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This section includes 585 Mcqs, each offering curated multiple-choice questions to sharpen your Computer Organization knowledge and support exam preparation. Choose a topic below to get started.
101. |
Both the CISC and RISC architectures have been developed to reduce the |
A. | Cost |
B. | Time delay |
C. | Semantic gap |
D. | All of the mentioned |
Answer» D. All of the mentioned | |
102. |
The computer architecture aimed at reducing the time of execution of instructions is _____ |
A. | CISC |
B. | RISC |
C. | ISA |
D. | ANNA |
Answer» C. ISA | |
103. |
The CISC stands for ____ |
A. | Computer Instruction Set Compliment |
B. | Complete Instruction Set Compliment |
C. | Computer Indexed Set Components |
D. | Complex Instruction set computer |
Answer» E. | |
104. |
The commitment unit uses a queue called __ |
A. | Record buffer |
B. | Commitment buffer |
C. | Storage buffer |
D. | None of the mentioned |
Answer» B. Commitment buffer | |
105. |
Since it uses the out of order mode of execution, the results are stored in _ |
A. | Buffers |
B. | Special memory locations |
C. | Temporary registers |
D. | TLB |
Answer» D. TLB | |
106. |
A special unit used govern the out of order execution of the instructions is called as ____ |
A. | Commitment unit |
B. | Temporal unit |
C. | Monitor |
D. | Supervisory unit |
Answer» B. Temporal unit | |
107. |
The step where in the results stored in the temporary register is transfered into the permanent register is called as _ |
A. | Final step |
B. | Committment step |
C. | Last step |
D. | Inception step |
Answer» C. Last step | |
108. |
If an exception is raised and the succeeding instructions are executed completly, then the processor is said to have _ |
A. | Exception handling |
B. | Imprecise exceptions |
C. | Error correction |
D. | None of the mentioned |
Answer» C. Error correction | |
109. |
When the processor executes multiple instructions at a time it is said to use ___ |
A. | single issue |
B. | Multiplicity |
C. | Visualization |
D. | Multiple issue |
Answer» E. | |
110. |
The throughput of a super scalar processor is |
A. | less than 1 |
B. | 1 |
C. | More than 1 |
D. | Not Known |
Answer» D. Not Known | |
111. |
The situation where in the data of operands are not available is called __ |
A. | Data hazard |
B. | Stock |
C. | Deadlock |
D. | Structural hazard |
Answer» B. Stock | |
112. |
The contention for the usage of a hardware device is called as __ |
A. | Structural hazard |
B. | Stalk |
C. | Deadlock |
D. | None of the mentioned |
Answer» B. Stalk | |
113. |
The periods of time when the unit is idle is called as _ |
A. | Stalls |
B. | Bubbles |
C. | Hazards |
D. | Both Stalls and Bubbles |
Answer» E. | |
114. |
The pipelining process is also called as ___ |
A. | Superscalar operation |
B. | Assembly line operation |
C. | Von neumann cycle |
D. | None of the mentioned |
Answer» C. Von neumann cycle | |
115. |
To increase the speed of memory access in pipelining, we make use of ___ |
A. | Special memory locations |
B. | Special purpose registers |
C. | Cache |
D. | Buffers |
Answer» D. Buffers | |
116. |
If a unit completes its task before the allotted time period, then |
A. | It’ll perform some other task in the remaining time |
B. | Its time gets reallocated to different task |
C. | It’ll remain idle for the remaining time |
D. | None of the mentioned |
Answer» D. None of the mentioned | |
117. |
The fetch and execution cycles are interleaved with the help of ____ |
A. | Modification in processor architecture |
B. | Clock |
C. | Special unit |
D. | Control unit |
Answer» C. Special unit | |
118. |
In double precision format the size of the mantissa is ___ |
A. | 32 bit |
B. | 52 bit |
C. | 64 bit |
D. | 72 bit |
Answer» C. 64 bit | |
119. |
The 32 bit representation of the decimal number is called as _ |
A. | Double-precision |
B. | Single-precision |
C. | Extended format |
D. | None of the mentioned |
Answer» C. Extended format | |
120. |
The sign followed by the string of digits is called as _ |
A. | Significant |
B. | Determinant |
C. | Mantissa |
D. | Exponent |
Answer» D. Exponent | |
121. |
In 32 bit representation the scale factor as a range of __ |
A. | -128 to 127 |
B. | -256 to 255 |
C. | 0 to 255 |
D. | None of the mentioned |
Answer» B. -256 to 255 | |
122. |
_______ constitute the representation of the floating number. |
A. | Sign |
B. | Significant digits |
C. | Scale factor |
D. | All of the mentioned |
Answer» E. | |
123. |
If the decimal point is placed to the right of the first significant digit, then the number is called as __ |
A. | Orthogonal |
B. | Normalized |
C. | Determinate |
D. | None of the mentioned |
Answer» C. Determinate | |
124. |
