MCQOPTIONS
Bookmark
Saved Bookmarks
→
Electronics & Communication Engineering
→
Signals And Systems
→
The phase angle curve of G(jω) H(jω) is drawn by a...
1.
The phase angle curve of G(jω) H(jω) is drawn by adding the phase angles of individual factors.
A.
True
B.
False
Answer» B. False
Show Answer
Discussion
No Comment Found
Post Comment
Related MCQs
N circles for a = a1, and a = a1 ± 180° n (where n = 1, 2, 3, ....) are the same.
Nichol's chart is symmetric about - 180° axis.
At low frequencies the factor e-jωT and behave simple.
For type 0 system the starting point (i.e. ω = 0) of polar plot is finite and is on positive real axis.
For as ω approaches infinity, the magnitude approaches zero and phase angle approaches - 90°.
The phase angle curve of G(jω) H(jω) is drawn by adding the phase angles of individual factors.
At corner frequency the phase angle of factor is - 45°
The phase angle of is constant and equal to - 90° for all values of ω
The log magnitude curve of factor jω is a straight line having a slope of 20 dB/decade.
Transfer functions of even complicated components can be found by frequency response tests.
Reply to Comment
×
Name
*
Email
*
Comment
*
Submit Reply
Your experience on this site will be improved by allowing cookies. Read
Cookie Policy
Reject
Allow cookies