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This section includes 2291 Mcqs, each offering curated multiple-choice questions to sharpen your Engineering knowledge and support exam preparation. Choose a topic below to get started.
1651. |
When decisions demand two possible actions, the IF/THEN/ELSE control structure is used. |
A. | True |
B. | False |
Answer» B. False | |
1652. |
The 54 prefix on ICs indicates a broader operating temperature range, generally intended for military use. |
A. | True |
B. | False |
Answer» B. False | |
1653. |
This is an example of a POS expression: |
A. | True |
B. | False |
Answer» B. False | |
1654. |
A data selector is also called a demultiplexer. |
A. | True |
B. | False |
Answer» C. | |
1655. |
An exclusive-OR gate will invert a signal on one input if the other is always HIGH. |
A. | True |
B. | False |
Answer» B. False | |
1656. |
TTL stands for transistor-technology-logic. |
A. | True |
B. | False |
Answer» C. | |
1657. |
The following combination is correct for an EVEN parity data transmission system: data = 100111100 and parity = 0 |
A. | True |
B. | False |
Answer» C. | |
1658. |
The circuit given below implements the equation, . |
A. | True |
B. | False |
Answer» B. False | |
1659. |
The abbreviation for an exclusive-OR gate is XOR. |
A. | True |
B. | False |
Answer» B. False | |
1660. |
In an even-parity system, the parity bit is adjusted to make an even number of one bits. |
A. | True |
B. | False |
Answer» B. False | |
1661. |
The XOR gate will produce a HIGH output if only one but not both of the inputs is HIGH. |
A. | True |
B. | False |
Answer» B. False | |
1662. |
When decisions demand one of many possible actions, the ELSIF control structure is used. |
A. | True |
B. | False |
Answer» B. False | |
1663. |
The CASE control structure is used when an expression has a list of possible values. |
A. | True |
B. | False |
Answer» B. False | |
1664. |
In VHDL, data can be each of the following types except ________. |
A. | BIT |
B. | BIT_VECTOR |
C. | STD_LOGIC |
D. | STD_VECTOR |
Answer» E. | |
1665. |
When grouping cells within a K-map, the cells must be combined in groups of ________. |
A. | 2's |
B. | 1, 2, 4, 8, etc. |
C. | 4's |
D. | 3's |
Answer» C. 4's | |
1666. |
The ________ circuit produces a HIGH output whenever the two inputs are unequal. |
A. | exclusive-AND |
B. | exclusive-NOR |
C. | exclusive-OR |
D. | inexclusive-OR |
Answer» D. inexclusive-OR | |
1667. |
The Boolean equation ________ results from this Karnaugh map. |
A. | <img src="/_files/images/digital-electronics/digital-systems/fba4_1020a1.gif" align="center"> |
B. | <img src="/_files/images/digital-electronics/digital-systems/fba4_1020b1.gif" align="center"> |
C. | <img src="/_files/images/digital-electronics/digital-systems/fba4_1020c1.gif" align="center"> |
D. | <img src="/_files/images/digital-electronics/digital-systems/fba4_1020d1.gif" align="center"> |
Answer» B. <img src="/_files/images/digital-electronics/digital-systems/fba4_1020b1.gif" align="center"> | |
1668. |
The ________ series of IC's are pin, function, and voltage-level compatible with the 74 series IC's. |
A. | ALS |
B. | CMOS |
C. | HCT |
D. | 2N |
Answer» D. 2N | |
1669. |
The simplified form of is ________. |
A. | <img src="/_files/images/digital-electronics/digital-systems/fba4_1015a1.jpeg"> |
B. | <img src="/_files/images/digital-electronics/digital-systems/fba4_1015b1.jpeg"> |
C. | <img src="/_files/images/digital-electronics/digital-systems/fba4_1015c1.jpeg"> |
D. | <img src="/_files/images/digital-electronics/digital-systems/fba4_1015d1.jpeg"> |
Answer» E. | |
1670. |
The ________ circuit produces a HIGH output whenever the two inputs are equal. |
A. | exclusive-AND |
B. | exclusive-NAND |
C. | exclusive-NOR |
D. | exclusive-OR |
Answer» D. exclusive-OR | |
1671. |
A 4-bit adder has the following inputs: C0 = 0, A1 = 0, A2 = 1, A3 = 0, A4 = 1, B1 = 0, B2 = 1, B3 = 1, B4 = 1. The output will be ________. |
A. | 01100 |
B. | 10101 |
C. | 11000 |
D. | 00011 |
Answer» D. 00011 | |
1672. |
The ________ statement evaluates the variable status. |
A. | IF/THEN |
B. | IF/THEN/ELSE |
C. | CASE |
D. | ELSIF |
Answer» B. IF/THEN/ELSE | |
1673. |
An 8-bit binary number is input to an odd parity generator. The parity bit will equal 1 only if ________. |
A. | the number is odd |
B. | the number of 1s in the number is odd |
C. | the number is even |
D. | the number of 1s in the number is even |
Answer» E. | |
1674. |
Two 4-bit comparators are cascaded to form an 8-bit comparator. The cascading inputs of the most significant 4 bits should be connected ________. |
A. | to the outputs from the least significant 4-bit comparator |
B. | to the cascading inputs of the least significant 4-bit comparator |
C. | A = B to a logic high, A < b and a > B to a logic low |
D. | ground |
Answer» B. to the cascading inputs of the least significant 4-bit comparator | |
1675. |
When Karnaugh mapping, we must be sure to use the ________ number of loops. |
A. | maximum |
B. | minimum |
C. | median |
