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This section includes 519 Mcqs, each offering curated multiple-choice questions to sharpen your Electronics & Communication Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
N circles for a = a1, and a = a1 ± 180° n (where n = 1, 2, 3, ....) are the same. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 2. |
Nichol's chart is symmetric about - 180° axis. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 3. |
At low frequencies the factor e-jωT and behave simple. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 4. |
For type 0 system the starting point (i.e. ω = 0) of polar plot is finite and is on positive real axis. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 5. |
For as ω approaches infinity, the magnitude approaches zero and phase angle approaches - 90°. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 6. |
The phase angle curve of G(jω) H(jω) is drawn by adding the phase angles of individual factors. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 7. |
At corner frequency the phase angle of factor is - 45° |
| A. | True |
| B. | False |
| Answer» B. False | |
| 8. |
The phase angle of is constant and equal to - 90° for all values of ω |
| A. | True |
| B. | False |
| Answer» B. False | |
| 9. |
The log magnitude curve of factor jω is a straight line having a slope of 20 dB/decade. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 10. |
Transfer functions of even complicated components can be found by frequency response tests. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 11. |
Assertion (A): For a given system only one of the static error constants is finite and significant.Reason (R): If finite static error constant is large, the loop gain becomes smaller as ω approaches zero. |
| A. | Both A and R are correct and R is correct explanation of A |
| B. | Both A and R are correct but R is not correct explanation of A |
| C. | A is correct but R is wrong |
| D. | R is correct but A is wrong |
| Answer» D. R is correct but A is wrong | |
| 12. |
Assertion (A): The steady state response, of a stable, linear, time invariant system, to sinusoidal input depends on initial conditions. Reason (R): Frequency response, in steady state, is obtained by replacing s in the transfer function by jω |
| A. | Both A and R are correct and R is correct explanation of A |
| B. | Both A and R are correct but R is not correct explanation of A |
| C. | A is correct but R is wrong |
| D. | R is correct but A is wrong |
| Answer» E. | |
| 13. |
Assertion (A): F(s) is valid throughout s plane except at poles of F(s).Reason (R): £[f1(t) + f2(t)] = £[f1(t)] + £[f2(t)] |
| A. | Both A and R are correct and R is correct explanation of A |
| B. | Both A and R are correct but R is not correct explanation of A |
| C. | A is correct but R is wrong |
| D. | R is correct but A is wrong |
| Answer» C. A is correct but R is wrong | |
| 14. |
Assertion (A): For an underdamped system with damping ratio ξ, the maximum overshoot is e-ξp/(1-ξ2)0.5Reason (R): Peak time of a second order under damped system = p/ωd where ωd is frequency of damped oscillations. |
| A. | Both A and R are correct and R is correct explanation of A |
| B. | Both A and R are correct but R is not correct explanation of A |
| C. | A is correct but R is wrong |
| D. | R is correct but A is wrong |
| Answer» C. A is correct but R is wrong | |
| 15. |
Assertion (A): An on off controller gives rise to oscillation of the output between two limits.Reason (R): Location of a pair of poles on jω axis gives rise to self sustained oscillations in the output. |
| A. | Both A and R are correct and R is correct explanation of A |
| B. | Both A and R are correct but R is not correct explanation of A |
| C. | A is correct but R is wrong |
| D. | R is correct but A is wrong |
| Answer» C. A is correct but R is wrong | |
| 16. |
Assertion (A): The closeness of G(jω) locus to (- 1 + j0) point can be used as a measured of margin of stability.Reason (R): When the G(jω) locus comes close to encircling (- 1 + j0) point the system becomes oscillatory. |
