The expression of $$\frac{{\cot \theta+ \operatorname{cosec} \theta- 1}}{{\cot \theta+ \operatorname{cosec} \theta+ 1}}$$is equal to?

$\frac{{\cot \theta+ 1}}{{\operatorname{cosec} \theta }}$$

$\frac{{1 + \cos \theta }}{{\sin \theta }}$$

$\frac{{1 - \cos \theta }}{{\sin \theta }}$$

$\frac{{\cot \theta- 1}}{{\sin \theta }}$$

The expression of $$\frac{{\cot \theta+ \operatorname{cosec} \theta- 1

1.	The expression of $$\frac{{\cot \theta+ \operatorname{cosec} \theta- 1}}{{\cot \theta+ \operatorname{cosec} \theta+ 1}}$$is equal to?
A.	$\frac{{1 + \cos \theta }}{{\sin \theta }}$$
B.	$\frac{{1 - \cos \theta }}{{\sin \theta }}$$
C.	$\frac{{\cot \theta+ 1}}{{\operatorname{cosec} \theta }}$$
D.	$\frac{{\cot \theta- 1}}{{\sin \theta }}$$
Answer» C. $\frac{{\cot \theta+ 1}}{{\operatorname{cosec} \theta }}$$