 
			 
			MCQOPTIONS
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				This section includes 10 Mcqs, each offering curated multiple-choice questions to sharpen your Computational Fluid Dynamics knowledge and support exam preparation. Choose a topic below to get started.
| 1. | The central differencing scheme gives good results when _____________ | 
| A. | the grid is coarse | 
| B. | the grid is very fine | 
| C. | the grid is Cartesian and uniform | 
| D. | the gird is on-Cartesian | 
| Answer» C. the grid is Cartesian and uniform | |
| 2. | The order of accuracy of the central differencing scheme is _____________ | 
| A. | fourth-order | 
| B. | third-order | 
| C. | second-order | 
| D. | first-order | 
| Answer» D. first-order | |
| 3. | The central difference scheme gives unphysical results when the problem is _____________ | 
| A. | depends on the boundary conditions | 
| B. | equally dominated by diffusion and convection | 
| C. | diffusive dominant | 
| D. | convective dominant | 
| Answer» E. | |
| 4. | The central differencing scheme becomes inconsistent when the Peclet number _____________ | 
| A. | is higher than 2 | 
| B. | is less than 2 | 
| C. | is higher than 5 | 
| D. | is less than 5 | 
| Answer» B. is less than 2 | |
| 5. | Which of these is correct about the central differencing scheme? | 
| A. | The importance of upwind and downwind nodes depends on the problem | 
| B. | It gives more importance to the downwind nodes | 
| C. | It gives equal importance to upwind and downwind nodes | 
| D. | It gives more importance to the upwind nodes | 
| Answer» D. It gives more importance to the upwind nodes | |
| 6. | The central difference approximation goes wrong when _____________ | 
| A. | Peclet number is negative | 
| B. | Peclet number is positive | 
| C. | Peclet number is low | 
| D. | Peclet number is high | 
| Answer» E. | |
| 7. | What is the relationship between \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w}\) and the Peclet number (Pe) when the grid is uniform? | 
| A. | \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = \frac{1}{2}(1-\frac{Pe}{2}) \) | 
| B. | \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = \frac{1}{2}(1+\frac{Pe}{2}) \) | 
| C. | \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = \frac{1}{2}(\frac{Pe}{2}-1) \) | 
| D. | \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = (\frac{Pe}{4}) \) | 
| E. | when the grid is uniform?a) \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = \frac{1}{2}(1-\frac{Pe}{2}) \) b) \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = \frac{1}{2}(1+\frac{Pe}{2}) \) c) \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = \frac{1}{2}(\frac{Pe}{2}-1) \) d) \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = (\frac{Pe}{4}) \) | 
| Answer» B. \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = \frac{1}{2}(1+\frac{Pe}{2}) \) | |
| 8. | What is the central differencing scheme similar to? | 
| A. | Interpolation profile | 
| B. | Linear interpolation profile | 
| C. | Weighted average method | 
| D. | Geometric mean | 
| Answer» C. Weighted average method | |
| 9. | Consider the following stencil.Assume that the grid is a uniform Cartesian grid. What is φw as given by the central difference scheme?(Note: Φ represents the flow variable). | 
| A. | Φc | 
| B. | \(\frac{\phi_c+\phi_w}{2}\) | 
| C. | \(\frac{\phi_c-\phi_w}{2}\) | 
| D. | \(\frac{\phi_w-\phi_c}{2}\) | 
| E. | .a) Φcb) \(\frac{\phi_c+\phi_w}{2}\) c) \(\frac{\phi_c-\phi_w}{2}\) d) \(\frac{\phi_w-\phi_c}{2}\) | 
| Answer» C. \(\frac{\phi_c-\phi_w}{2}\) | |
| 10. | Consider the following stencil. What is Φe as given by the central difference scheme?(Note: Φ represents the flow variable). | 
| A. | \(\phi_E = \phi_c-\frac{(\phi_E+\phi_c)}{(x_E-x_C)}(x_e-x_C)\) | 
| B. | \(\phi_E = \phi_c+\frac{(\phi_E+\phi_c)}{(x_E-x_C)}(x_e-x_C)\) c) \(\phi_E = \phi_c+\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) d) \(\phi_E = \phi_c-\frac{(\phi_E-\phi_ | 
| C. | }{(x_E-x_C)}(x_e-x_C)\) b) \(\phi_E = \phi_c+\frac{(\phi_E+\phi_c)}{(x_E-x_C)}(x_e-x_C)\) c) \(\phi_E = \phi_c+\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) | 
| D. | \(\phi_E = \phi_c-\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) | 
| E. | .a) \(\phi_E = \phi_c-\frac{(\phi_E+\phi_c)}{(x_E-x_C)}(x_e-x_C)\) b) \(\phi_E = \phi_c+\frac{(\phi_E+\phi_c)}{(x_E-x_C)}(x_e-x_C)\) c) \(\phi_E = \phi_c+\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) d) \(\phi_E = \phi_c-\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) | 
| Answer» D. \(\phi_E = \phi_c-\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) | |