The elastic strain ∆ of the subgrade is __________

Question

TuteeHUB · Accepted Answer

$∆=\frac{p}{2}\left[\frac{2(1+μ)z}{(a^2+z^2)^\frac{1}{2}}+ \frac{z^3}{(a^2+z^2)^\frac{3}{2}}\right]$

TuteeHUB · Answer

$∆=\frac{p}{E}\left[(2-2μ^2)(a^2+z^2)^\frac{1}{2}-\frac{(1+μ) z^2}{(a^2+z^2)^\frac{1}{2}}+(μ+2μ^2-1)z\right]$

TuteeHUB · Answer

$∆=\frac{p}{2}\left[\frac{2(1+μ)z}{(a^2+z^2)^\frac{1}{2}}+ \frac{z^3}{(a^2+z^2)^\frac{3}{2}}\right]$

TuteeHUB · Answer

$∆=\frac{p}{2}\left[1-2μ-\frac{2(1+μ)z}{(a^2+z^2)^\frac{1}{2}}+ \frac{z^3}{(a^2+z^2)^\frac{3}{2}}\right]$

TuteeHUB · Answer

$∆=\frac{p}{2}\left[1+2μ-\frac{2(1+μ)z}{(a^2+z^2)^\frac{1}{2}}+ \frac{z^3}{(a^2+z^2)^\frac{3}{2}}\right]$

1.	The elastic strain ∆ of the subgrade is __________
A.	\(∆=\frac{p}{E}\left[(2-2μ^2)(a^2+z^2)^\frac{1}{2}-\frac{(1+μ) z^2}{(a^2+z^2)^\frac{1}{2}}+(μ+2μ^2-1)z\right]\)
B.	\(∆=\frac{p}{2}\left[\frac{2(1+μ)z}{(a^2+z^2)^\frac{1}{2}}+ \frac{z^3}{(a^2+z^2)^\frac{3}{2}}\right]\)
C.	\(∆=\frac{p}{2}\left[1-2μ-\frac{2(1+μ)z}{(a^2+z^2)^\frac{1}{2}}+ \frac{z^3}{(a^2+z^2)^\frac{3}{2}}\right]\)
D.	\(∆=\frac{p}{2}\left[1+2μ-\frac{2(1+μ)z}{(a^2+z^2)^\frac{1}{2}}+ \frac{z^3}{(a^2+z^2)^\frac{3}{2}}\right]\)
Answer» B. \(∆=\frac{p}{2}\left[\frac{2(1+μ)z}{(a^2+z^2)^\frac{1}{2}}+ \frac{z^3}{(a^2+z^2)^\frac{3}{2}}\right]\)

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