MCQOPTIONS
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MCQOPTIONS
This section includes 187 Mcqs, each offering curated multiple-choice questions to sharpen your Civil Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 151. |
For structural analysis, Maxwell’s reciprocal theorem can be applied to: |
| A. | Plastic structures |
| B. | Elastic structures |
| C. | Symmetrical structures |
| D. | All the above |
| Answer» C. Symmetrical structures | |
| 152. |
The resolved part of the resultant of two forces inclined at an angle in a given direction is equal to |
| A. | The algebraic sum of the resolved parts of the forces in the given direction |
| B. | The sum of the resolved parts of the forces in the given direction |
| C. | The difference of the forces multiplied by the cosine of |
| D. | The sum of the forces multiplied by the sine of |
| Answer» B. The sum of the resolved parts of the forces in the given direction | |
| 153. |
If a circular beam of diameter d experiences a longitudinal strain P/E and a lateral strain 2P/mE, the volumetric strain is |
| A. | (P/E) + (2P/mE) |
| B. | (P/E) – (2P/mE) |
| C. | (P/E) + (mE/2P) |
| D. | (P/E) – (mE/2P |
| Answer» C. (P/E) + (mE/2P) | |
| 154. |
A bending moment may be defined as |
| A. | Arithmetic sum of the moments of all the forces on either side of the section |
| B. | Arithmetic sum of the forces on either side of the section |
| C. | Algebraic sum of the moments of all the forces on either side of the section |
| D. | None of these |
| Answer» D. None of these | |
| 155. |
The unit of force in S.I. units is |
| A. | Kilogram |
| B. | Newton |
| C. | Watt |
| D. | Dyne |
| Answer» C. Watt | |
| 156. |
The property of a material by which it can be drawn to a smaller section, due to tension, is called |
| A. | Plasticity |
| B. | Ductility |
| C. | Elasticity |
| D. | Malleability |
| Answer» C. Elasticity | |
| 157. |
In ideal machines |
| A. | Mechanical advantage is greater than velocity ratio |
| B. | Mechanical advantage is equal to velocity ratio |
| C. | Mechanical advantage is less than velocity ratio |
| D. | Mechanical advantage is unity |
| Answer» C. Mechanical advantage is less than velocity ratio | |
| 158. |
A long vertical member, subjected to an axial compressive load, is called |
| A. | A column |
| B. | A strut |
| C. | A tie |
| D. | A stanchion |
| Answer» B. A strut | |
| 159. |
The tensile force required to cause an elongation of 0.045 mm in a steel rod of 1000 mm length and 12 mm diameter, is (where E = 2 × 106 kg/cm2) |
| A. | 166 kg |
| B. | 102 kg |
| C. | 204 kg |
| D. | 74 kg |
| Answer» C. 204 kg | |
| 160. |
The M.I. of hollow circular section about a central axis perpendicular to section as compared to its M.I. about horizontal axis is |
| A. | Same |
| B. | Double |
| C. | Half |
| D. | Four times |
| Answer» C. Half | |
| 161. |
Beams of uniform strength are preferred to those of uniform section because these are economical for |
| A. | Large spans |
| B. | Heavy weights |
| C. | Light weights |
| D. | Short spans |
| Answer» B. Heavy weights | |
| 162. |
The maximum frictional force which comes into play when a body just begins to slide over another surface is called |
| A. | Limiting friction |
| B. | Sliding friction |
| C. | Rolling friction |
| D. | Kinematic friction |
| Answer» B. Sliding friction | |
| 163. |
In a solid arch, shear force acts |
| A. | Vertically upwards |
| B. | Along the axis of the arch |
| C. | Perpendicular to the axis of arch |
| D. | Tangentially to the arch |
| Answer» D. Tangentially to the arch | |
| 164. |
If rain is falling in the opposite direction of the movement of a pedestrian, he has to hold his umbrella |
| A. | More inclined when moving |
| B. | Less inclined when moving |
| C. | More inclined when standing |
| D. | Less inclined when standing |
| Answer» E. | |
| 165. |
The under mentioned type is simple strain |
| A. | Tensile strain |
| B. | Compressive strain |
| C. | Shear strain |
| D. | All the above |
| Answer» E. | |
| 166. |
If a three hinged parabolic arch carries a uniformly distributed load on its entire span, every section of the arch resists |
| A. | Compressive force |
| B. | Tensile force |
| C. | Shear force |
| D. | Bending moment |
| Answer» B. Tensile force | |
| 167. |
The ratio of limiting friction and normal reaction is known as |
| A. | Coefficient of friction |
| B. | Angle of friction |
| C. | Angle of repose |
| D. | Sliding friction |
| Answer» B. Angle of friction | |
| 168. |
A beam is said to be of uniform strength, if |
| A. | B.M. is same throughout the beam |
| B. | Deflection is same throughout the beam |
| C. | Bending stress is same throughout the beam |
| D. | Shear stress is same throughout the beam |
| Answer» D. Shear stress is same throughout the beam | |
| 169. |
A heavy string attached at two ends at same horizontal level and when central dip is very small approaches the following curve |
| A. | Catenary |
| B. | Parabola |
| C. | Hyperbola |
| D. | Elliptical |
| Answer» C. Hyperbola | |
| 170. |
The deflection of any rectangular beam simply supported, is |
| A. | Directly proportional to its weight |
| B. | Inversely proportional to its width |
| C. | Inversely proportional to the cube of its depth |
| D. | Directly proportional to the cube of its length |
| Answer» D. Directly proportional to the cube of its length | |
