MCQOPTIONS
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MCQOPTIONS
This section includes 2171 Mcqs, each offering curated multiple-choice questions to sharpen your ENGINEERING SERVICES EXAMINATION (ESE) knowledge and support exam preparation. Choose a topic below to get started.
| 1851. |
Which of the following circuits can operate class AB for audio power output? |
| A. | Emitter follower |
| B. | Push pull |
| C. | Cascade |
| D. | Darlington pair |
| Answer» E. | |
| 1852. |
In an op-amp comparator, the positive or negative output is |
| A. | saturated |
| B. | amplifier |
| C. | unsaturated |
| D. | any of the above |
| Answer» B. amplifier | |
| 1853. |
A D.C. amplifier amplify |
| A. | D.C. only |
| B. | A.C. only |
| C. | both A.C. and D.C. |
| D. | none of the above. |
| Answer» B. A.C. only | |
| 1854. |
Assertion (A): In Darlington pair, the overall β is product of individual βsReason (R): The voltage gain of a base driven amplifier is equal to ac collector voltage divided by ac base voltage |
| A. | Both A and R are correct and R is correct explanation for A |
| B. | Both A and R are correct but R is not correct explanation for A |
| C. | A is correct R is wrong |
| D. | A is wrong R is correct |
| Answer» C. A is correct R is wrong | |
| 1855. |
The equivalent circuit of an op-amp has |
| A. | a virtual ground at input |
| B. | a virtual ground at output |
| C. | virtual ground at input as well as at output |
| D. | none of the above |
| Answer» B. a virtual ground at output | |
| 1856. |
Assertion (A): The horizontal intercept of dc load line is the same as ideal cut off pointReason (R): When a transistor is in cut off region, collector current is zero |
| A. | Both A and R are correct and R is correct explanation for A |
| B. | Both A and R are correct but R is not correct explanation for A |
| C. | A is correct R is wrong |
| D. | A is wrong R is correct |
| Answer» B. Both A and R are correct but R is not correct explanation for A | |
| 1857. |
In figure the input and output Miller capacitances are |
| A. | 0.25 μF each |
| B. | 500 pF each |
| C. | 0.25 μF and 500 pF respectively |
| D. | 500 pF and 0.25 μF respectively |
| Answer» B. 500 pF each | |
| 1858. |
If it is desired to have low output impedance in an amplifier circuit then we should use |
| A. | common collector circuit |
| B. | common base circuit |
| C. | common emitter circuit |
| D. | either (b) or (c) |
| Answer» B. common base circuit | |
| 1859. |
A pulse transformer uses |
| A. | ferrite core |
| B. | air core |
| C. | iron core |
| D. | copper core |
| Answer» B. air core | |
| 1860. |
Which of the following oscillators is suitable for frequencies in the range of mega hertz? |
| A. | RC phase shift |
| B. | Wien bridge |
| C. | Hartley |
| D. | Both (a) and (c) |
| Answer» D. Both (a) and (c) | |
| 1861. |
In a N-P-N transistor, when emitter junction is forward biased and collector junction is reverse biased, the transistor will operate in |
| A. | active region |
| B. | saturation region |
| C. | cut of region |
| D. | inverted region |
| Answer» B. saturation region | |
| 1862. |
As compared to a BJT amplifier circuit, a JFET amplifier circuit |
| A. | has low input impedance |
| B. | has high input impedance |
| C. | has very low input impedance |
| D. | may have either low or high input impedance |
| Answer» C. has very low input impedance | |
| 1863. |
When a CE transistor is cut off |
| A. | voltage across collector reduces to zero |
| B. | voltage across collector is maximum |
| C. | maximum collector current flows |
| D. | maximum voltage appears across the load resistance |
| Answer» C. maximum collector current flows | |
| 1864. |
The advantage of using crystal oscillator is that it |
| A. | requires low d.c. supply voltage |
| B. | works at high frequency |
| C. | gives high output voltage |
| D. | gives constant frequency of oscillations |
| Answer» E. | |
| 1865. |
Assertion (A): Transformer coupling has the disadvantage of the weight of transformer and Saturation of coreReason (R): Transformer coupling is very suitable for impedance matching |
| A. | Both A and R are correct and R is correct explanation for A |
| B. | Both A and R are correct but R is not correct explanation for A |
