MCQOPTIONS
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MCQOPTIONS
This section includes 100 Mcqs, each offering curated multiple-choice questions to sharpen your Industrial Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Maximize z = 15x1 + 20x2 Subject to 12x1 + 4x1 36 12x1 + 6x1 24 x1, x1 0 The above linear programming problem has |
| A. | infeasible solution |
| B. | unbounded solution |
| C. | alternative optimum solutions |
| D. | degenerate solution |
| Answer» C. alternative optimum solutions | |
| 2. |
A linear programming problem is shown below: Maximise 3x + 7y Subjeot to 3x + 7y 10 4x + 6y 8 x, y 0 |
| A. | an unbounded objective function |
| B. | exactly one optimal solution |
| C. | exactly two optimal solution |
| D. | infinitely many optimal solution |
| Answer» C. exactly two optimal solution | |
| 3. |
Consider an objective function Z(x1, x2) = 3x1 + 9x2 and the constraints x1 + x2 8 x1 + 2x2 4 x1 0, x2 0 The maximum value of the objective function is __________. |
| A. | 10 |
| B. | 18 |
| C. | 20 |
| D. | 14 |
| Answer» C. 20 | |
| 4. |
For the linear programming problem: Maximize z = 3x1 + 2x2 Subject to 2x1 + 3x2 9 x1 5x2 20 x1, x2 0 The above problem has |
| A. | unbounded solution |
| B. | infeasible solution |
| C. | alternative optimum solution |
| D. | degenerate solution |
| Answer» D. degenerate solution | |
| 5. |
For the standard transportation linear program with m sources and n destinations and total supply equaling total demand, an optimal solution (lowest cost) with the smallest number of non-zero xij values (amounts from source i to destination j) is desired. The best upper bound for this number is |
| A. | m n |
| B. | 2(m + n) |
| C. | m + n. |
| D. | m + n 1 |
| Answer» D. m + n 1 | |
| 6. |
The problem of maximizing Z = x1 x2 subject to constrains x1 + x2 10, x1 0, x2 0 and x2 5 has |
| A. | no solution |
| B. | one solution |
| C. | two solutions |
| D. | more than two solutions |
| Answer» C. two solutions | |
| 7. |
The minimum value of 3x + 5y such that: 3x + 5y 15 4x + 9y 8 13x + 2y 2 x 0, y 0 is ___________ . |
| A. | 0 |
| B. | 1 |
| C. | 2 |
| D. | - 1 |
| Answer» B. 1 | |
| 8. |
Following data refers to the jobs (P, Q, R, S) which have arrived at a machine for scheduling. The shortest possible average flow time is ____ days.JobProcessing Time (days)P15Q9R 22S12 |
| A. | 31 |
| B. | 32 |
| C. | 33 |
| D. | 30 |
| Answer» B. 32 | |
| 9. |
The unit worth of resource R2, i.e. dual price of resource R2 in Rs per kg is |
| A. | 0 |
| B. | 1360 |
| C. | 1500 |
| D. | 2000 |
| Answer» B. 1360 | |
| 10. |
Consider the following Linear Programming Problem (LPP): Maximize z = 3x1 + 2x2, Subject to x1 4 x2 = 6 3x1 + 2x2 < 18 x1 0, x2 0 |
| A. | The LPP has a unique optimal solution |
| B. | The LPP is infeasible |
| C. | The LPP is unbounded |
| D. | The LPP has multiple optimal solution |
| Answer» E. | |
| 11. |
In an M/M/1 queuing system, the number of arrivals in an interval of length T is a Poisson random variable i.e. the probability of there being n arrivals in an interval of length T is e T( T)nThe probability density function f(t) of the inter- arrival time is given byn! |
| A. | |
| B. | (e |
| C. | ) |
| D. | |
| E. | e |
| Answer» D. | |
| 12. |
If an additional constraint X1 + X2 5 is added, the optimal solution is |
| A. | (5/3, 5/3) |
| B. | (4/3,4/3) |
| C. | (5/2, 5/2) |
| D. | (5, 0) |
| Answer» C. (5/2, 5/2) | |
| 13. |
A company has two factories S1, S2 and two warehouses D1, D2. The supplies from S1 and S2 are 50 and 40 units respectively. Warehouse D1 requires a minimum of 20 units and a maximum of 40 units. Warehouse D2 requires a minimum of 20 units and, over and above, it can take as much as can be supplied. A balanced transportation problem is to be formulated for the above situation. The number of supply points, the number of demand points, and the total supply (or total demand) in the balanced transportation problem respectively are |
| A. | 2, 4, 90 |
| B. | 2, 4, 110 |
| C. | 3, 4, 90 |
| D. | 3, 4,110 |
| Answer» D. 3, 4,110 | |
| 14. |