The multiplier -6(11010) is recorded as, |
A. | 0-1-2 |
B. | 0-1+1-10 |
C. | -2-10 |
D. | None of the mentioned |
Answer» B. 0-1+1-10 | |
125. |
The numbers written to the power of 10 in the representation of decimal numbers are called as __ |
A. | Height factors |
B. | Size factors |
C. | Scale factors |
D. | None of the mentioned |
Answer» D. None of the mentioned | |
126. |
CSA stands for |
A. | Computer Speed Addition |
B. | Carry Save Addition |
C. | Computer Service Architecture |
D. | None of the mentioned |
Answer» B. Carry Save Addition | |
127. |
The bits 1 & 1 are recorded as _______ in bit-pair recording. |
A. | -1 |
B. | 0 |
C. | +1 |
D. | both -1 and 0 |
Answer» E. | |
128. |
The method used to reduce the maximum number of summands by half is __ |
A. | Fast multiplication |
B. | Bit-pair recording |
C. | Quick multiplication |
D. | None of the mentioned |
Answer» C. Quick multiplication | |
129. |
The product of 1101 & 1011 is |
A. | 10001111 |
B. | 10101010 |
C. | 11110000 |
D. | 11001100 |
Answer» B. 10101010 | |
130. |
The multiplicand and the control signals are passed through to the n-bit adder via _ |
A. | MUX |
B. | DEMUX |
C. | Encoder |
D. | Decoder |
Answer» B. DEMUX | |
131. |
The ______ is used to co-ordinate the operation of the multiplier. |
A. | Controller |
B. | Coordinator |
C. | Control sequencer |
D. | None of the mentioned |
Answer» D. None of the mentioned | |
132. |
The multiplier is stored in __ |
A. | PC Register |
B. | Shift register |
C. | Cache |
D. | None of the mentioned |
Answer» C. Cache | |
133. |
The delay reduced to in the carry look ahead adder is _____ |
A. | 5 |
B. | 8 |
C. | 10 |
D. | 2n |
Answer» B. 8 | |
134. |
The final addition sum of the numbers, 0110 & 0110 is |
A. | 1101 |
B. | 1111 |
C. | 1001 |
D. | 1010 |
Answer» B. 1111 | |
135. |
In a normal adder circuit the delay obtained in generation of the output is __ |
A. | 2n + 2 |
B. | 2n |
C. | n + 2 |
D. | None of the mentioned |
Answer» B. 2n | |
136. |
The usual implementation of the carry circuit involves __ |
A. | And and or gates |
B. | XOR |
C. | NAND |
D. | XNOR |
Answer» C. NAND | |
137. |
In full adders the sum circuit is implemented using _ |
A. | And & or gates |
B. | NAND gate |
C. | XOR |
D. | XNOR |
Answer» D. XNOR | |
138. |
______ is used to deal with the difference in the transfer rates between the drive and the bus. |
A. | Data repeaters |
B. | Enhancers |
C. | Data buffers |
D. | None of the mentioned |
Answer» D. None of the mentioned | |
139. |
The carry in the ripple adders(which is true) |
A. | Are generated at the beginning only |
B. | Must travel through the configuration |
C. | Is generated at the end of each operation |
D. | None of the mentioned |
Answer» C. Is generated at the end of each operation | |
140. |
The carry generation function: ci + 1 = yici + xici + xiyi, is implemented in _____ |
A. | Half adders |
B. | Full adders |
C. | Ripple adders |
D. | Fast adders |
Answer» C. Ripple adders | |
141. |
_____ is used to detect and correct the errors that may occur during data transfers. |
A. | ECC |
B. | CRC |
C. | Checksum |
D. | None of the mentioned |
Answer» B. CRC | |
142. |
The disk drive is connected to the system by using the _ |
A. | PCI bus |
B. | SCSI bus |
C. | HDMI |
D. | ISA |
Answer» C. HDMI | |
143. |
The access time is composed of __ |
A. | Seek time |
B. | Rotational delay |
C. | Latency |
D. | Both Seek time and Rotational delay |
Answer» E. | |
144. |
To distinguish between two sectors we make use of _____ |
A. | Inter sector gap |
B. | Splitting bit |
C. | Numbering bit |
D. | None of the mentioned |
Answer» B. Splitting bit | |
145. |
The method of placing the heads and the discs in an air tight environment is called as _____ |
A. | RAID Arrays |
B. | ATP tech |
C. | Winchester technology |
D. | Fleming reduction |
Answer» D. Fleming reduction | |
146. |
The data can be accessed from the disk using ___ |
A. | Surface number |
B. | Sector number |
C. | Track number |
D. | All of the mentioned |
Answer» E. | |
147. |
The set of corresponding tracks on all surfaces of a stack of disks form a ____ |
A. | Cluster |
B. | Cylinder |
C. | Group |
D. | Set |
Answer» C. Group | |
148. |
A hard disk with 20 surfaces will have _____ heads. |
A. | 10 |
B. | 5 |
C. | 1 |
D. | 20 |
Answer» E. | |
149. |
___ pushes the heads away from the surface as they rotate at their standard rates. |
A. | Magnetic tension |
B. | Electric force |
C. | Air pressure |
D. | None of the mentioned |
Answer» D. None of the mentioned | |
150. |
The air pressure can be countered by putting ______ in the head-disc surface arrangement. |
A. | Air filter |
B. | Spring mechanism |
C. | coolant |
D. | None of the mentioned |
Answer» C. coolant | |