifiers |
| C. | band pass amplifiers |
| D. | none of the above |
| Answer» C. band pass amplifiers | |
| 1562. |
The output impedance of an ideal op-amp is |
| A. | zero |
| B. | low |
| C. | high |
| D. | infinite |
| Answer» B. low | |
| 1563. |
Which of the following is not the main characteristic of a FET? |
| A. | Drain resistance |
| B. | Forward transconductance |
| C. | Temperature stability |
| D. | Amplification factor |
| Answer» D. Amplification factor | |
| 1564. |
A CE amplifier is the most common BJT amplifier. |
| A. | True |
| B. | False |
| C. | May be True or False |
| D. | can't say |
| Answer» B. False | |
| 1565. |
In the circuit shown in the figure |
| A. | only red will glow |
| B. | only green will glow |
| C. | both red and green will glow |
| D. | none will glow |
| Answer» B. only green will glow | |
| 1566. |
In an amplifier circuit the emitter is at ac ground potential in a |
| A. | CB circuit |
| B. | CC circuit |
| C. | CE circuit |
| D. | both CB and CE circuit |
| Answer» D. both CB and CE circuit | |
| 1567. |
A difference amplifier using op-amp has closed loop gain = 50. If input is 2 V to each of inverting and non-inverting terminals, output is 5 mA. Then CMRR = |
| A. | 20000 |
| B. | 2000 |
| C. | 200 |
| D. | 20 |
| Answer» B. 2000 | |
| 1568. |
An RC coupled amplifier has an open loop gain of 200 and a lower cutoff frequency of 50 Hz. If negative feedback with β = 0.1 is used, the lower cut off frequency will be |
| A. | about 50 Hz |
| B. | about 5 Hz |
| C. | about 2.38 Hz |
| D. | about 70.5 Hz |
| Answer» D. about 70.5 Hz | |
| 1569. |
In CE amplifier |
| A. | input and output are in phase |
| B. | phase difference between input and output is 30° to 90° |
| C. | phase difference between input and output is 60° to 120° |
| D. | output is inverted with respect to its input voltage |
| Answer» E. | |
| 1570. |
A BJT is said to be operating in saturation region if |
| A. | both junctions are reverse biased |
| B. | both junctions are forward biased |
| C. | base emitter junction is forward biased and base collector junction is reverse biased |
| D. | base collector junction is forward biased and base emitter junction is reverse biased |
| Answer» C. base emitter junction is forward biased and base collector junction is reverse biased | |
| 1571. |
Which amplifier will be preferred for highest gain? |
| A. | Darlington's pair |
| B. | Single stage amplifier |
| C. | Cascade amplifier |
| D. | Depends on the circuitry |
| Answer» D. Depends on the circuitry | |
| 1572. |
The multivibrator circuit that has a typical application of converting sinusoidal input into a square wave output is |
| A. | emitter coupled binary |
| B. | Schmitt trigger |
| C. | monoshot multivibrator |
| D. | free-running multivibrator |
| Answer» C. monoshot multivibrator | |
| 1573. |
If a = 0.995, IE = 10 mA, ICO = 0.5 mA, then ICEO will be |
| A. | 100 μA |
| B. | 25 μA |
| C. | 10.1 μA |
| D. | 10.5 μA |
| Answer» B. 25 μA | |
| 1574. |
The advantage of transistor over vacuum tube is |
| A. | no heat is required |
| B. | small size and light in weight |
| C. | very low power consumption |
| D. | all of the above |
| Answer» E. | |
| 1575. |
In a base driver amplifier the voltage gain is the ratio of |
| A. | ac collector voltage to ac base voltage |
| B. | ac emitter voltage to ac base voltage |
| C. | ac collector voltage to ac emitter voltage |
| D. | ac base voltage to ac emitter voltage |
| Answer» B. ac emitter voltage to ac base voltage | |
| 1576. |
In a half wave rectifier, Vrms is |
| A. | A |
| B. | B |
| C. | C |
| D. | D |
| Answer» B. B | |
| 1577. |
Assertion (A): Electric coupling, magnetic coupling and ground loop can cause unwanted high frequency oscillations.Reason (R): Hartley oscillator uses a tapped inductor |
| A. | Both A and R are correct and R is correct explanation for A |
| B. | Both A and R are correct but R is not correct explanation for A |
| C. | A is correct R is wrong |
| D. | A is wrong R is correct |
| Answer» C. A is correct R is wrong | |
| 1578. |
Which of the following plot can be used to show the input volt-ampere characteristics of a common-emitter configuration? |
| A. | VBE versus iB for constant values of VCE |
| B. | VCE versus iC for constant values of IB |
| C. | VCE versus iC for constant values of IE |
| D. | None of the above |
| Answer» B. VCE versus iC for constant values of IB | |
| 1579. |
Which amplifier has the higher power gain? |
| A. | Common emitter |
| B. | Common collector |
| C. | Common base |
| D. | Both CC and CE |
| Answer» B. Common collector | |
| 1580. |
Transformer coupling in transistor amplifier circuits provides high efficiency, because |
| A. | d.c. resistance is low |
| B. | collector voltage is stepped up |
| C. | flux linkages are incomplete |
| D. | all of the above |
| Answer» B. collector voltage is stepped up | |
| 1581. |
The early effect in BJT is caused by |
| A. | fast turn on |
| B. | fast turn off |
| C. | large collector base reverse bias |
| D. | large emitter base forward bias |
| Answer» D. large emitter base forward bias | |
