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This section includes 115 Mcqs, each offering curated multiple-choice questions to sharpen your Genetic Engineering knowledge and support exam preparation. Choose a topic below to get started.
1. |
Mobile portions of a chromosome which can be transferred from one portion to another are termed as ___________ |
A. | mobile part |
B. | transposons |
C. | walking elements |
D. | transferrable genetic element |
Answer» C. walking elements | |
2. |
Nitrocellulose membranes are less sensitive than nylon membranes. |
A. | True |
B. | False |
C. | May be True or False |
D. | Can't say |
Answer» C. May be True or False | |
3. |
GFP is one of a marker which is used for screening libraries in hosts other than E. coli. Choose the incorrect statement for GFP. |
A. | It stands for Green Fluorescent Protein |
B. | It is obtained from a bio-luminescent jellyfish and produces protein aequorin which emits blue light |
C. | The blue light is produced because of binding of sodium ions |
D. | The absorbed blue light produces green light which can be detected further |
Answer» D. The absorbed blue light produces green light which can be detected further | |
4. |
Luciferase genes are also used at times for detection. Choose the correct statement for them. |
A. | They are obtained from fire flies only |
B. | The detection requires provision of substrate which produces light |
C. | Enzymes such as beta-galactosidase requires substrate X-gluc to produce light |
D. | Lucifearse genes are preferred over fluorescent proteins |
Answer» C. Enzymes such as beta-galactosidase requires substrate X-gluc to produce light | |
5. |
If we are having sequence data for a particular organism, but screening is carried out for homologues the program used is BLAST. |
A. | True |
B. | False |
C. | May be True or False |
D. | Can't say |
Answer» B. False | |
6. |
The screening of libraries us carried out by nucleic acid hybridisation and constitutes of following steps:i) Peeling of membranes carrying away bacterial cells with itii) Cells are lysed and denaturing of DNA is being carried outiii) Hybridization with labelled DNAiv) Placing the membrane onto plate containing recombinant cellsChoose the correct sequence in which the steps are carried out (starting to ending). |
A. | iv)-i)-ii)-iii) |
B. | iv)-ii)-i)-iii) |
C. | i)-ii)-iii)-iv) |
D. | iii)-ii)-i)-iv) |
Answer» B. iv)-ii)-i)-iii) | |
7. |
The nucleic acid from the cell type that contains the sequence we are interested in is called ___________ |
A. | driver |
B. | subtractive sequence |
C. | tracer |
D. | wanted sequence |
Answer» D. wanted sequence | |
8. |
If physical methods are used, tracer is amplified and is labelled with biotin. |
A. | True |
B. | False |
C. | May be True or False |
D. | Can't say |
Answer» C. May be True or False | |
9. |
Choose the incorrect statement for the open reading frame. |
A. | It is helpful in deciding whether the clone is correct or not |
B. | It consists of an initiation codon |
C. | It consists of a termination codon |
D. | The presence of introns doesn’t affect the open reading frame |
Answer» E. | |
10. |
Choose the incorrect statement for colony or plaque lift. |
A. | It is the base for screening based on nucleic acid hybridization |
B. | It is also known as Grunstein-Hogness technique |
C. | It is based on the fact that which members of the library have the same sequence as the DNA probe |
D. | The library may be plaques on a bacterial lawn and in that case it is known as plaque lift |
Answer» D. The library may be plaques on a bacterial lawn and in that case it is known as plaque lift | |
11. |
If the genome size is small, then sequencing of the entire genome is ___________ |
A. | easy |
B. | difficult |
C. | independent of the size of genome |
D. | not possible |
Answer» B. difficult | |
12. |
For identification of genes that are expressed under special conditions, _______ libraries are used. |
A. | cDNA |
B. | genomic |
C. | subtractive |
D. | shelf |
Answer» D. shelf | |
13. |
