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This section includes 646 Mcqs, each offering curated multiple-choice questions to sharpen your ENGINEERING SERVICES EXAMINATION (ESE) knowledge and support exam preparation. Choose a topic below to get started.
51. |
Let the impulse response of an LTI system be h(t) = e-tu(t). Find the output y(T) if the input is x(t) = u(t) |
A. | y(t) = e-tu(t) |
B. | y(t) = etu(t) |
C. | y(t) = (1-et)u(t) |
D. | y(t) = (1 – e-t)u(t) |
Answer» E. | |
52. |
Based on the given para, answer the following question.Sensitivity considerations often are important in the design of Control Systems. Because all physical elements have properties that change with environment and age, we cannot always consider the parameters of the Control System to be completely stationary over the entire operating life of the system. For instance, the winding resistance of electric motor changes as the temperature of the motor rises during operation. Control systems with electric components may not operate normally when first turned on because of the still-changing system parameters during warmup. This phenomenon is sometimes called “morning sickness”. Most duplicating machines have a warmup period during which time operation is blocked out when first turn on.Which of the following statements is correct? |
A. | Feedback can only increase the sensitivity of a system |
B. | Feedback can increase or decrease the sensitivity of a system |
C. | Feedback can only decrease the sensitivity of a system |
D. | Feedback never affects the sensitivity of a system |
Answer» C. Feedback can only decrease the sensitivity of a system | |
53. |
Impulse response of an LTI system is h(t) = e-t u(t). Suppose if the input x(t) = u(t), then the output would be: |
A. | Y(t) = (1 – 2e-t) u(t) |
B. | Y(t) = (1 – e-2t) u(t) |
C. | Y(t) = (1 – e-t) u(t) |
D. | Y(t) = (1 – 2e-2t) u(t) |
Answer» D. Y(t) = (1 – 2e-2t) u(t) | |
54. |
If the input and output of a system is related by the following differential equation, then find its transfer function.\(\frac{{{d^2}y\left( t \right)}}{{dt}} + 3\frac{{dy\left( t \right)}}{{dt}} + 2y\left( t \right) = u\left( t \right) + \frac{{du\left( t \right)}}{{dt}}\) |
A. | \( TF = \frac{s+1}{{{s^2} + 3s + 2}}\) |
B. | \( TF = \frac{1}{{{s^2} + 3s + 2}}\) |
C. | \( TF = \frac{s+2}{{{s^2} + 3s + 2}}\) |
D. | \( TF = \frac{s-1}{{{s^2} + 3s + 2}}\) |
Answer» B. \( TF = \frac{1}{{{s^2} + 3s + 2}}\) | |
55. |
Based on the given para, answer the following question.Sensitivity considerations often are important in the design of Control Systems. Because all physical elements have properties that change with environment and age, we cannot always consider the parameters of the Control System to be completely stationary over the entire operating life of the system. For instance, the winding resistance of an electric motor changes as the temperature of the motor rises during operation. Control systems with electric components may not operate normally when first turned on because of the still-changing system parameters during warmup. This phenomenon is sometimes called “morning sickness”. Most duplicating machines have a warmup period during which time operation is blocked out when first turn on.For an open-loop control system, sensitivity of overall transfer function M(s) with respect to forward path transfer function G(s) will be: |
A. | 1 |
B. | 0 |
C. | -1 |
D. | ∞ |
Answer» B. 0 | |
56. |
An open-loop control system is one in which the control action: |
A. | Depends on the input signal |
B. | Is independent of the desired output |
C. | Depends on system variables |
D. | Depends on system size |
Answer» C. Depends on system variables | |