| 1582. |
In an amplifier with a gain of - 1000 and feedback factor β = - 0.1, the change in gain is 20% due to temperature. The change in gain for feedback amplifier will be |
| A. | 10% |
| B. | 5% |
| C. | 0.2% |
| D. | 0.01% |
| Answer» D. 0.01% | |
| 1583. |
The static characteristic of an adequately forward biased p-n junction is a straight line if the plot is of |
| A. | log I vs log V |
| B. | log I vs V |
| C. | I vs log V |
| D. | I vs V |
| Answer» C. I vs log V | |
| 1584. |
If a capacitor C is charged by a constant current I, then the rate of change of voltage with time given by sweep speed equal to |
| A. | C/I |
| B. | IC |
| C. | I/C |
| D. | 1/2(I/C) |
| Answer» D. 1/2(I/C) | |
| 1585. |
In a linear op-amp circuit |
| A. | the product of gain and bandwidth is constant |
| B. | input can be dc only |
| C. | input can be ac only |
| D. | saturation may occur |
| Answer» B. input can be dc only | |
| 1586. |
For the amplifier circuit of figure, the h parameters of transistor are hib = 25 Ω, hfb = 0.999, hob = 10¯⁶ Ω. The voltage gain is |
| A. | 0.999 |
| B. | 1.98 |
| C. | 20 |
| D. | 400 |
| Answer» E. | |
| 1587. |
Assertion (A): A class C amplifier can also be used as frequency multiplierReason (R): When narrow current pulses drive a resonant circuit the output can be a near perfect sine wave |
| A. | Both A and R are correct and R is correct explanation for A |
| B. | Both A and R are correct but R is not correct explanation for A |
| C. | A is correct R is wrong |
| D. | A is wrong R is correct |
| Answer» C. A is correct R is wrong | |
| 1588. |
Assertion (A): A tuned amplifier uses a parallel tuned circuitReason (R): A tuned amplifier is used to amplify a narrowband frequencies |
| A. | Both A and R are correct and R is correct explanation for A |
| B. | Both A and R are correct but R is not correct explanation for A |
| C. | A is correct R is wrong |
| D. | A is wrong R is correct |
| Answer» B. Both A and R are correct but R is not correct explanation for A | |
| 1589. |
When a JFET is cut off, it's like an __________ switch and when it is saturated, it's like a __________ switch. |
| A. | closed, open |
| B. | open, closed |
| C. | open, open |
| D. | closed, closed |
| Answer» C. open, open | |
| 1590. |
Typical values of current gains for CE, CB and CC amplifiers are |
| A. | 120, 120 and 1 respectively |
| B. | 120, 1 and 120 respectively |
| C. | 1, 120 and 120 respectively |
| D. | 1, 1 and 120 respectively |
| Answer» C. 1, 120 and 120 respectively | |
| 1591. |
An inverting amplifier has R1 = 10 kΩ, and Rf = 150 kΩ then the O/P voltage, if input voltage Vi = 1 volt. |
| A. | -15 V |
| B. | -10 V |
| C. | 15 V |
| D. | -14 V |
| Answer» B. -10 V | |
| 1592. |
If the op-amp in figure has a unity gain frequency of 1 MHz, the cut off frequency is |
| A. | 100 kHz |
| B. | 1 MHz |
| C. | 10 MHz |
| D. | 90 MHz |
| Answer» B. 1 MHz | |
| 1593. |
In an inverting amplifier using op-amp the current input to the inverting terminal |
| A. | is equal to the current through feedback resistance |
| B. | is less than the current through feedback resistance |
| C. | is more than the current through feedback resistance |
| D. | may be equal to, less or more than current through feedback resistance |
| Answer» B. is less than the current through feedback resistance | |
| 1594. |
In a transistor IE = 10 mA, ICO = 0.5 μA and α = 0.995. Then ICEO = |
| A. | 100 μA |
| B. | 25 μA |
| C. | 10.1 mA |
| D. | 10.5 mA |
| Answer» B. 25 μA | |
| 1595. |
Calculate the O/P voltage of a non-inverting constant gain multiplier with R1 = 100 kΩ, Rf= 600 kΩ, V1 = 2 volt, then O/P voltage Vo of non inverting op-amp is given by |
| A. | 16 V |
| B. | 14 V |
| C. | 20 V |
| D. | 15 V |
| Answer» C. 20 V | |
| 1596. |
In the op-amp circuit given in the figure, the load current iL is |
| A. | A |
| B. | B |
| C. | C |
| D. | D |
| Answer» B. B | |
| 1597. |
A Darlington circuit is obtained by connecting |
| A. | two CB stages in cascade |
| B. | two CE stages in cascade |
| C. | a CE stages followed by CB stage |
| D. | two emitter follower in cascade |
| Answer» B. two CE stages in cascade | |
| 1598. |
In CE approximation, the upper end of d.c. load line is called the __________ point and the lower end is the __________ point. |
| A. | Q, base |
| B. | base, Q |
| C. | saturation, cut off |
| D. | cut off, saturation |
| Answer» D. cut off, saturation | |
| 1599. |
In a transistor with normal bias |
| A. | the emitter junction has a low resistance |
| B. | the emitter junction has a very high resistance |
| C. | the emitter junction supplies majority carries into the base region |
| D. | none of the above |
| Answer» B. the emitter junction has a very high resistance | |
| 1600. |
The circuit shown is |
| A. | voltage series feedback amplifier |
| B. | transconductance amplifier |
| C. | transresistance amplifier with open circuit mutual resistance RF |
| D. | transresistance amplifier with short circuit mutual resistance RF |
| Answer» D. transresistance amplifier with short circuit mutual resistance RF | |