If translation and transcription are taking place together, the reaction is called as ______ and if they are carried out separately, it is called as _______ |
A. | coupled, linked |
B. | linked, coupled |
C. | grouped, separate |
D. | grouped, individual |
Answer» B. linked, coupled | |
14. |
Which of the following is desirable? |
A. | Driver- driver hybrid |
B. | Driver- tracer hybrid |
C. | Tracer- tracer hybrid |
D. | Driver alone |
Answer» D. Driver alone | |
15. |
At what temperatures the hybridization and washing of the DNA probes should be carried out? |
A. | At melting temperature |
B. | At a temperature lower than the melting temperature |
C. | At a temperature higher than the melting temperature |
D. | At 100 degrees |
Answer» C. At a temperature higher than the melting temperature | |
16. |
Choose the correct statement in order to enrich rare species. |
A. | The most basic principle relies on the kinetics of hybridization |
B. | A collection of single stranded molecules is allowed to reanneal under given conditions |
C. | The strands which are less abundant are able to find their complement easily |
D. | The left over molecules are more abundant in nature |
Answer» B. A collection of single stranded molecules is allowed to reanneal under given conditions | |
17. |
The process of finding a particular member of the library which is having some defined properties is called as ___________ |
A. | searching |
B. | screening |
C. | locating |
D. | narrowing |
Answer» C. locating | |
18. |
In two hybrid screening system, the activator binds through _______ domain to a sequence upstream of the gene under its control, and ________ domain stimulates transcription. |
A. | DNA binding, activation |
B. | Activation, DNA binding |
C. | Activation, transcription |
D. | DNA binding, transcription |
Answer» B. Activation, DNA binding | |
19. |
The process of baking or cross-linking of the membrane is carried out by ___________ |
A. | By heating at 80 degrees |
B. | By irradiating with UV |
C. | Both irradiation and heating method are used |
D. | By addition of agarose |
Answer» D. By addition of agarose | |
20. |
If the screening of the DNA constructs is carried out in pooled batches then it takes less time. |
A. | True |
B. | False |
C. | May be True or False |
D. | Can't say |
Answer» B. False | |
21. |
If the gene to be screened belongs to prokaryotic species then there are chances that it is not expressed. |
A. | True |
B. | False |
C. | May be True or False |
D. | Can't say |
Answer» B. False | |
22. |
The first primer in the case of 3’ RACE is ___________ |
A. | internal sequence |
B. | oligo-dT adaptor molecule |
C. | oligo-dA adaptor molecule |
D. | adaptor oligo-dT primer |
Answer» C. oligo-dA adaptor molecule | |
23. |
Choose the correct statement for RACE. |
A. | It stands for Random Amplification of cDNA ends |
B. | It is for cloning particular cDNA ends |
C. | It is only of one type, which is 5’ RACE |
D. | Sequence data is not available in any case |
Answer» C. It is only of one type, which is 5’ RACE | |
24. |
_____ should enter the cell in the case of activation of the reporter gene for two hybrid system. |
A. | Bait protein |
B. | Prey protein |
C. | Both bait and prey protein |
D. | Either one of them |
Answer» D. Either one of them | |
25. |
During storage, there are chances of degradation of DNA. Larger fragments are having more chances of being got lost. |
A. | True |
B. | False |
C. | May be True or False |
D. | Can't say |
Answer» B. False | |
26. |
Poly A tail from the column is eluted by using high salt concentration. |
A. | True |
B. | False |
C. | May be True or False |
D. | Can't say |
Answer» C. May be True or False | |
27. |
Choose the incorrect statement for oligo-dT cellulose. |
A. | It is used for separation of polyadenylated mRNA from another mRNA |
B. | oligo-dT are covalently attached to the solid support via OH bonds |
C. | A solution containing RNA is passed through the column |
D. | Poly A tail attaches to the oligo-dT by ionic bonds |
Answer» E. | |
28. |
Complete digestion is preferred over partial digestion for the fragmentation of DNA. |
A. | True |
B. | False |
C. | May be True or False |