57. |
Determine the output C in terms of E. |
A. | C = G1G2E |
B. | C = G1 - G2 E |
C. | \(C=\dfrac{G_1}{G_2} E\) |
D. | C = G1 + G2 E |
Answer» B. C = G1 - G2 E | |
58. |
Consider a linear time-invariant system whose input r(t) and output y(t) are related by the following differential equation:\(\frac{{{d^2}y\left( t \right)}}{{d{t^2}}} + 4y\left( t \right) = 6r\left( t \right)\)The poles of this system are at |
A. | +2j, -2j |
B. | +2, -2 |
C. | +4, -4 |
D. | +4j, -4j |
Answer» B. +2, -2 | |
59. |
A cybernetic control system that acts to reduce deviations from standard is called |
A. | a negative feedback loop |
B. | a positive feedback loop |
C. | a closed loop |
D. | an open loop |
Answer» B. a positive feedback loop | |
60. |
A servomotor is mainly used for |
A. | position control |
B. | velocity control |
C. | acceleration control |
D. | both velocity and acceleration control |
Answer» B. velocity control | |
61. |
A first order linear system is initially relaxed for a unit step signal u(t), the response is v(t) = (1 – e-3t), for t > 0. If a signal 3u(t) + δ(t) is applied to the same system, the response is |
A. | (3 – 6e-3t) u(t) |
B. | (3 – 3e-3t) u(t) |
C. | 3u(t) |
D. | (3 + 3e3t) u(t) |
Answer» D. (3 + 3e3t) u(t) | |
62. |
Let a causal LTI system be characterized by the following differential equation, with initial rest condition\(\frac{{{d^2}y}}{{d{t^2}}} + 7\frac{{dy}}{{dt}} + 10y\left( t \right) = 4x\left( t \right) + 5\frac{{dx\left( t \right)}}{{dt}}\)where x(t) and y(t) are the input and output respectively. The impulse response of the system is (u(t) is the unit step function) |
A. | 2e-2tu(t) – 7 e-5tu(t) |
B. | –2e-2tu(t) + 7 e-5tu(t) |
C. | 7e-2tu(t) – 2 e-5tu(t) |
D. | –7e-2tu(t) + 2 e-5tu(t) |
Answer» C. 7e-2tu(t) – 2 e-5tu(t) | |
63. |
In the force-voltage analogy, voltage V corresponds to: |
A. | Damper |
B. | Displacement |
C. | Spring Constant |
D. | Torque |
Answer» E. | |
64. |
For a given differential equation, \(\frac{{{d^2}y\left( t \right)}}{{d{t^2}}} + 4\frac{{dyt)}}{{dt}} + 5y\left( t \right) = 5x\left( t \right)\) with \(y\left( {{0^ - }} \right) = 1\;and\;{\left. {\frac{{dy\left( t \right)}}{{dt}}} \right|_{{0^ - }}} = 2\) and input x(t) = u(t). The output y(t) will be |
A. | 2u(t) – 2e-2t sin t |
B. | u(t) + 2e-2t sin t |
C. | u(t) – e-t sin t |
D. | 2u(t) + e-t sin t |
Answer» C. u(t) – e-t sin t | |
65. |
A system has the transfer function \(\frac{1-s}{1+s}\). It is a |
A. | non-minimum phase system |
B. | minimum phase system |
C. | low pass system |
D. | second order system |
Answer» B. minimum phase system | |
66. |
In an automobile driving system, function of actuator is being performed by |
A. | accelerator only |
B. | brakes only |
C. | both accelerator and brakes |
D. | wheels only |
Answer» D. wheels only | |
67. |
In a positive feedback control system, the feedback signal is ______ with respect to the input signal. |
A. | out of phase |
B. | lagging by 90° |
C. | in phase |
D. | leading by 90° |
Answer» D. leading by 90° | |
68. |
By increasing the gain K of type 1 system, for a step input, the steady state error |
A. | increases |
B. | decreases |
C. | remains unaltered at a positive non zero value |
D. | remains zero |
Answer» E. | |
69. |
Any signal that tends to affect the controlled variable other than the reference command signal is termed as: |
A. | Disturbance signal |
B. | Control signal |
C. | Command signal |
D. | Reference Input signal |
Answer» B. Control signal | |
70. |
Assertion (A): A necessary and sufficient condition for a feedback system to be stable is that all the poles of the system transfer function have negative real parts.Reason (R): To obtain a bounded response, the poles of the closed-loop system must be in the left half portion of the s-plan. |
A. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
B. | Both (A) and (R) are true, but (R) is not the correct explanation of (A) |
C. | (A) is true, but (R) is false |
D. | (A) false, but (R) is true |
Answer» B. Both (A) and (R) are true, but (R) is not the correct explanation of (A) | |
71. |
If \(G\left( s \right) = \frac{5}{s}\) and \(H\left( s \right) = \frac{1}{s}\), then this is: |
A. | Type 0 system |
B. | Type 3 system |
C. | Type 2 system |
D. | Type 1 system |
Answer» D. Type 1 system | |
72. |
In a cascade control system, the closed loop transfer function of the inner loop may be assumed to have a single time-constant τ1. Similarly, the closed loop transfer function of the outer loop may be assumed to have a single time-constant τ2. The desired relationship between τ1 and τ2 in a well-designed control system is |
A. | τ1 is much less than τ2 |
B. | τ1 is equal to τ2 |
C. | τ1 is much greater than τ2 |
D. | τ1 is independent of τ2 |
Answer» B. τ1 is equal to τ2 | |
73. |
In a transfer function, the frequencies for which the value of denominator becomes zero are called |
A. | Poles |
B. | Zeros |
C. | Roots |
D. | Solutions |
Answer» B. Zeros | |
74. |
Identify the stable system from the following systems with their characteristics equation: |
A. | s + 1 = 0 |
B. | s - 1 =0 |
C. | 2s2 - 10 = 0 |
D. | 4s2 + 10 =0 |
Answer» B. s - 1 =0 | |
75. |
For the unity feedback control system shown in the figure, the open-loop transfer function G(s) is given as\({\rm{G}}\left( {\rm{s}} \right) = \frac{2}{{{\rm{s}}\left( {{\rm{s}} + 1} \right)}}\)The steady-state error ess due to a unit step input is |
A. | 0 |
B. | 0.5 |
C. | 1 |
D. | ∞ |
Answer» B. 0.5 | |
76. |
A quiescent linear time-invariant system subjected to a unit step input u(t) has the response c(t) = te-t, t ≥ 0. Then \(\frac{{C\left( s \right)}}{{R\left( s \right)}}\) would be |
A. | \(\frac{1}{{s\left( {s + 1} \right)}}\) |
B. | \(\frac{1}{{s + 1}}\) |
C. | \(\frac{1}{{{{\left( {s + 1} \right)}^2}}}\) |
D. | None of the above |
Answer» E. | |
77. |
In an automobile driving system, eyes of the driver act as |
A. | error detector |
B. | summing block |
C. | visual link to feedback loop |
D. | feedback gain |
Answer» D. feedback gain | |
78. |
Poles are the complex frequencies of a transfer function where the response becomes |
A. | infinite |
B. | zero |
C. | oscillatory |
D. | decaying |
Answer» B. zero | |
79. |
A system with transfer function \(\frac{{Y\left( s \right)}}{{X\left( s \right)}} = \frac{s}{{s + p}}\) has an output \(y\left( t \right) = cos\left( {2t - \frac{\pi }{3}} \right)\)for the input signal \(x\left( t \right) = p\cos \left( {2t - \frac{\pi }{2}} \right)\). Then, the system parameter p is |
A. | √3 |
B. | 2 / √3 |
C. | 1 |
D. | √3 / 2 |
Answer» C. 1 | |
80. |
As compared to a closed loop system, an open loop system is |
A. | more stable as well as more accurate |
B. | less stable as well as less accurate |
C. | more stable but less accurate |
D. | less stable but more accurate |
Answer» D. less stable but more accurate | |
81. |
Following statements are given regarding the above passage:a) Automobile driving system is an open-loop control systemb) Automobile driving system is a closed-loop control systemc) Traffic signal system is a closed-loop control systemd) Traffic signal system is an open-loop control systemOut of the above statements, which are correct? |
A. | and d) are correct |
B. | and c) are correct |
C. | and c) are correct |
D. | and d) are correct |
Answer» E. | |
82. |
A Servomechanism is a feedback control system required to control |
A. | position |