| C. | A is correct R is wrong |
| D. | A is wrong R is correct |
| Answer» C. A is correct R is wrong | |
| 1866. |
Leakage current approximately doubles for every 10°C increase in the temperature of a transistor has ICBO = 400 nA at 25°C, then its leakage current at 80°C |
| A. | 10 μA |
| B. | 18 μA |
| C. | 20 μA |
| D. | 15 μA |
| Answer» C. 20 μA | |
| 1867. |
In the graphical analysis of CE amplifier circuit, the upper end of load line is called |
| A. | saturation point |
| B. | cut off point |
| C. | Q point |
| D. | none of the above |
| Answer» B. cut off point | |
| 1868. |
The coupling capacitor in amplifier circuits |
| A. | affects dc biasing |
| B. | does not affect dc biasing |
| C. | affects dc biasing to some extent |
| D. | both (a) and (c) |
| Answer» C. affects dc biasing to some extent | |
| 1869. |
In order to rectify sinusoidal signals of millivolt range (< 0.6 V) |
| A. | bridge rectifier using diodes can be employed |
| B. | full wave diode rectifier can be used |
| C. | a diode is to be inserted in the feedback loop of an op-amp |
| D. | a diode is to be inserted in the I/P of an op-amp |
| Answer» D. a diode is to be inserted in the I/P of an op-amp | |
| 1870. |
In the circuit of figure, v0 = |
| A. | 3 v1 + 4 v2 |
| B. | -3 v1 - 4 v2 |
| C. | 4 v1 + 3 v2 |
| D. | -4 v1 - 3 v2 |
| Answer» C. 4 v1 + 3 v2 | |
| 1871. |
The circuit in figure is |
| A. | rectifier |
| B. | voltage to frequency converter |
| C. | frequency to voltage converter |
| D. | logarithmic amplifier |
| Answer» E. | |
| 1872. |
In a single stage differential amplifier, the output offset voltage is basically dependent on the mismatch of |
| A. | VBE, IB and β |
| B. | VBE and IB |
| C. | IB and β |
| D. | VBE and β |
| Answer» D. VBE and β | |
| 1873. |
In a CE amplifier, the output voltage is equal to product of |
| A. | ac collector current and ac collector resistance |
| B. | ac base current and ac collector resistance |
| C. | ac emitter current and ac emitter resistance |
| D. | ac collector current and source resistance |
| Answer» B. ac base current and ac collector resistance | |
| 1874. |
When negative feedback is used the fractional changes in closed loop gain are desensitized by the factor (1 + Avβ) |
| A. | True |
| B. | False |
| C. | May be True or False |
| D. | can't say |
| Answer» B. False | |
| 1875. |
A transistor has a power rating of 8 W for a case temperature of 25°C. If derating factor is 30 mW/°C, the power rating for 55°C, case temperature is |
| A. | 8 W |
| B. | 7.5 W |
| C. | 7.1 W |
| D. | 6.8 W |
| Answer» D. 6.8 W | |
| 1876. |
The circuit shown in figure will |
| A. | oscillate at 456 kHz |
| B. | oscillate at 228 kHz |
| C. | oscillate at microwave frequency |
| D. | not oscillate |
| Answer» E. | |
| 1877. |
The more negative gate voltage, the conductive channel becomes |
| A. | narrower |
| B. | wider |
| C. | thicker |
| D. | linear |
| Answer» B. wider | |
| 1878. |
When a transistor is connected in common emitter mode, it with have |
| A. | negligible input resistance and high output resistance |
| B. | high input resistance and low output resistance |
| C. | medium input resistance and high output resistance |
| D. | low input resistance as well as output resistance |
| Answer» D. low input resistance as well as output resistance | |
| 1879. |
Which op-amp circuit uses a diode as one of the circuit components? |
| A. | Integrating amplifier |
| B. | Differentiating amplifier |
| C. | Logarithmic amplifier |
| D. | Summing amplifier |
| Answer» D. Summing amplifier | |
| 1880. |
A full wave bridge diode rectifier uses diodes having forward resistance of 50 ohms each. The load resistance is also 50 ohms. The voltage regulations is |
| A. | 20% |
| B. | 50% |
| C. | 100% |
| D. | 200% |
| Answer» E. | |
| 1881. |
The V MOS can handle __________ currents than a conventional MOSFET. |
| A. | much lower |
| B. | almost same |
| C. | almost half |
| D. | much larger |
| Answer» E. | |
| 1882. |
In the circuit of figure β = 50 and VBE = 0.5 V. The quiescent value of base current IB is |
| A. | about 28 μA |
| B. | about 28 mA |
| C. | about 0.28 μA |
| D. | about 2.8 A |
| Answer» B. about 28 mA | |
| 1883. |
