1.

For a Poisson’s ratio of 0.5, the elastic strain ∆ is ___________

A. \(∆=\frac{3pa^2}{2E} \)
B. \(∆=\frac{pa^2}{2E(a^2+z^2)^\frac{1}{2}} \)
C. \(∆=\frac{3pa^2}{2E(a^2+z^2)^\frac{1}{2}} \)
D. \(∆=\frac{a^2}{2E(a^2+z^2)^\frac{1}{2}} \)
Answer» D. \(∆=\frac{a^2}{2E(a^2+z^2)^\frac{1}{2}} \)


Discussion

No Comment Found