Let the statement be “If n is not an odd integer then square of n is not odd.”, then if P(n) is “n is an not an odd integer” and Q(n) is “(square of n) is not odd.” For direct proof we should prove

Let the statement be “If n is not an odd integer then square of n is

1.	Let the statement be “If n is not an odd integer then square of n is not odd.”, then if P(n) is “n is an not an odd integer” and Q(n) is “(square of n) is not odd.” For direct proof we should prove
A.	∀np ((n) → q(n))
B.	∃ np ((n) → q(n))
C.	∀n~(p ((n)) → q(n))
D.	∀np ((n) → ~(q(n)))
Answer» B. ∃ np ((n) → q(n))