MCQOPTIONS
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MCQOPTIONS
This section includes 9 Mcqs, each offering curated multiple-choice questions to sharpen your Computational Fluid Dynamics knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Gradient for an unstructured grid is calculated by ___________ |
| A. | looping over the nodes in the computational domain |
| B. | looping over the elements in the computational domain |
| C. | looping over the faces in the computational domain |
| D. | looping over the gradients in the computational domain |
| Answer» D. looping over the gradients in the computational domain | |
| 2. |
When compared to the algorithm to calculate the gradient of a structured grid, the algorithm for unstructured grids ___________ |
| A. | need more computational cost |
| B. | need less computational cost |
| C. | is more accurate |
| D. | is less accurate |
| Answer» C. is more accurate | |
| 3. |
The topology of the faces in an unstructured grid depends upon ___________ |
| A. | Straddling elements |
| B. | Boundary elements |
| C. | Interior elements |
| D. | Neighbouring elements |
| Answer» B. Boundary elements | |
| 4. |
Which of these formulae is correct to find the gradient of the element ‘k’? |
| A. | ∇Φk = \(\frac{1}{V_k}(\Sigma_{n\leftarrow f<k}\Phi_n\vec{S_n}-\Sigma_{n\leftarrow f>k} \Phi_n\vec{S_n})\) |
| B. | ∇Φk = \(\frac{1}{V_k}(-\Sigma_{n\leftarrow f}\Phi_n \vec{S_n})\) |
| C. | ∇Φk = \(\frac{1}{V_k}(\Sigma_{n\leftarrow f}\Phi_n \vec{S_n})\) |
| D. | ∇Φk = \(\frac{1}{V_k}(- \Sigma_{n\leftarrow f<k}\Phi_n\vec{S_n}+\Sigma_{n\leftarrow f>k} \Phi_n\vec{S_n})\) |
| Answer» E. | |
| 5. |
The direction of the normal to a face in an unstructured mesh depends upon __________ |
| A. | Local indices |
| B. | Global indices |
| C. | Direction of flow |
| D. | Direction of increasing indices |
| Answer» C. Direction of flow | |
| 6. |
Which of these entities need the information to be explicitly stored? |
| A. | Elements, faces, nodes and neighbours |
| B. | Elements, faces and nodes |
| C. | Elements, faces and neighbours |
| D. | Elements, nodes and neighbours |
| Answer» B. Elements, faces and nodes | |
| 7. |
What is the cost of flexibility in unstructured grids? |
| A. | Consistency |
| B. | Stability |
| C. | Accuracy |
| D. | Complexity |
| Answer» E. | |
| 8. |
Which of these statements is true for unstructured grids? |
| A. | It is simple to model and use |
| B. | Element connectivity is implicitly defined |
| C. | Element connectivity does not depend upon indices |
| D. | Bounding faces can be easily found |
| Answer» D. Bounding faces can be easily found | |
| 9. |
The advantage of using unstructured grids is ___________ |
| A. | vectorization |
| B. | flexibility |
| C. | simple arrangement |
| D. | less memory requirement |
| Answer» C. simple arrangement | |