B. | a derivative of position |
C. | either (a) or (b) above |
D. | none of these |
Answer» D. none of these | |
83. |
A regulator can be classified as a |
A. | type 0 system |
B. | type 1 system |
C. | type 2 system |
D. | type 3 system |
Answer» B. type 1 system | |
84. |
Consider a system with the closed loop transfer function \(C(S) = \frac{{20\left( {s + 4} \right)}}{{{s^2} + 8s + 15}}\) with input R(s) and output C(s). When all initial conditions are zero and the input is an impulse then the output c(t) is: |
A. | e-8t + 10 e-t |
B. | 10 e-3t - 10 e-5t |
C. | 10 e-3t + 10 e-5t |
D. | 20 e-8t + 5 e-15t |
Answer» D. 20 e-8t + 5 e-15t | |
85. |
Consider the following statements:The output of a linear circuit, driven with a sine wave at a frequency f, is itself a sine wave1. at the same frequency2. with a chance of changed amplitude3. with chances of changed amplitude and phaseWhich of the above statements is/are correct? |
A. | 1 and 2 |
B. | 1 only |
C. | 1 and 3 |
D. | 2 only |
Answer» D. 2 only | |
86. |
Input to a controller is the following signal: |
A. | Error signal |
B. | Servo signal |
C. | Desired Variable value |
D. | Sensed signal |
Answer» B. Servo signal | |
87. |
Out of the following. what happens to the overall gain of the system of a closed loop control system with positive value of feedback gain? |
A. | No effect |
B. | Increase |
C. | Decrease |
D. | Increase or Decrease |
Answer» C. Decrease | |
88. |
If the bandwidth of a control system is increased, the noise in the output of the system due to presence of sensor noise will |
A. | increase |
B. | decrease |
C. | not change |
D. | be zero |
Answer» B. decrease | |
89. |
A function y(t) satisfies the following differential equation:\(\frac{{dy\left( t \right)}}{{dt}} + y\left( t \right) = \delta \left( t \right)\)Where δ(t) is unit impulse function and u(t) is unit step function. Assuming zero initial conditions, what is y(t)? |
A. | et |
B. | e-t |
C. | et u(t) |
D. | e-t u(t) |
Answer» E. | |
90. |
Consider an LTI system whose response to the input x(t) = [e-t + e-3t] u(t) is y(t) = [2e-t – 2e-4t]. The system’s impulse response will be |
A. | \(\frac{3}{2}\left[ {{e^{ - 2t}} + {e^{ - 4t}}} \right]u\left( t \right)\) |
B. | \(\frac{3}{2}\left[ {{e^{ - 2t}} - {e^{ - 4t}}} \right]u\left( t \right)\) |
C. | \(\frac{1}{2}\left[ {{e^{ - 2t}} + {e^{ - 4t}}} \right]u\left( t \right)\) |
D. | \(\frac{1}{2}\left[ {{e^{ - 2t}} - {e^{ - 4t}}} \right]u\left( t \right)\) |
Answer» B. \(\frac{3}{2}\left[ {{e^{ - 2t}} - {e^{ - 4t}}} \right]u\left( t \right)\) | |
91. |
An amplifier with a positive feedback circuit causes ____ |
A. | bandwidth to stabilize |
B. | gain of an amplifier to stabilize |
C. | bandwidth to decrease |
D. | bandwidth to increase |
Answer» D. bandwidth to increase | |
92. |
Based on the given para, answer the following question.Sensitivity considerations often are important in the design of Control Systems. Because all physical elements have properties that change with environment and age, we cannot always consider the parameters of the Control System to be completely stationary over the entire operating life of the system. For instance, the winding resistance of an electric motor changes as the temperature of the motor rises during operation. Control systems with electric components may not operate normally when first turned on because of the still-changing system parameters during warmup. This phenomenon is sometimes called “morning sickness”. Most duplicating machines have a warmup period during which time operation is blocked out when first turn on.The sensitivity of the overall (closed-loop) transfer function for the system shown below, with respect to forward path transfer function at ω = 1 rad/sec will be: |
