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This section includes 519 Mcqs, each offering curated multiple-choice questions to sharpen your Electronics & Communication Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
For the log magnitude Bode plot of the given figure, the transfer function is |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» E. | |
| 52. |
A system has two poles as shown in the given figure. The zeros are at infinity. If input is unit step, the steady state output is |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | 1 |
| Answer» E. | |
| 53. |
If , initial and final values of i(t) are |
| A. | zero and 1 |
| B. | zero and 10 |
| C. | 10 and zero |
| D. | 70 and 80 |
| Answer» D. 70 and 80 | |
| 54. |
For the second order system having following differential equation(When θ0 and θi are output and input) the natural frequency is |
| A. | [A]. |
| B. | [B]. |
| C. | KJ |
| D. | [D]. |
| Answer» B. [B]. | |
| 55. |
In the given figure the transfer function |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» E. | |
| 56. |
A system with transfer function may be approximated by the system |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» B. [B]. | |
| 57. |
For the system in the given figure, |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | none of the above |
| Answer» C. [C]. | |
| 58. |
In a two phase ac servomotor rotor resistance is R and rotor reactance is X. The speed curve will be linear if |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | X2 = R |
| Answer» B. [B]. | |
| 59. |
For the system in the given figure, the ratio C(s)/R(s) = |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» B. [B]. | |
| 60. |
For the mechanical system in the given figure the transfer function = |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» B. [B]. | |
| 61. |
A feedback amplifier has forward gains A1, A2 and feedback factor β as shown in signal flow graph of the given figure. Because of feedback as shown in signal noise ratio at output will |
| A. | increase |
| B. | decrease |
| C. | be unaffected |
| D. | depend on value of β |
| Answer» D. depend on value of β | |
| 62. |
In terms of ξ and ωn the settling time (5% criterion) of a second order system for a step input, is equal to |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» D. [D]. | |
| 63. |
In terms of ξ and ωn the settling time of a second order systems for 2% criterion and step input is equal to |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» E. | |
| 64. |
In the given figure shows pole-zero plot. If steady state gain is 2 the transfer function G(s) is |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» B. [B]. | |
| 65. |
In the given figure the input is x(t) = A sin ωt. The steady state output y(t) = |
| A. | A sin (ωt + φ) where φ = tan-1 |G(jω)| |
| B. | |G(jω)| A sin [ωt + ∠G(jω)] |
| C. | |G(jω)| A sin [2ωt + ∠G(jω)] |
| D. | A G(jω) sin [ωt + ∠G(jω)] |
| Answer» C. |G(jω)| A sin [2ωt + ∠G(jω)] | |
| 66. |
For the circuit in the given figure, |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» D. [D]. | |
| 67. |
For the given figure, the transfer function of signal flow graph is |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» B. [B]. | |
| 68. |
If the characteristic equation is (λ + 1) (λ + 2) (λ + 3) = 0, the eigen values are |
| A. | -1, -2, -3 |
| B. | 1, 2, 3 |
| C. | 0, 1, 2 |
| D. | 0, 2, 3 |
| Answer» B. 1, 2, 3 | |
| 69. |
For the system of the given figure |G(jω)| = 0 dB at ω = |
| A. | 0 |
| B. | 1 rad/sec. |
| C. | ∞ |
| D. | 2.38 rad/sec. |
| Answer» E. | |
| 70. |
If phase angle of open loop transfer function becomes - 180° at frequency ω1, then gain margin is equal to |
| A. | |G(jω1)| |
| B. | [B]. |
| C. | 1 + |G(jω1)| |
| D. | [D]. |
| Answer» C. 1 + |G(jω1)| | |
| 71. |
The polar plot of the given figure is for the term |
| A. | (jω)2 |
| B. | 1 + (jω)2 |
| C. | [C]. |
| D. | [D]. |
| Answer» D. [D]. | |
| 72. |
For type 2 system, the magnitude and phase angle of the term (jω)2 in the denominator, at ω = 0, are respectively |
| A. | 0 and - 90° |
| B. | 0 and + 90° |
| C. | infinity and - 180° |
| D. | infinity and + 180° |
| Answer» D. infinity and + 180° | |
| 73. |
For the transport lag G(jω) = e-jωT, the polar plot is |
| A. | a semi circle |
| B. | a circle |
| C. | a unit circle |
| D. | none of the above |
| Answer» D. none of the above | |
| 74. |
For the transport lag G(jω) = e-jωT, the phase angle |
| A. | is constant |
| B. | varies linearly with frequency |
| C. | varies linearly with low frequencies only |
| D. | values as per square law |
| Answer» C. varies linearly with low frequencies only | |
| 75. |
For the transport lag G(jω) = e-jωT, the magnitude is always equal to |