Match the following List-I (Problem areas) List-II (Techniques) A. JIT 1. CRAFT B. Computer assisted 2. PERT layout C. Scheduling 3. Johnson's rule D. Simulation 4. Kanbans 5. EOQ rule 6. Monte Carl |
| A. | A 4, B 5, C 3, D 1. |
| B. | A 1, B 5, C 3, D 4. |
| C. | A 4, B 1, C 3, D 6 |
| D. | A 5, B 2, C 3, D 6 |
| Answer» D. A 5, B 2, C 3, D 6 | |
| 15. |
If the demand for an item is doubled and the ordering cost halved, the economic order quantity |
| A. | remains unchanged |
| B. | increases by factor of |
| C. | |
| D. | is doubled |
| E. | is halved |
| Answer» B. increases by factor of | |
| 16. |
A manufacturer produces two types of products, 1 and 2, at production levels of x1 and x2 respectively. The profit is given is 2x1 + 5x2. The production constraints are : x1 + 3x2 < 40 3x1 + x2 < 24 x1 + x2 < 10 x1 > 0 , x2 > 0 The maximum profit which can meet the constraints is |
| A. | 29 |
| B. | 38 |
| C. | 44 |
| D. | 75 |
| Answer» D. 75 | |
| 17. |
In the notation (a/b/c): {d/e/f) for summarizing the characteristics of queuing situation, the letters b and c stand respectively for |
| A. | service time distribution & queue discipline |
| B. | number of servers & size of calling source |
| C. | number of servers & queue discipline |
| D. | service time distribution and maximum number allowed in system |
| Answer» B. number of servers & size of calling source | |
| 18. |
For a single server with Poisson arrival and exponential service time, the arrival rate is 12 per hour. Which one of the following service rates will provide a steady state finite queue length? |
| A. | 6 per hour |
| B. | 10 per hour |
| C. | 12 per hour |
| D. | 24 per hour |
| Answer» E. | |
| 19. |
In a single-channel queuing model, the customer arrival rate is 12 per hour and the serving rate is 24 per hour. The expected time that a customer is in queue is minutes. |
| A. | 2.1min |
| B. | 2.5 min |
| C. | 3.5 min |
| D. | 2 min |
| Answer» C. 3.5 min | |
| 20. |
Which of the following forecasting methods takes a fraction of forecast error into account for the next period forecast? |
| A. | simple average method |
| B. | moving average method |
| C. | weighted moving average method |
| D. | exponential smoothening method |
| Answer» E. | |
| 21. |
A manufacturer can produce 12000 bearings per day. The manufacturer received an order of 8000 bearings per day from a customer. The cost of holding a bearing in stock is Rs. 0.20 per month. Setup cost per production run is Rs. 500. Assuming 300 working days in a year, the frequency of production run should be |
| A. | 4.5 days |
| B. | 4.5 months |
| C. | 6.8 days |
| D. | 6.8 months |
| Answer» D. 6.8 months | |
| 22. |
Annual demand for window frames is 10000. Each frame costs Rs. 200 and ordering cost is Rs. 300 per order. Inventory holding cost is Rs. 40 per frame per year. The supplier is willing to offer 2% discount if the order quantity is 1000 or more, and 4% if order quantity is 2000 or more. If the total cost is to be minimized, the retailer should |
| A. | order 200 frames every time |
| B. | accept 2% discount |
| C. | accept 4% discount |
| D. | order Economic Order Quantity |
| Answer» D. order Economic Order Quantity | |
| 23. |
Maximize z = 15x |
| A. | infeasible solution |
| B. | unbounded solution |
| C. | alternative optimum solutions |
| D. | degenerate solution |
| Answer» C. alternative optimum solutions | |
| 24. |
The demand and forecast for February are 12000 and 10275, respectively. Using single exponential smoothening method (smoothening coefficient = 0.25), forecast for the month of March is |
| A. | 431 |
| B. | 9587 |
| C. | 10706 |
| D. | 11000 |
| Answer» D. 11000 | |
| 25. |
In computing Wilson's economic lot size for an item, by mistake the demand rate estimate used was 40% higher than the true demand rate. Due to this error in the lot size computation, the total cost of setup plus inventory holding per unit time. Would rise above the true optimum by approximately |
| A. | 1.4% |
| B. | 3.3% |
| C. | 18.3% |
| D. | 8.7% |
| Answer» D. 8.7% | |
| 26. |
If duration of activity f is changed to 10 days, then the critical path for the project is |
