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This section includes 10 Mcqs, each offering curated multiple-choice questions to sharpen your Genetic Engineering knowledge and support exam preparation. Choose a topic below to get started.
1. |
If all the nucleotides are present with equal frequencies and at random, what are the chances of having a particular four nucleotide long motif? |
A. | 1/256 |
B. | 1/64 |
C. | 1/16 |
D. | 1/8 |
Answer» B. 1/64 | |
2. |
The recognition sequence is at times palindromic in nature. Which of the following statements is correct with respect to it? |
A. | The molecules which are cut by the same enzyme, anneal only if the sequence is palindromic in nature |
B. | When the molecules are cleaved by the same enzyme and the recognition sequence is palindromic in nature, there is no effect on annealing |
C. | There are increased chances of annealing if the recognition sequence is palindromic in nature |
D. | The term palindromic can be used whether the sequence is read from 5 to 3 or 3 to 5 |
Answer» D. The term palindromic can be used whether the sequence is read from 5 to 3 or 3 to 5 | |
3. |
The recognition sequence of Sau3A is 5 |GATC 3 and that for DpnI is 5 GA|TC 3 . Which of the statements is true? |
A. | The ends created by both the enzymes are compatible |
B. | The ends created by both the enzymes are not-compatible |
C. | The ends created by DpnI are single stranded |
D. | The ends created by Sau3A are single stranded |
Answer» C. The ends created by DpnI are single stranded | |
4. |
The recognition sequence for BamHI is 5 G|GATCC 3 . The | represents the cutting site. What can be inferred about the ends from it? |
A. | The ends created are double stranded |
B. | The single stranded end is 5 in nature |
C. | The single stranded end is 3 in nature |
D. | To decide about the nature of the ends more information is needed |
Answer» C. The single stranded end is 3 in nature | |
5. |
Blunt ends created by the restriction endonuclease can be joined. |
A. | True |
B. | False |
Answer» B. False | |
6. |
A sequence is having two ends, 5 and 3 . Which of the following statements is correct regarding the nature of the ends? |
A. | The 5 end is having hydroxyl group |
B. | The 5 end is having phosphate group |
C. | The 3 end is having phosphate group |
D. | Any group can be present at any end |
Answer» C. The 3 end is having phosphate group | |
7. |
After cleaving the sequence, the nature of the ends created by the type II endonuclease is __________ |
A. | The ends created are always single stranded |
B. | The ends created are always double stranded |
C. | Either the ends are single stranded or they are double stranded |
D. | One end is single stranded and one end is double stranded |
Answer» D. One end is single stranded and one end is double stranded | |
8. |
Type II cuts the sequence in the following way __________ |
A. | Within the recognition sequence |
B. | At 100-1000 nucleotides away from the recognition sequence |
C. | At 27-30 nucleotides away from the recognition sequence |
D. | It cuts randomly |
Answer» B. At 100-1000 nucleotides away from the recognition sequence | |
9. |
The restriction endonuclease is having a defence mechanism in the bacterial system against foreign DNA such as viruses. But how it is able to protect its own DNA? |
A. | By methylation of bacterial DNA by restriction enzyme |
B. | By methylation of foreign DNA by restriction enzyme |
C. | By phosphorylation of bacterial DNA by restriction enzyme |
D. | By phosphorylation of foreign DNA by restriction enzyme |
Answer» B. By methylation of foreign DNA by restriction enzyme | |
10. |
The term endonuclease refers to cutting the DNA sequence from ______________ |
A. | only within the polynucleotide chain, not at the ends |
B. | the ends of the chain |
C. | anywhere in the chain |
D. | exactly in the middle of the chain |
Answer» B. the ends of the chain | |