| A. | 0 |
| B. | 1 |
| C. | 10 |
| D. | 0.5 |
| Answer» C. 10 | |
| 76. |
The polar plot of G(jω) = 1/jω is |
| A. | positive imaginary axis |
| B. | positive real axis |
| C. | negative imaginary axis |
| D. | negative real axis |
| Answer» D. negative real axis | |
| 77. |
The open loop transfer function of a system is . If the frequency at the intersection of - 40 dB/decade line and 0 dB line is ω, then |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» C. [C]. | |
| 78. |
The phase angle curve of G(jω) H(jω) can be drawn |
| A. | by adding the phase angle curves of individual factors |
| B. | by subtracting the phase angle curves of individual factors |
| C. | by multiplying the phase angle curves of individual factors |
| D. | by dividing the phase angle curves of individual factors |
| Answer» B. by subtracting the phase angle curves of individual factors | |
| 79. |
For a quadratic factor in denominator of transfer function the phase angle at corner frequency (in Bode phase angle plot) |
| A. | is -90° |
| B. | is +90° |
| C. | depends on the damping factor |
| D. | none of the above |
| Answer» B. is +90° | |
| 80. |
In log magnitude Bode diagram the slope of high frequency asymptote of (1 + jωT) is |
| A. | 20 dB per decade |
| B. | 10 dB per decade |
| C. | 20 dB per octave |
| D. | 10 dB per octave |
| Answer» B. 10 dB per decade | |
| 81. |
At corner frequency the phase angle of factor 1/(1 + jωT) is |
| A. | +90° |
| B. | -90° |
| C. | +45° |
| D. | -45° |
| Answer» E. | |
| 82. |
In Bode diagram (log magnitude plot) of the factor 1/(1 + jωT) in the transfer function the log magnitude for ω |
| A. | 0 dB |
| B. | 20 log ωT dB |
| C. | -20 log ωT dB |
| D. | none of the above |
| Answer» B. 20 log ωT dB | |
| 83. |
In Bode diagram (log magnitude plot) the factor (jω)n in the transfer function gives a line having slope |
| A. | 20 dB/decade |
| B. | 20n dB/decade |
| C. | [C]. |
| D. | -20n dB/decade |
| Answer» C. [C]. | |
| 84. |
The damping ratio of a pair of complex poles when expressed in terms of angle θ measured from jω axis equal to |
| A. | sin θ |
| B. | cos θ |
| C. | tan θ |
| D. | cot θ |
| Answer» B. cos θ | |
| 85. |
For the system of the given figure, the break away and break in points are determined from the conditions . Then K = |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» C. [C]. | |
| 86. |
For the given figure C(s)/R(s) = |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» C. [C]. | |
| 87. |
A system has transfer function. If a sinusoidal input of frequency ω is applied the steady state output is of the form |
| A. | [A]. |
| B. | K1 K2 (1 + jω/T) |
| C. | K1K2/jωT |
| D. | [D]. |
| Answer» B. K1 K2 (1 + jω/T) | |
| 88. |
For the op-amp circuit of the given figure, Eo(s)/Ei(s) = |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» C. [C]. | |
| 89. |
For op-amp circuit of the given figure, Eo(s)/Ei(s) = |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» E. | |
| 90. |
For the system of given figure the closed loop transfer function |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» E. | |
| 91. |
A unity feedback system has open loop transfer function The closed loop transfer function is |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» D. [D]. | |
| 92. |
In a second order system ωn = 10 rad/sec and ζ = 0.1, then ωd = |
| A. | 9.1 rad/sec |
| B. | 9.95 rad/sec |
| C. | 9 rad/sec |
| D. | 1 rad/sec |
| Answer» C. 9 rad/sec | |
| 93. |
For the given figure the equation of motion is |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | none of the above |
| Answer» B. [B]. | |
| 94. |
A second order system has damping ratio x and natural frequency ωn. The unit step response is |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» D. [D]. | |
| 95. |
In the given figure, P = Pm sin ωt. Then X(s) = |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» B. [B]. | |
| 96. |
In the given figure, P = 3 kg force. Then X(s) = |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» D. [D]. | |
| 97. |
For the given figure, the transfer function X(s)/P(s) = |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» C. [C]. | |
| 98. |
A motor is coupled to a load through gear ratio n. If T is the motor torque, Jm and JL are moment of inertia of rotor and load, then torque to inertia ratio referred to motor shaft is |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» D. [D]. | |
| 99. |
For the given figure |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» D. [D]. | |
| 100. |
The system in the given figure, x(0) = 0 and x (0) = 0, At t = 0 the unit impulse δ(t) is applied X(s) |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» D. [D]. | |