| A. | Critical path remains the same and the total duration to complete the project changes to 19 days. |
| B. | Critical path and the total duration to complete the project remains the same. |
| C. | Critical path changes but the total duration tocomplete the project remains the same. |
| D. | Critical path changes and the total duration to complete the project changes to 17 days. |
| Answer» B. Critical path and the total duration to complete the project remains the same. | |
| 27. |
For the linear programming problem: |
| A. | unbounded solution |
| B. | infeasible solution |
| C. | alternative optimum solution |
| D. | degenerate solution |
| Answer» D. degenerate solution | |
| 28. |
Consider an objective function Z(x |
| A. | 10 |
| B. | 18 |
| C. | 20 |
| D. | 14 |
| Answer» C. 20 | |
| 29. |
A linear programming problem is shown below: |
| A. | an unbounded objective function |
| B. | exactly one optimal solution |
| C. | exactly two optimal solution |
| D. | infinitely many optimal solution |
| Answer» C. exactly two optimal solution | |
| 30. |
If the Earliest Due Date (EDD) rule is used to sequence the jobs, the number of jobs delayed is |
| A. | 1 |
| B. | 2 |
| C. | 3 |
| D. | 4 |
| Answer» D. 4 | |
| 31. |
The time series forecasting method that gives equal weightage to each of the most recent observation is |
| A. | Moving average method |
| B. | Exponential smoothing with linear trend |
| C. | Triple Exponential smoothing |
| D. | Kalman Filter |
| Answer» B. Exponential smoothing with linear trend | |
| 32. |
Using the Shortest Processing Time (SPT) rule, totel tardiness is |
| A. | 0 |
| B. | 2 |
| C. | 6 |
| D. | 8 |
| Answer» D. 8 | |
| 33. |
A welding operation is time-studied during which an operator was pace-rated as 120%. The operator took, on an average, 8 minutes for producing the weld-joint. If a total of 10% allowances are at lowed for this operation. The expected standard production rate of the weldjoint (in units per 8 hour day) is |
| A. | 45 |
| B. | 50 |
| C. | 55 |
| D. | 60 |
| Answer» B. 50 | |
| 34. |
Jobs arrive at a facility at an average rate of 5 in an 8 hour shift. The arrival of the jobs follows Poisson distribution. The average service time of a job on the facility is 40 minutes. The service time follows exponential distribution. Idle time (in hours) at the facility per shift will be |
| A. | 5/7 |
| B. | 14/3 |
| C. | 7/3 |
| D. | 10/3 |
| Answer» C. 7/3 | |
| 35. |
The lengths of a large stock of titanium rods follow a normal distribution with a mean ( ) of 440 mm and a standard deviation ( ) of 1 mm. What is the percentage of rods whose lengths lie between 438 mm and 441 mm? |
| A. | 68.4% |
| B. | 99.75% |
| C. | 81.85% |
| D. | 86.64% |
| Answer» D. 86.64% | |
| 36. |
At a work station, 5 jobs arrive every minute. The mean time spent on each job in the work station is 1/8 minute. The mean steady state number of jobs in the system is |
| A. | 8 |
| B. | 14 |
| C. | 15 |
| D. | None of these |
| Answer» E. | |
| 37. |
Customers arrive at a ticket counter at a rate of 50 per hr and tickets are issued in the order of their arrival. The average time taken for issuing a ticket is 1 min. Assuming that customer arrivals form a Poisson process and service times are exponentially distributed, the average waiting time in queue in min is |
| A. | 3 |
| B. | 4 |
| C. | 5 |
| D. | 6 |
| Answer» D. 6 | |
| 38. |
Cars arrive at a service station according to Poisson's distribution with a mean rate of 5 per hour. The service time per car is exponential with a mean of 10 minutes. At steady state, the average waiting time in the queue is |
| A. | 10 minutes |
| B. | 20 minutes |
| C. | 25 minutes |
| D. | 50 minutes |
| Answer» E. | |
| 39. |
Little's law is a relationship between |
| A. | stock level and lead time in an inventory system |
| B. | waiting time and length of the queue in a queuing system |
| C. | number of machines and job due dates in a scheduling problem |
| D. | uncertainty in the activity time and project completion time |
| Answer» C. number of machines and job due dates in a scheduling problem | |