D. | Can't say |
Answer» C. May be True or False | |
29. |
If the library to be screened and the host belongs to different species, then it is called as ___________ |
A. | homologous selection |
B. | heterologous selection |
C. | intraspecies selection |
D. | mixed selection |
Answer» C. intraspecies selection | |
30. |
The direct selection allows _______ number of recombinants to be screened and _______ |
A. | less, slowly |
B. | less, quickly |
C. | more, quickly |
D. | more, slowly |
Answer» D. more, slowly | |
31. |
Polyadenylation of RNA species is an important criterion for the production of cDNA species. Which of the following holds true? |
A. | Polyadenylation should be at 3’ end |
B. | Eukaryotic mRNAs are mostly non-polyadenylated |
C. | Bacterial mRNAs and organelle mRNAs are polyadenylated |
D. | It is carried out by the addition of T residues after synthesis |
Answer» B. Eukaryotic mRNAs are mostly non-polyadenylated | |
32. |
If hybridization is carried out with a clone having a sequence similar to that of the vector from which library has been constructed, then it is of no use. Choose the correct statement in respect to it. |
A. | PCR amplification of the probe can be carried out |
B. | Excision of the probe should be carried out which should be followed polyacrylamide gel electrophoresis |
C. | If the vector sequence and the DNA probe are having similarities, some of the vector would be hybridized |
D. | Probe should be in a vector that is having some sequence similarity with the library to be screened |
Answer» B. Excision of the probe should be carried out which should be followed polyacrylamide gel electrophoresis | |
33. |
How many techniques are there for carrying out the screening of sequences encoding for RNAs? |
A. | 1 |
B. | 2 |
C. | 3 |
D. | 4 |
Answer» C. 3 | |
34. |
Choose the incorrect statement for cDNA libraries. |
A. | They constitute of DNA copies produced from the RNA sequences and usually mRNA |
B. | They represent expressed sequences |
C. | Introns are not represented |
D. | Comparison of cDNA sequences with genomic sequences leads to the determination of polyadenylation sites |
Answer» D. Comparison of cDNA sequences with genomic sequences leads to the determination of polyadenylation sites | |
35. |
After hybridization how the position of the labelled DNA probe is determined? |
A. | By staining |
B. | By UV irradiation |
C. | By using chemiluminescence |
D. | By electronic microscope |
Answer» D. By electronic microscope | |
36. |
What would not happen if the RNA strand is completely removed from RNA: DNA hybrid? |
A. | There are no chances of the synthesis of the second DNA strand |
B. | Chance complementarity would take place |
C. | Hairpin structure would be formed |
D. | Hairpin structure is formed is not the final structure |
Answer» B. Chance complementarity would take place | |
37. |
Choose the correct statement for modification of homopolymer tailing method. |
A. | It includes modification of primers |
B. | Primers are varied by simply altering their size by randomly adding or removing bases |
C. | The 5’ end of the first cDNA strand is tailed with C residues |
D. | A single stranded oilgonucleotide is then used for second strand synthesis |
Answer» B. Primers are varied by simply altering their size by randomly adding or removing bases | |
38. |
The polypeptides produced after addition of mRNA are analysed with antibodies. Choose the incorrect statement for this analysis. |
A. | Antibodies are added to each reaction tube and precipitation is simply based on antigen-antibody reaction |
B. | Along with simple antigen-antibody complex, a substrate is added for easy precipitation |
C. | Protein A-Sepharose is added |
D. | Protein A-Sepharose binds to IgG antibodies |
Answer» B. Along with simple antigen-antibody complex, a substrate is added for easy precipitation | |
39. |
Which of the statement holds true? |
A. | The tracer is treated with an enzyme which generates compatible ends |
B. | The driver is treated with an enzyme which generates compatible ends |