| A. | Both A and R are correct and R is correct explanation of A |
| B. | Both A and R are correct but R is not correct explanation of A |
| C. | A is correct but R is wrong |
| D. | R is correct but A is wrong |
| Answer» B. Both A and R are correct but R is not correct explanation of A | |
| 17. |
Assertion (A): If minimum phase system has a gain margin of 8 dB and phase margin of 21°, the system is stable.Reason (R): For a minimum phase system both GM and PM must be positive for the system to be stable. |
| A. | Both A and R are correct and R is correct explanation of A |
| B. | Both A and R are correct but R is not correct explanation of A |
| C. | A is correct but R is wrong |
| D. | R is correct but A is wrong |
| Answer» B. Both A and R are correct but R is not correct explanation of A | |
| 18. |
Assertion (A): A. For a unity feedback system, with , the settling time of step response is constant for all values of K ≥ 1Reason (R): The real part of the roots for all values of K ≥ 1 are negative. |
| A. | Both A and R are correct and R is correct explanation of A |
| B. | Both A and R are correct but R is not correct explanation of A |
| C. | A is correct but R is wrong |
| D. | R is correct but A is wrong |
| Answer» B. Both A and R are correct but R is not correct explanation of A | |
| 19. |
The given figure shows log magnitude versus ω plots of a system for different values of gain. For this system |
| A. | curve 1 shows highest gain margin and curve 2 shows poorest gain margin |
| B. | gain margins shown by the three curves are equal |
| C. | curve 1 shows poorest gain margin and curve 3 shows highest gain margin |
| D. | curve 3 shows poorest gain margin while curve 1 shows highest gain margin |
| Answer» D. curve 3 shows poorest gain margin while curve 1 shows highest gain margin | |
| 20. |
The Nyquist plot in the given figure is for G(s) H(s) = |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» D. [D]. | |
| 21. |
The slope of log-magnitude asymptote changes by - 40 dB/ decade at a frequency ω1. This means that |
| A. | a double pole is present |
| B. | a pair of complex conjugate poles is present |
| C. | either a double pole or a pair of complex conjugate poles is present |
| D. | a pole or zero at origin is present |
| Answer» D. a pole or zero at origin is present | |
| 22. |
For G(jω) = |
| A. | magnitude is 1 at all frequencies and phase angle varies from 0 to - 180° as ω varies from 0 to ∞ |
| B. | magnitude is T at all frequencies and phase angle 0 |
| C. | magnitude is (1 + ω2T2)0.5 and phase angle varies from0 to 0 - 180° as ω varies from 0 to ∞ |
| D. | none of the above |
| Answer» B. magnitude is T at all frequencies and phase angle 0 | |
| 23. |
For the factor (1 + 0.5 jω) the corner frequency is |
| A. | 1 rad/sec |
| B. | 0.5 rad/sec |
| C. | 2 rad/sec |
| D. | 0.25 rad/sec |
| Answer» D. 0.25 rad/sec | |
| 24. |
For Bode plot of (1 + jωT) has |
| A. | slope of 20 dB/decade and phase angle + tan-1 (ωT) |
| B. | slope of - 20 dB/decade and phase angle + tan-1 (ωT) |
| C. | slope of 20 dB/decade and phase angle - tan-1 (ωT) |
| D. | slope of - 40 dB/decade and phase angle - tan-1(ωT) |
| Answer» B. slope of - 20 dB/decade and phase angle + tan-1 (ωT) | |
| 25. |
The polar plot in the given figure is for G(jω) = |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» D. [D]. | |
| 26. |
For the plot in the given figure, G(jω) = |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» E. | |
| 27. |
Consider the following statements about polar plots Addition of a non-zero pole to a transfer function results in further rotation of polar plot through an angle of - 90° as ω → ∞Addition of a pole at the origin to a transfer function rotates the polar plot at zero and infinite frequencies by a further angle of - 90° Of the above statements: |
| A. | Both are correct |
| B. | Both are wrong |
| C. | 1 is correct and 2 is wrong |
| D. | 2 is correct and 1 is wrong |
| Answer» B. Both are wrong | |
| 28. |
The polar plot of the given figure can be for G(jω) = |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» C. [C]. | |