D. | Karnaugh |
Answer» C. median | |
1676. |
The final output of a POS circuit is generated by ________. |
A. | an AND |
B. | an OR |
C. | a NOR |
D. | a NAND |
Answer» B. an OR | |
1677. |
The correct output for this XOR truth table is ________. |
A. | <img src="/_files/images/digital-electronics/digital-systems/fba4_1022a1.gif" align="center"> |
B. | <img src="/_files/images/digital-electronics/digital-systems/fba4_1022b1.gif" align="center"> |
C. | <img src="/_files/images/digital-electronics/digital-systems/fba4_1022c1.gif" align="center"> |
D. | <img src="/_files/images/digital-electronics/digital-systems/fba4_1022d1.gif" align="center"> |
Answer» E. | |
1678. |
In an odd-parity system, the data that will produce a parity bit = 1 is ________. |
A. | data = 1010011 |
B. | data = 1111000 |
C. | data = 1100000 |
D. | All of the above |
Answer» E. | |
1679. |
Except for ________, STD_LOGIC may have the following values. |
A. | 'z' |
B. | 'U' |
C. | '?' |
D. | 'L' |
Answer» D. 'L' | |
1680. |
A gate that could be used to compare two logic levels and provide a HIGH output if they are equal is a(n) ________. |
A. | XOR gate |
B. | XNOR gate |
C. | NAND gate |
D. | NOR gate |
Answer» C. NAND gate | |
1681. |
VHDL is very strict in the way it allows us to assign and compare ________ such as signals, variables, constants, and literals. |
A. | objects |
B. | LOGIC_VECTORS |
C. | designs |
D. | arrays |
Answer» B. LOGIC_VECTORS | |
1682. |
The AND-OR-INVERT gates are designed to simplify implementation of ________. |
A. | POS logic |
B. | DeMorgan's theorem |
C. | NAND logic |
D. | SOP logic |
Answer» C. NAND logic | |
1683. |
If you need a NAND, an AND, and an inverter you would purchase a 7400 IC. |
A. | True |
B. | False |
Answer» B. False | |
1684. |
The systematic reduction of logic circuits is performed using Boolean algebra. |
A. | True |
B. | False |
Answer» B. False | |
1685. |
CPLD software can be used to design original circuits that prove the Boolean rules and laws. |
A. | True |
B. | False |
Answer» B. False | |
1686. |
A Karnaugh map is similar to a truth table. |
A. | True |
B. | False |
Answer» B. False | |
1687. |
Occasionally, a particular logic expression will be of no consequence in the operation of a circuit, such as in a BCD-to-decimal converter. These result in ________ terms in the K-map and can be treated as either ________ or ________, in order to ________ the resulting term. |
A. | don't care, 1's, 0's, simplify |
B. | spurious, AND's, OR's, eliminate |
C. | duplicate, 1's, 0's, verify |
D. | spurious, 1's, 0's, simplify |
Answer» B. spurious, AND's, OR's, eliminate | |
1688. |
After each circuit in a subsection of a VHDL program has been ________, they can be combined and the subsection can be tested. |
A. | designed |
B. | tested |
C. | engineered |
D. | produced |
Answer» C. engineered | |
1689. |
A Karnaugh map will ________. |
A. | eliminate the need for tedious Boolean simplifications |
B. | allow any circuit to be implemented with just AND and OR gates |
C. | produce the simplest sum-of-products expression |
D. | give an overall picture of how the signals flow through the logic circuit |
Answer» B. allow any circuit to be implemented with just AND and OR gates | |
1690. |
The symbol shown below is for a 2-input NAND gate. |
A. | True |
B. | False |
Answer» C. | |
1691. |
SOP stands for sum-of-powers. |
A. | True |
B. | False |
Answer» C. | |
1692. |
The VHDL editor provided with a schematic editor development system will produce a file with the extension .vhd, which can be used by the simulator to test the output of the logic design. |
A. | True |
B. | False |
Answer» B. False | |
1693. |
In the commutative law, in ORing and ANDing of two variables, the order in which the variables are ORed or ANDed makes no difference. |
A. | True |
B. | False |
Answer» B. False | |
1694. |
The binary value of 1010 is converted to the product term . |
A. | True |
B. | False |
Answer» C. | |
1695. |
Most Boolean reductions result in an equation in only one form. |
A. | True |
B. | False |
Answer» C. | |
1696. |
Boolean algebra simplifies logic circuits. |
A. | True |
B. | False |
Answer» B. False | |
1697. |
The Boolean expression is equal to ________. |
A. | C |
B. | D |
C. | C + D |
D. | 1 |
Answer» D. 1 | |
1698. |
The Boolean expression can be reduced to ________. |
A. | <img src="/_files/images/digital-electronics/digital-fundamentals/cua4_0070a.gif"> |
B. | <img src="/_files/images/digital-electronics/digital-fundamentals/cua4_0070b.gif"> |
C. | <img src="/_files/images/digital-electronics/digital-fundamentals/cua4_0070c.gif"> |
D. | <img src="/_files/images/digital-electronics/digital-fundamentals/cua4_0070d.gif"> |
Answer» E. | |
1699. |
Generally speaking, DACs with a current output will have a shorter settling time than those with voltage outputs. |
A. | True |
B. | False |
Answer» B. False | |
1700. |
A D/A converter changes things such as temperature variations into digital quantities. |
A. | True |
B. | False |
Answer» C. | |