MCQOPTIONS
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MCQOPTIONS
This section includes 17 Mcqs, each offering curated multiple-choice questions to sharpen your Waste Water Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What is the EE/O for TCA in kWh/1000 US gal/order? |
| A. | t15 |
| B. | t20 |
| C. | t10 |
| D. | t30 |
| Answer» B. t20 | |
| 2. |
What is the EE/O for Xylene in kWh/1000 US gal/order? |
| A. | t2-5 |
| B. | t5-7 |
| C. | t7-9 |
| D. | t9-12 |
| Answer» B. t5-7 | |
| 3. |
What is the EE/O for Vinyl chloride in kWh/1000 US gal/order? |
| A. | t1-2 |
| B. | t2-3 |
| C. | t3-5 |
| D. | t5-7 |
| Answer» C. t3-5 | |
| 4. |
How is the UV power calculated? |
| A. | tUV power = [UV dosage x 60 x flow(US gallons)]/1000 |
| B. | tUV power = [UV dosage x 600 x flow(US gallons)]/1000 |
| C. | tUV power = [UV dosage x flow(US gallons)]/1000 |
| D. | tUV power = [UV dosage x 16 x flow(US gallons)]/1000 |
| Answer» B. tUV power = [UV dosage x 600 x flow(US gallons)]/1000 | |
| 5. |
How is the operating cost calculated for an advanced oxidation process system in $ per 1000US gallon? |
| A. | tTotal operating cost = 1.45 x electrical cost + Peroxide cost |
| B. | tTotal operating cost = 0.45 x electrical cost + Peroxide cost |
| C. | tTotal operating cost = electrical cost + Peroxide cost |
| D. | tTotal operating cost = 1.5 x electrical cost + Peroxide cost |
| Answer» B. tTotal operating cost = 0.45 x electrical cost + Peroxide cost | |
| 6. |
How is UV dosage expressed mathematically? |
| A. | tUV dosage = EE/O log(C<sub>i</sub>)/(C<sub>f</sub>) |
| B. | tUV dosage = EE/O /log(C<sub>i</sub>)/(C<sub>f</sub>) |
| C. | tUV dosage = log(C<sub>i</sub>)/(C<sub>f</sub>) |
| D. | tUV dosage = EE/O (C<sub>i</sub>)/(C<sub>f</sub>) |
| Answer» B. tUV dosage = EE/O /log(C<sub>i</sub>)/(C<sub>f</sub>) | |
| 7. |
What is the EE/O for chloroform in kWh/1000 US gal/order? |
| A. | t5-10 |
| B. | t15 |
| C. | t20-25 |
| D. | t25-30 |
| Answer» C. t20-25 | |
| 8. |
What is the EE/O for DCA in kWh/1000 US gal/order? |
| A. | t5 |
| B. | t15 |
| C. | t20 |
| D. | t25 |
| Answer» C. t20 | |
| 9. |
What is the EE/O for benzene in kWh/1000 US gal/order? |
| A. | t2-5 |
| B. | t5-7 |
| C. | t7-9 |
| D. | t9-11 |
| Answer» B. t5-7 | |
| 10. |
What is the EE/O for atrazine in kWh/1000 US gal/order? |
| A. | t2-6 |
| B. | t30 |
| C. | t20 |
| D. | t15-20 |
| Answer» C. t20 | |
| 11. |
What is the EE/O for 1,4 dioxane in kWh/1000 US gal/order? |
| A. | t2-6 |
| B. | t30 |
| C. | t15 |
| D. | t15-20 |
| Answer» B. t30 | |
| 12. |
What is the oxidative potential of hydroxyl radical? |
| A. | t2.08 |
| B. | t2.18 |
| C. | t2.28 |
| D. | t1.78 |
| Answer» D. t1.78 | |
| 13. |
The cost of AOP is high because of _________ |
| A. | tHigh pumping cost |
| B. | tContinuous input of energy |
| C. | tExpensive chemical reagents |
| D. | tUV radiations |
| Answer» C. tExpensive chemical reagents | |
| 14. |
Advanced oxidation processes are cheap. |
| A. | tTrue |
| B. | tFalse |
| Answer» C. | |
| 15. |
What is the process used in AOP? |
| A. | tOxidation |
| B. | tReduction |
| C. | tSubstitution |
| D. | tChlorination |
| Answer» B. tReduction | |
| 16. |
Organic materials in wastewater are removed by oxidation through reactions with _______ |
| A. | thydrogen |
| B. | thydroxyl radicals |
| C. | twater |
| D. | toxygen |
| Answer» C. twater | |
| 17. |
Advanced oxidation processes are used to remove inorganic materials in water and wastewater. |
| A. | tTrue |
| B. | tFalse |
| Answer» B. tFalse | |