| 29. |
Consider the following statements: If any root of characteristic equation has a positive real part the impulse response is unbounded and system is unstable.If all the roots of a characteristic equation have negative real parts, the impulse response decays to zero.If one or more non-repeated roots of characteristic equation are on jω axis impulse response is bounded but the system is unstable. Which of the above equations are correct? |
| A. | 1, 2 and 3 |
| B. | 1 and 2 only |
| C. | 1 and 3 only |
| D. | 2 and 3 only |
| Answer» B. 1 and 2 only | |
| 30. |
If feedback factor is β the overall gain of a closed loop system is approximately equal to |
| A. | [A]. |
| B. | [B]. |
| C. | β |
| D. | β |
| Answer» C. β | |
| 31. |
For a second order system ωn is natural frequency, ωd is frequency of damped oscillations and ζ is damping factor. Then |
| A. | ωd = ωn ξ |
| B. | ωd = ωn (1 - ξ)2 |
| C. | ωd = ωn (1 - ξ)0.5 |
| D. | ωd = ωn (1 - ξ2)0.5 |
| Answer» E. | |
| 32. |
For a second order system damping factor is 0.1. If ωd is frequency of damped oscillations and ωn is natural frequency, then |
| A. | ωd ≈ ωn |
| B. | [B]. |
| C. | ωn ≈ ωn |
| D. | ωd ≈ (ωn)2 |
| Answer» B. [B]. | |
| 33. |
For a second order system with 0 < ξ < 1, the angle which poles make with negative real axis is |
| A. | sin-1 ξ |
| B. | cos-1 ξ |
| C. | tan-1 ξ |
| D. | cot-1 ξ |
| Answer» C. tan-1 ξ | |
| 34. |
In the given figure, R2 >> R1. Then |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» B. [B]. | |
| 35. |
If ΔP is pressure difference, A is area of each flat surface, K is stiffness and Δx is displacement of movable surface from reference of bellows, then |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» D. [D]. | |
| 36. |
For the given figure, |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» C. [C]. | |
| 37. |
In the given figure |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» B. [B]. | |
| 38. |
In the given figure, C(s) = |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» C. [C]. | |
| 39. |
In an armature controlled dc motor let J be equivalent moment of inertia of motor and load, f0 be equivalent viscous friction coefficient of motor and load and θ be angular displacement of motor shaft. Then torque equation is |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» B. [B]. | |
| 40. |
The radius of constant N circle for N = 1 is |
| A. | 2 |
| B. | 2 |
| C. | 1 |
| D. | [D]. |
| Answer» E. | |
| 41. |
For the feedback system with closed loop transfer function the settling time for 2% tolerance |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | 4ξωn |
| Answer» D. 4ξωn | |
| 42. |
Given figure shows a magnitude Bode plot. The transfer function for this plot is |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» D. [D]. | |
| 43. |
A phase lead network with where a < 1, gives maximum phase lead at a frequency equal to |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» D. [D]. | |
| 44. |
For a feedback systemThen the velocity error constant Kv is given by |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» B. [B]. | |
| 45. |
For the circuit in the given figure, V2(s)/V1(s) = |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» C. [C]. | |
| 46. |
The phase difference (jω - p1) means |
| A. | phasor drawn from p1 to jω |
| B. | phasor drawn from origin to p1 |
| C. | phasor directed from origin to jω point |
| D. | phasor directed from jω to p1 |
| Answer» B. phasor drawn from origin to p1 | |
| 47. |
An RLC series circuit hasIf poles p1 and p1* are close to jω axis, then |
| A. | resonant frequency is high |
| B. | Q is high |
| C. | bandwidth is large |
| D. | Q is low |
| Answer» D. Q is low | |
| 48. |
For an RLC series circuit Z(s) is of the form |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» E. | |
| 49. |
If the angle of departure of root locus at s = - 1 + j is |
| A. | zero |
| B. | 90° |
| C. | -90° |
| D. | -180° |
| Answer» E. | |
| 50. |
For the system of the given figure the transfer function is |
| A. | [A]. |
| B. | [B]. |
| C. | [C]. |
| D. | [D]. |
| Answer» E. | |