| 40. |
During the development of a product, an entirely new process plan is made based on design logic, examination of geometry and tolerance information. This type of process planning is known as |
| A. | retrieval |
| B. | generative |
| C. | variant |
| D. | group technology based |
| Answer» B. generative | |
| 41. |
The demand for a two-wheeler was 900 units and 1030 units in April 2015 and May 2015, respectively. The forecast for the month of April 2015 was 850 units. Considering a smoothing constant of 0.6, the forecast for the month of June 2015 is |
| A. | 850 units |
| B. | 927 units |
| C. | 965 units |
| D. | 970 units |
| Answer» E. | |
| 42. |
For a canteen, the actual demand for disposable cups was 500 units in January and 600 units in February. The forecast for the month of January was 400 units. The forecast for the month of March considering smoothing coefficient as 0.75 is. |
| A. | 569 |
| B. | 568 |
| C. | 570 |
| D. | 565 |
| Answer» B. 568 | |
| 43. |
The supply at three sources is 50, 40 and 60 units respectively while the demand at the four destinations is 20, 30,10 and 50 units. In solving this transportation problem. |
| A. | a dummy source of capacity 40 units is needed |
| B. | a dummy destination of capacity 40 units is needed |
| C. | no solution exists as the problem is infeasible |
| D. | none solution exists as the problem is degenerate |
| Answer» C. no solution exists as the problem is infeasible | |
| 44. |
Following data refers to the jobs (P, Q, R, S) which have arrived at a machine for scheduling. The shortest possible average flow time is ____ days. |
| A. | 31 |
| B. | 32 |
| C. | 33 |
| D. | 30 |
| Answer» B. 32 | |
| 45. |
The annual requirement of rivets at a ship manufacturing company is 2000 unit. The rivets are supplied in units of 1 kg costing Rs. 25 each. The costs Rs. 100 to place an order and the annual cost of carrying one unit is 9% of its purchase cost, the cycle length of the order (in days) will be ______. |
| A. | 76.9457 days |
| B. | 75.9457 days |
| C. | 73.9457 days |
| D. | 74.9457 days |
| Answer» B. 75.9457 days | |
| 46. |
Cylindrical pins of diameter 15 0.020 mm are being produced on a machine. Statistical quality control tests show a mean of 14.995 mm and standard deviation of 0.004 mm. The process capability index Cp is |
| A. | 0.833 |
| B. | 1.667 |
| C. | 3.333 |
| D. | 3.750 |
| Answer» C. 3.333 | |
| 47. |
A manufacturer has the following data regarding a product: Fixed cost per month = Rs. 50000 Variable cost per unit = Rs. 200 Selling price per unit = Rs. 300 Production capacity = 1500 units per month .If the production is carried out at 80% of the rated capacity, then the monthly profit (in Rs.) is___. |
| A. | Rs. 70,000 |
| B. | Rs. 69,000 |
| C. | Rs. 71,000 |
| D. | Rs. 75,000 |
| Answer» B. Rs. 69,000 | |
| 48. |
Annual demand of a product is 50000 units and the ordering cost is Rs. 7000 per order. Considering the basic economic order quantity model, the economic order quantity is 10000 units. When the annual inventory cost is minimized, the annual inventory holding cost (in Rs.) is_____. |
| A. | 35000 |
| B. | 34000 |
| C. | 34500 |
| D. | 35500 |
| Answer» B. 34000 | |
| 49. |
Two models, P and Q of a product earn profits of Rs. 100 and Rs. 80 per piece, respectively. Production times for P and Q are 5 hours and 3 hours, respectively, while the total production time available is 150 hours. For a total batch size of 40, to maximize profit, the member of units of P to be produced is_____. |
| A. | 15 |
| B. | 14 |
| C. | 16 |
| D. | 17 |
| Answer» B. 14 | |
| 50. |
The annual demand of valves per year in a company is 10,000 units. The current order quantity is 400 valves per order. The holding cost is Rs. 24 per valve per year and the ordering cost is Rs. 400 per order. If the current order quant i t y i s changed t o Economi c Or der Quantity, then the saving in the total cost of inventory per year will be Rs. _____ (round off to two decimal places). |
| A. | Rs. 943.59 |
| B. | Rs. 933.59 |
| C. | Rs. 923.59 |
| D. | Rs. 953.59 |
| Answer» B. Rs. 933.59 | |