C. | Both driver and tracer are treated with an enzyme to generate compatible ends |
D. | Both driver and tracer are treated with an enzyme to generate incompatible ends |
Answer» B. The driver is treated with an enzyme which generates compatible ends | |
40. |
What is done after the recovery of pellets has been carried out in order to know the amount of polypeptides? |
A. | Denaturing and gel electrophoresis in SDS- Polyacryamide gel |
B. | Gel electrophoresis in agarose gel |
C. | Quantitative PCR |
D. | Weighing pellets |
Answer» B. Gel electrophoresis in agarose gel | |
41. |
What is done after RNA fractionation is carried out? |
A. | Each band is translated in vivo |
B. | Translation is carried out in wheat gram or lysate of rabbit reticulocyte cells |
C. | Translation is carried out with a high background |
D. | Amino acid is not radioactively labelled |
Answer» C. Translation is carried out with a high background | |
42. |
What do we mean by housekeeping genes? |
A. | Housekeeping genes are those genes which are specific to an organism |
B. | Housekeeping genes are those genes which are present in all the organisms |
C. | Housekeeping genes are those genes which are meant for repair and maintenance in a species of organism |
D. | Housekeeping genes are those genes which required for the replication process |
Answer» C. Housekeeping genes are those genes which are meant for repair and maintenance in a species of organism | |
43. |
If screening is carried out on the basis of sequences which are related to the desired sequence, then the process is called ___________ |
A. | in-silico |
B. | homologue search |
C. | annotation |
D. | partial search |
Answer» D. partial search | |
44. |
Choose the incorrect statement with respect to the membranes used for adhering of bacterial cells onto them. |
A. | Nitrocellulose membranes were preferred earlier |
B. | They bind DNA very efficiently |
C. | They can be handled easily without breakage |
D. | They are inflammable |
Answer» D. They are inflammable | |
45. |
The important parameters for precise annealing of the probe and the subsequent washing don’t include ___________ |
A. | Size of the probe |
B. | Proportion of only A |
C. | Ionic concentration of hybridization buffer |
D. | Other agents which alter the base pairing |
Answer» C. Ionic concentration of hybridization buffer | |
46. |
Choose the correct statement with respect to the self priming method of cDNA synthesis. |
A. | It is less preferred than RNaseH method |
B. | A hairpin structure is formed with guarantee |
C. | The sequence corresponding to the 5’ end is lost |
D. | Reverse transcriptase is not used |
Answer» D. Reverse transcriptase is not used | |
47. |
Sometimes a gene which we want to clone is present on a particular chromosome. For this purpose, the chromosome should be in which phase? |
A. | Prophase |
B. | Telophase |
C. | Metaphase |
D. | Anaphase |
Answer» D. Anaphase | |
48. |
Choose the incorrect statement for panning. |
A. | It is a variant of ligand binding approach |
B. | The ligand is immobilized on the solid support and the cells are passed over it |
C. | If the ligand-binding domain is exposed on surface of the any recombinant molecules then they will bind to ligand |
D. | They are not useful for scanning libraries in cultured mammalian cells |
Answer» E. | |
49. |
The various steps for construction of libraries are ___________i) Fragmentation of DNAii) Isolation of genomic DNAiii) Amplificationiv) Ligation and introduction to the hostv) Vector preparationThe correct order of construction of libraries is (In the order of starting to ending). |
A. | i)-ii)-iii)-iv)-v) |
B. | ii)-i)-v)-iv)-iii) |
C. | ii)-v)-i)-iv)-iii) |
D. | v)-ii)-i)-iii)-iv) |
Answer» C. ii)-v)-i)-iv)-iii) | |
50. |
Choose the incorrect statement with respect to host used. |
A. | The host must carry mutation for the gene of interest |
B. | The host should not contain restriction enzymes |
C. | The host if having restriction enzymes, then the incoming DNA should not be methylated |
D. | The host should be deficient in recombination |
Answer» D. The host should be deficient in recombination | |