For a given differential equation, \(\frac{{{d^2}y\left( t \right)}}{{d{t^2}}} + 4\frac{{dyt)}}{{dt}} + 5y\left( t \right) = 5x\left( t \right)\) with \(y\left( {{0^ - }} \right) = 1\;and\;{\left. {\frac{{dy\left( t \right)}}{{dt}}} \right|_{{0^ - }}} = 2\) and input x(t) = u(t). The output y(t) will be

For a given differential equation, \(\frac{{{d^2}y\left( t \right)}}{{

1.	For a given differential equation, \(\frac{{{d^2}y\left( t \right)}}{{d{t^2}}} + 4\frac{{dyt)}}{{dt}} + 5y\left( t \right) = 5x\left( t \right)\) with \(y\left( {{0^ - }} \right) = 1\;and\;{\left. {\frac{{dy\left( t \right)}}{{dt}}} \right\|_{{0^ - }}} = 2\) and input x(t) = u(t). The output y(t) will be
A.	2u(t) – 2e-2t sin t
B.	u(t) + 2e-2t sin t
C.	u(t) – e-t sin t
D.	2u(t) + e-t sin t
Answer» C. u(t) – e-t sin t