Displacement coordinates for the beam are as shown in figure. The flexibility matrix is given by:

\(\frac{1}{{EI}}\left[ {\begin{array}{*{20}{c}} 4&{ - 8}\\ { - 8}&{64 - 3} \end{array}} \right]\)

\(\frac{1}{{EI}}\left[ {\begin{array}{*{20}{c}} {64/3}&{ - 8}\\ { - 8}&{64} \end{array}} \right]\)

\(\frac{1}{{EI}}\left[ {\begin{array}{*{20}{c}} {64/3}&8\\ 8&{ - 64/3} \end{array}} \right]\)

\(\frac{1}{{EI}}\left[ {\begin{array}{*{20}{c}} {64/3}&8\\ 8&4 \end{array}} \right]\)

Displacement coordinates for the beam are as shown in figure. The flex

1.	Displacement coordinates for the beam are as shown in figure. The flexibility matrix is given by:
A.	\(\frac{1}{{EI}}\left[ {\begin{array}{*{20}{c}} {64/3}&{ - 8}\\ { - 8}&{64} \end{array}} \right]\)
B.	\(\frac{1}{{EI}}\left[ {\begin{array}{*{20}{c}} {64/3}&8\\ 8&{ - 64/3} \end{array}} \right]\)
C.	\(\frac{1}{{EI}}\left[ {\begin{array}{*{20}{c}} {64/3}&8\\ 8&4 \end{array}} \right]\)
D.	\(\frac{1}{{EI}}\left[ {\begin{array}{*{20}{c}} 4&{ - 8}\\ { - 8}&{64 - 3} \end{array}} \right]\)
Answer» D. \(\frac{1}{{EI}}\left[ {\begin{array}{*{20}{c}} 4&{ - 8}\\ { - 8}&{64 - 3} \end{array}} \right]\)

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Displacement coordinates for the beam are as shown in figure. The flexibility matrix is given by:

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