MCQOPTIONS
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| 1. |
For the frame shown in figure the, the shear equation is |
| A. | \(\frac{{({M_{BA}} + {M_{BC}})}}{4} + \frac{{{M_{CD}}}}{4} + P = 0\) |
| B. | \(\frac{{({M_{BA}} + {M_{AB}})}}{4} + \frac{{{M_{CD}}}}{4} + P = 0\) |
| C. | \({M_{BA}} + {M_{AB}} + {M_{CD}} + {M_{DC}} = 0\) |
| D. | \({M_{BA}} + {M_{AB}} + {M_{CD}} + {M_{DC}} = P\) |
| Answer» C. \({M_{BA}} + {M_{AB}} + {M_{CD}} + {M_{DC}} = 0\) | |