A. | 0.938 |
B. | 0.583 |
C. | 0.25 |
D. | 0.398 |
Answer» E. | |
93. |
Based on the given para, answer the following question.Sensitivity considerations often are important in the design of Control Systems. Because all physical elements have properties that change with environment and age, we cannot always consider the parameters of the Control System to be completely stationary over the entire operating life of the system. For instance, the winding resistance of an electric motor changes as the temperature of the motor rises during operation. Control systems with electric components may not operate normally when first turned on because of the still-changing system parameters during warmup. This phenomenon is sometimes called “morning sickness”. Most duplicating machines have a warmup period during which time operation is blocked out when first turn on.A good Control System should be:(a) Very sensitive to parameter variations(b) Insensitive to parameter variations(c) Insensitive to input commands(d) Sensitive to input commandsWhich of the above are correct? |
A. | (a) and (b) |
B. | (b) and (c) |
C. | (b) and (d) |
D. | (a) and (d) |
Answer» D. (a) and (d) | |
94. |
A Tachometer has a sensitivity of 5 V/1000 rpm. The Gain constant of the Tachometer is |
A. | 0.48 V/rad/sec |
B. | 0.048 V/rad/sec |
C. | 4.8 V/rad/sec |
D. | 48 V/rad/sec |
Answer» C. 4.8 V/rad/sec | |
95. |
Consider a unit delay element:Determine whether the system is memory less, causal and linear. |
A. | Memoryless, causal and linear |
B. | Not memoryless, non-causal and non-linear |
C. | Not memoryless, causal and linear |
D. | Not memoryless, causal and non-linear |
Answer» D. Not memoryless, causal and non-linear | |
96. |
In a closed-loop control system |
A. | control action is independent of output |
B. | output is independent of input |
C. | there is no feedback |
D. | control action is dependent on output |
Answer» E. | |
97. |
Directions: It consists of two statements, one labelled as the ‘Statement (I)’ and the other as ‘Statement (II)’. Examine these two statements carefully and select the answers to these items using the codes given below:Statement (I):For radar tracking systems, signals are available in the form of pulse trains.Statement (II):The stability of a discrete-time system is decreased as the sampling period is shortened. |
A. | Both Statement (I) and Statement (II) are individually true and Statement (II) is the correct explanation of Statement (I) |
B. | Both Statement (I) and Statement (II) are individually true but Statement (II) is not the correct explanation of Statement (I) |
C. | Statement (I) is true but Statement (II) is false |
D. | Statement (I) is false but Statement (II) is true |
Answer» D. Statement (I) is false but Statement (II) is true | |
98. |
A unity feedback control system has \(G(s) = \frac{K}{{{s^2}\left( {sT + 1} \right)}}\)The order and type of the closed-loop system will be: |
A. | 3 and 3 |
B. | 2 and 3 |
C. | 1 and 3 |
D. | 3 and 2 |
Answer» E. | |
99. |
For the closed-loop system shown, the transfer function \(\frac{{E(s)}}{{R(s)}}\) is |
A. | \(\frac{G}{{1 + GH}}\) |
B. | \(\frac{1}{{1 + GH}}\) |
C. | \(\frac{1}{{1 + G}}\) |
D. | \(\frac{GH}{{1 + GH}}\) |
Answer» C. \(\frac{1}{{1 + G}}\) | |
100. |
If the unit step response of a network is \(\left( {1 - {e^{ - \alpha t}}} \right)\), then its unit impulse response will be |
A. | \(\alpha {e^{ - \alpha t}}\) |
B. | \(\alpha {e^{ - \frac{1}{\alpha }t}}\) |
C. | \(\frac{1}{\alpha }{e^{ - \alpha t}}\) |
D. | \(\left( {1 - \alpha } \right){e^{ - \alpha t}}\) |
Answer» B. \(\alpha {e^{ - \frac{1}{\alpha }t}}\) | |