Which of the following figures is an ideal equivalent circuit of a n-p-n transistor? |
| A. | figure A |
| B. | figure B |
| C. | figure C |
| D. | none |
| Answer» C. figure C | |
| 1884. |
A bridge rectifier circuit has input of 50 Hz frequency. The load resistance is RL and filter capacitance is C. For good output wave shape, the time constant RLC should be at least equal to |
| A. | 10 ms |
| B. | 20 ms |
| C. | 50 ms |
| D. | 100 ms |
| Answer» E. | |
| 1885. |
IF amplifiers for radio receivers are often tuned to |
| A. | 456 Hz |
| B. | 456 kHz |
| C. | 3456 MHz |
| D. | 456 GHz |
| Answer» C. 3456 MHz | |
| 1886. |
The emitter resistor RE in the emitter of CE amplifier stabilizes the dc operating point against variation in |
| A. | temperature only |
| B. | β of transistor |
| C. | both temperature and β |
| D. | none of the above |
| Answer» D. none of the above | |
| 1887. |
A buffer amplifier should have |
| A. | high output impedance and high input impedance |
| B. | high output impedance and low input impedance |
| C. | low output impedance an low input impedance |
| D. | low output impedance and high input impedance |
| Answer» E. | |
| 1888. |
Negative feedback is used in audio amplifiers to |
| A. | operate class C |
| B. | reduce distortion |
| C. | increase distortion |
| D. | increase gain |
| Answer» C. increase distortion | |
| 1889. |
In the case of the circuit shown in the figure Vio = 10 mV dc maximum, the maximum possible output offset voltage Voo caused by the input offset voltage Vio with respect to ground is |
| A. | 60 mV dc |
| B. | 110 mV dc |
| C. | 130 mV dc |
| D. | 150 mV dc |
| Answer» D. 150 mV dc | |
| 1890. |
A bypass capacitor produces |
| A. | dc ground |
| B. | ac ground |
| C. | both dc and ac ground |
| D. | none of the above |
| Answer» C. both dc and ac ground | |
| 1891. |
The circuit of figure is |
| A. | positive clipper |
| B. | negative clipper |
| C. | combination clipper |
| D. | either (a) or (b) |
| Answer» D. either (a) or (b) | |
| 1892. |
A Hartley oscillator uses |
| A. | a tapped inductor |
| B. | a tapped capacitor |
| C. | both (a) and (b) |
| D. | neither (a) nor (b) |
| Answer» B. a tapped capacitor | |
| 1893. |
In CE amplifier the base current is very high. |
| A. | True |
| B. | False |
| C. | May be True or False |
| D. | can't say |
| Answer» C. May be True or False | |
| 1894. |
Which of the following compensation method in amplifier can be used to reduce the bandwidth? |
| A. | Pole-zero compensation |
| B. | Dominant pole compensation |
| C. | Lead compensation |
| D. | Any of the above |
| Answer» C. Lead compensation | |
| 1895. |
The quiescent collector current IC, and collector to emitter voltage VCE in a CE connection are the values when |
| A. | ac signal is zero |
| B. | ac signal is low |
| C. | ac signal is negative |
| D. | either (a) or (b) |
| Answer» B. ac signal is low | |
| 1896. |
An amplifier has open loop gain of 100, input impedance 1 kΩ and output impedance 100 Ω. If negative feedback with β = 0.99 is used, the new input and output impedances are |
| A. | 10 Ω and 1 Ω |
| B. | 10 Ω and 10 kΩ |
| C. | 100 kΩ and 1 Ω |
| D. | 100 kΩ and 10 Ω |
| Answer» D. 100 kΩ and 10 Ω | |
| 1897. |
A half wave diode rectifier and full wave diode bridge rectifier both have an input frequency of 50 Hz. The frequencies of outputs respectively are |
| A. | 100 Hz and 50 Hz |
| B. | 50 Hz and 100 Hz |
| C. | 100 Hz each |
| D. | 50 Hz each |
| Answer» C. 100 Hz each | |
| 1898. |
A transistor is said to be in a quiescent state when |
| A. | the amplitude of input and output signal is equal |
| B. | the phase of input and output signal is identical |
| C. | no signal is applied to the input |
| D. | the transistor is unbiased |
| Answer» D. the transistor is unbiased | |
| 1899. |
The dc output voltage of the circuit is |
| A. | 4.3 V |
| B. | 1.369 V |
| C. | 3.87 V |
| D. | 1.94 V |
| Answer» C. 3.87 V | |
| 1900. |
Examine the circuit of figure and the following statements:1. Vs is more than the zener breakdown voltage.2. IL = I1 - I2.3. Rs is less than zener nominal resistance. Which of the above statements are correct? |
| A. | 1, 2, 3 |
| B. | 1, 2 |
| C. | 1 only |
| D. | 2 and 3 |
| Answer» C. 1 only | |