MCQOPTIONS
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MCQOPTIONS
| 1. |
Consider the following stencil. What is Φe as given by the central difference scheme?(Note: Φ represents the flow variable). |
| A. | \(\phi_E = \phi_c-\frac{(\phi_E+\phi_c)}{(x_E-x_C)}(x_e-x_C)\) |
| B. | \(\phi_E = \phi_c+\frac{(\phi_E+\phi_c)}{(x_E-x_C)}(x_e-x_C)\) c) \(\phi_E = \phi_c+\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) d) \(\phi_E = \phi_c-\frac{(\phi_E-\phi_ |
| C. | }{(x_E-x_C)}(x_e-x_C)\) b) \(\phi_E = \phi_c+\frac{(\phi_E+\phi_c)}{(x_E-x_C)}(x_e-x_C)\) c) \(\phi_E = \phi_c+\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) |
| D. | \(\phi_E = \phi_c-\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) |
| E. | .a) \(\phi_E = \phi_c-\frac{(\phi_E+\phi_c)}{(x_E-x_C)}(x_e-x_C)\) b) \(\phi_E = \phi_c+\frac{(\phi_E+\phi_c)}{(x_E-x_C)}(x_e-x_C)\) c) \(\phi_E = \phi_c+\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) d) \(\phi_E = \phi_c-\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) |
| Answer» D. \(\phi_E = \phi_c-\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) | |