| 171. |
The maximum twisting moment a shaft can resist, is the product of the permissible shear stress and |
| A. | Moment of inertia |
| B. | Polar moment of inertia |
| C. | Polar modulus |
| D. | Modulus of rigidly |
| Answer» D. Modulus of rigidly | |
| 172. |
The center of gravity of a uniform lamina lies at |
| A. | The center of heavy portio |
| B. | The bottom surface |
| C. | The midpoint of its axis |
| D. | All of the above |
| Answer» D. All of the above | |
| 173. |
Kinetic friction is the |
| A. | Tangent of angle between normal reaction and the resultant of normal reaction and the limiting friction |
| B. | Ratio of limiting friction and normal reaction |
| C. | The friction force acting when the body is just about to move |
| D. | The friction force acting when the body is in motion |
| Answer» E. | |
| 174. |
If a suspended body is struck at the centre of percussion, then the pressure on die axis passingv through the point of suspension will be |
| A. | Maximum |
| B. | minimum |
| C. | Zero |
| D. | Infinity |
| Answer» D. Infinity | |
| 175. |
Two coplanar couples having equal and opposite moments |
| A. | Balance each other |
| B. | Produce a couple and an unbalanced force |
| C. | Are equivalent |
| D. | Produce a moment of couple |
| Answer» E. | |
| 176. |
If a number of forces act simultaneously on a particle, it is possible |
| A. | Not a replace them by a single force |
| B. | To replace them by a single force |
| C. | To replace them by a single force through C.G. |
| D. | To replace them by a couple |
| Answer» C. To replace them by a single force through C.G. | |
| 177. |
Which of the following do not have identical dimensions? |
| A. | Momentum and impulse |
| B. | Torque and energy |
| C. | Torque and work |
| D. | Moment of a force and angular momentum |
| Answer» E. | |
| 178. |
According to principle of transmissibility of forces, the effect of a force upon a body is |
| A. | Maximum when it acts at the center of gravity of a body |
| B. | Different at different points in its line of action |
| C. | The same at every point in its line of action |
| D. | Minimum when it acts at the C.G. of the body |
| Answer» D. Minimum when it acts at the C.G. of the body | |
| 179. |
determining stresses in frames by methods of sections, the frame is divided into two parts by an imaginary section drawn in such a way as not to cut more than |
| A. | Two members with unknown forces of the frame |
| B. | Three members with unknown forces of the frame |
| C. | Four members with unknown forces of the frame |
| D. | Three members with known forces of the frame |
| Answer» C. Four members with unknown forces of the frame | |
| 180. |
A cable with a uniformly distributed load per horizontal metre run will take the following shape |
| A. | Straight line |
| B. | Parabola |
| C. | Hyperbola |
| D. | Elliptical |
| Answer» C. Hyperbola | |
| 181. |
Which of the following is the example of lever of first order? |
| A. | Arm of man |
| B. | Pair of scissors |
| C. | Pair of clinical tongs |
| D. | All of the above |
| Answer» E. | |
| 182. |
The necessary condition for forces to be in equilibrium is that these should be |
| A. | Coplanar |
| B. | Meet at one point |
| C. | Both (A) and (B) above |
| D. | All be equal |
| Answer» D. All be equal | |
| 183. |
Limiting force of friction is the |
| A. | Tangent of angle between normal reaction and the resultant of normal reaction and limiting friction |
| B. | Ratio of limiting friction and normal reaction |
| C. | The friction force acting when the body is just about to move |
| D. | The friction force acting when the body is in motion |
| Answer» D. The friction force acting when the body is in motion | |
| 184. |
Angle of friction is the |
| A. | Angle between normal reaction and the resultant of normal reaction and the limiting friction |
| B. | Ratio of limiting friction and normal reaction |
| C. | The ratio of minimum friction force to the friction force acting when the body is just about to move |
| D. | The ratio of minimum friction force to friction force acting when the body is in motion` |
| Answer» B. Ratio of limiting friction and normal reaction | |
| 185. |
The center of gravity of a triangle lies at the point of |
| A. | Concurrence of the medians |
| B. | Intersection of its altitudes |
| C. | Intersection of bisector of angles |
| D. | Intersection of diagonals |
| Answer» B. Intersection of its altitudes | |
| 186. |
A number of forces acting at a point will be in equilibrium if |
| A. | Their total sum is zero |
| B. | Two resolved parts in two directions at right angles are equal |
| C. | Sum of resolved parts in any two perpendicular directions are both zero |
| D. | All of them are inclined equally |
| Answer» D. All of them are inclined equally | |
| 187. |
According to Lami’s theorem |
| A. | Three forces acting at a point will be in equilibrium |
| B. | Three forces acting at a point can be represented by a triangle, each side being proportional to force |
| C. | If three forces acting upon a particle are represented in magnitude and direction by the sides of a triangle, taken in order, they will be in equilibrium |
| D. | If three forces acting at a point are in equilibrium, each force is proportional to the sine of the angle between the other two |
| Answer» E. | |