MCQOPTIONS
Bookmark
Saved Bookmarks
→
Electronics & Communication Engineering
→
Signals And Systems
→
For the given figure
1.
For the given figure
A.
[A].
B.
[B].
C.
[C].
D.
[D].
Answer» D. [D].
Show Answer
Discussion
No Comment Found
Post Comment
Related MCQs
N circles for a = a1, and a = a1 ± 180° n (where n = 1, 2, 3, ....) are the same.
Nichol's chart is symmetric about - 180° axis.
At low frequencies the factor e-jωT and behave simple.
For type 0 system the starting point (i.e. ω = 0) of polar plot is finite and is on positive real axis.
For as ω approaches infinity, the magnitude approaches zero and phase angle approaches - 90°.
The phase angle curve of G(jω) H(jω) is drawn by adding the phase angles of individual factors.
At corner frequency the phase angle of factor is - 45°
The phase angle of is constant and equal to - 90° for all values of ω
The log magnitude curve of factor jω is a straight line having a slope of 20 dB/decade.
Transfer functions of even complicated components can be found by frequency response tests.
Reply to Comment
×
Name
*
Email
*
Comment
*
Submit Reply
Your experience on this site will be improved by allowing cookies. Read
Cookie Policy
Reject
Allow cookies
