1.

For the frame shown in figure the, the shear equation is

A. \(\frac{{({M_{BA}} + {M_{BC}})}}{4} + \frac{{{M_{CD}}}}{4} + P = 0\)
B. \(\frac{{({M_{BA}} + {M_{AB}})}}{4} + \frac{{{M_{CD}}}}{4} + P = 0\)
C. \({M_{BA}} + {M_{AB}} + {M_{CD}} + {M_{DC}} = 0\)
D. \({M_{BA}} + {M_{AB}} + {M_{CD}} + {M_{DC}} = P\)
Answer» C. \({M_{BA}} + {M_{AB}} + {M_{CD}} + {M_{DC}} = 0\)


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