Which of these values used to find $(\frac{\partial \rho}{\partial t})_{i,j}^{av}$ is a predicted one?

Question

TuteeHUB · Accepted Answer

Both $(\frac{\partial\rho}{\partial t})_{i,j}^t and (\frac{\partial\rho}{\partial t})_{i,j}^{t+\Delta t}$

TuteeHUB · Answer

$(\frac{\partial\rho}{\partial t})_{i,j}^t$

TuteeHUB · Answer

Neither $(\frac{\partial\rho}{\partial t})_{i,j}^t nor (\frac{\partial\rho}{\partial t})_{i,j}^{t+\Delta t}$

TuteeHUB · Answer

$(\frac{\partial\rho}{\partial t})_{i,j}^{t+\Delta t}$

TuteeHUB · Answer

Both $(\frac{\partial\rho}{\partial t})_{i,j}^t and (\frac{\partial\rho}{\partial t})_{i,j}^{t+\Delta t}$

1.	Which of these values used to find \((\frac{\partial \rho}{\partial t})_{i,j}^{av}\) is a predicted one?
A.	\((\frac{\partial\rho}{\partial t})_{i,j}^t\)
B.	Neither \((\frac{\partial\rho}{\partial t})_{i,j}^t nor (\frac{\partial\rho}{\partial t})_{i,j}^{t+\Delta t}\)
C.	\((\frac{\partial\rho}{\partial t})_{i,j}^{t+\Delta t}\)
D.	Both \((\frac{\partial\rho}{\partial t})_{i,j}^t and (\frac{\partial\rho}{\partial t})_{i,j}^{t+\Delta t}\)
Answer» D. Both \((\frac{\partial\rho}{\partial t})_{i,j}^t and (\frac{\partial\rho}{\partial t})_{i,j}^{t+\Delta t}\)

Which of these values used to find \((\frac{\partial \rho}{\partial t})_{i,j}^{av}\) is a predicted one?